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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
How many 3-digit numbers are there in all? |
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Answer» there are 90000 five digit numbers there are 90000 five digit numbers |
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| 2. |
146 \times 384 |
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Answer» 56,064 is the answer |
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| 3. |
2. Attempt the following:2 marks each(1) The radius of a circle with centre P is 25 cm. Thelength of a chord of the same circle is 48 cm. Findthe distance of the chord from the centre P of thecircle.Ans:74VIKAS SMART iOn |
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| 4. |
5. Factorise x + 3 -762-1) +5.(Hint: Put x = 1 = y](Hint: Put x - |
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| 5. |
cot θ1+sec θ cosec-+--1-cot θ 1-tan θHint : Write the expression in terms of1 + sec A sin A, sec A 1- coS A [Hint : Simos A -sin A +1cos A +sin A1= cosec A + cot1 + sin A1- sin Ain A + cosec A)?+ (cos A+sec A)?-osec A-sin A)(see A-cos A)--=sec A+ tan A |
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| 6. |
rxand y:ax-bya + b ;ax-by-2ab.a. |
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Answer» Ax/b-by/a=a+b -------------(1)ax-by=2ab ------------------(2)Using cross multiplication method we get,x/(2b²-ab-b²)=y/(-a²-ab+2a²)=1/(a-b)or, x/(b²-ab)=y/(a²-ab)=1/(a-b)or, x/(-b)(a-b)=y/a(a-b)=1/(a-b)Equating the first and the last part,x/(-b)(a-b)=1/(a-b)or, x=(-b)(a-b)/(a-b)or, x=-bAgain equating the last two parts,y/a(a-b)=1/(a-b)or, y=a(a-b)/(a-b)or, y=a∴, the required solution : x=-b, y=a |
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| 7. |
\sec x + \tan x = \sqrt { \frac { 1 + \sin x } { 1 - \sin x } } |
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Answer» thanks |
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| 8. |
How many 3-digit numabers can brepeated?e digits 1 to 9 if no digit is |
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| 9. |
14. How many 3-digit numbers are there? |
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Answer» 100 to 9991000-99-1 =900 💯 to 9991000-99-1=900 |
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| 10. |
The perimeter of a rectangular short is 100cm. If the length is 35cm find its breadth Also find the area |
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Answer» perimeter of a rectangle= 2(length+ breadth)suppose breadth is x cm100= 2(35+x)100-70=2xx=15area of a rectangle is length*breadth35*15cm^2525cm^2 will be area of rectangular sheet |
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| 11. |
sqrt((-sin(x) %2B 1)/(sin(x) %2B 1))=-tan(x) %2B sec(x) |
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| 12. |
\int \frac{d x}{1+\sin x}=\tan x-\sec x+c |
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Answer» thanks |
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| 13. |
c) How many 3-digit numbers are there? |
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Answer» There are 900 types of 3 - digit numbers. |
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| 14. |
the area of bottom of box is 384 cm2 if it's height is 37cm .find the volume. |
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Answer» Area of box = L×B = 384 cm² Volume of box = L×B×H Volume of box = 384 cm² × 37 cm Volume of box = 14,208 cm² thx for answer me |
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| 15. |
12.In the given figure, find the value of x.130°(A) 40°(B) 50°(C) 70(D) 100Mathe |
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Answer» option A |
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| 16. |
निर्देश : निम्नलिखित प्रत्येक फलन का x के सापेक्ष समाकलन कीजिए :100 (2005, 12)x log *a2+2our-e-ax1-23(2008)earte-ax(2001, 05, 12)e2x-1Nx+x-olapolee2x +1संतन.6ect |
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Answer» option 5 is the correct answee |
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| 17. |
(2) In the figure, point D is in the interior of AABC,prove ZBDC> LA.(Hint: extend seg BD to intersect AC at E.)VIKAS SMART WORKBOOK MATHE |
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Answer» Where is the figure? |
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| 18. |
a + bax-1 bx-1=a+b;(x*1.1) |
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| 19. |
22 (i)-a -bax-1Hint. (0)abh0.ax -1br -1 |
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Answer» 4th step plzz explain |
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| 20. |
Q.1. Ifare linear pair angles, find themeasure of angles (2.c + 4) and (ax- 1)m. |
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| 21. |
2.If101 is divided by ax + 1, what is the remainder? |
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Answer» PLEASE LIKE IT, IF YOU FIND THIS SOLUTION HELPFUL. |
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| 22. |
if sec θx+,4xthen prove that sec θ + tan 8-2 r or |
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Answer» Let theta = A SecA=x+1/4x∴, sec²A=(x+1/4x)²=x²+2.x.1/4x+1/16x²=x²+1/2+1/16x² Now, sec²A-tan²A=1or, tan²A=sec²A-1or, tan²A=x²+1/2+1/16x²-1or, tan²A=x²+1/16x²-1/2or, tan²A=x²-2.x.1/4x+1/16x²or, tan²A=(x-1/4x)²or, tanA=+-(x-1/4x) Therefore, either secA+tanA=x+1/4x+x-1/4x [when tanA=x+1/4x]=2x or, secA+tanA=x+1/4x-x+1/4x [when tanA=-(x+1/4x)]=1/4x+1/4x=2/4x=1/2x (Proved) |
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| 23. |
x*(a*(r*(r*(o*(w*((pi/4)*((sec(x)^2 - 2)/(tan(x) - 1)))))))) |
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| 24. |
solve by factorisation:x2 +a/a+b a+b/ax + 1 0 |
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| 25. |
(i) sin r1 +sin xsec xtan x |
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| 26. |
-How many 3 digit no. are divisible by 8Alle bu |
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Answer» The first threedigit number divisible by 8is 104 and the lastnumber of three digits divisible by 8is 992. So there are 112 three-digit numberswhich aredivisible by 8. 2 5 6 / 8 = 3 2 |
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| 27. |
. The sides of a triangle are 12cm, 35cm and 37cmFind its area. |
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| 28. |
6.How many times will a wheel of radius 35cm be rotated to(Take |
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Answer» In one rotation wheel cov er = 2 × pi × r = 2 × 22/7 × 35 cm = 2 × 22 × 5 = 220 cm So, to cover 660cm wheel needs= 660/220 = 3 rotation |
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| 29. |
How many times will a wheel of radius 35cm be rotated to travel 660 cm?(Take π=-). |
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Answer» One time rotation = 2πr= 70π= 220cmnow n*220= 600number of rotation= 2.7 |
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| 30. |
4. The sides of a triangle are 12cm, 35cm and37cm.Find its area. |
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Answer» let side a=12cm sideb=35cm and side c=37cm∴ semiperimeter,= (a+b+c)/2=12+35+37/2=84/2=42 cm∴area of the triangle by heron'sformula,Δ=√s(s-a)(s-b)(s-c)Δ=√42(42-12)(42-35)(42-37 )Δ=√42*30*7*5Δ=√2*3*7*7*5*2*3*5Δ=2*3*5*7Δ=210 cm^2∴ total area of the triangle is= 210 cm^2 please like the solution 👍 ✔️👍 |
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| 31. |
21m÷7m |
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Answer» 12÷7 = 3 m. So, the answer is 3m. |
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| 32. |
21m2÷7m |
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Answer» 21m² ÷ 7m Cancel using 7 we get 3m² ÷ m Cancel using m 3m |
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| 33. |
A 35cm line segment is divided into two parts in the ratio 4:3. Find the length of each part |
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Answer» 20 cm 15 cm is the correct answer of the given question |
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| 34. |
IP 4) is the mid-point of the line segment joining the points Q-6.5) and R(-2,3) therfind the value of b. |
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Answer» no find the value of b IfP is mid point of Q and R thenb/3=(-6+(-2))/2b/3=(-6-2)/2b/3=-8/2b/3=-4b=-4*3b=-12 explain the steps with formula |
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| 35. |
6. The total surface area of a cube is 96 m2. Find its volume.7. Theouter dimensions of a closed box are 42 cm, 30 cm and 20 cm. If the box is made up of wood ofthe thickness 1cm, determine the volume of wood used |
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| 36. |
A bag contains 50 cards. Each card bears only one number from 1 to 50. One card is drawn at random from the bag. Write sample space. Also, write event A and the number of sample pointsEvent A : The number on the card is divisible by 6. |
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Answer» Sample space is 50 (from 1 to 50)Event A is drawing a card with number divisible by 6A: 6,12,18,24,30,36,42,48 Number of sample points=8 |
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| 37. |
A pendulum swings through an angles of 30° anddescribes an arc 8-8 cm in length. Find the lengthof the pendulum. |
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| 38. |
\left. \begin{array} { l } { 36 : 90 } \\ { 480 = 384 } \end{array} \right. |
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| 39. |
, दर 4 Sm.—l —3 e taH-l ........'777 5 36 |
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Answer» PLEASE HIT THE LIKE BUTTON |
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| 40. |
° Constructbase rs 8cm and altitude 4cm andthen another trianglo whose sidesan Psosceles tronqle whosaretimes the corresponding2.sides of the rsasceles trfangle. |
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| 41. |
35.44In the given circle,the given circle, O is a centre and CBDC = 42", the ZACB isequal to1.42°2.45°3.4809600 |
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Answer» Angle CDB=angle BAC=42°(angles subtended by same chord) CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°) In triangle CBA ,angle ACB=48°[angle sum property] |
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| 42. |
The circumference of a circle is the same as the perimeter ofrhombus is 44 cm, find the radius of the circle. |
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| 43. |
find the area of quadrant of a circle whose circumference is 44 cm |
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Answer» To find the quadrant of a circle we will have to first determine the circumference of the circle which is 2πr. Here, the circumference being 44cm, 2πr=44. Therefore, radius of circle = r=44/2π =44*7/2*22= 7cm. (π=22/7) Now, Area of circle = πr^2 = 22*(7^2)/7 = 154.06 cm². The area of the quadrant of a circle whose circumference in 44 cm is = 154.06 cm². |
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| 44. |
7m+19÷2=13 |
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Answer» 7m+19÷2=137m=13-19/27m=7/214m=7m=7/14 answer m= 1/2 is the answer of the following 7m+19/2=1314m+19=2614m=26-1914m=7m=7/14m=1/2 or m=0.5 ans. according to the questionm=1 Correct answer is m = 1/2 correct answer is m = 1/2 7m+☺️9/2=[m=1/2]it is the correct answer m = 1/2 is the best answer 7m+19÷2=137m=13_19/27m=7/214m=7m=7/14ans |
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| 45. |
14m of 7m 35cm |
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Answer» 7m35cm=735 cm 14m=1400 cm :.ratio = 1400:735 simplest form:: 200:105 =40:21(ans ) 40:21 is the right answer 7m35cm=735cm14m=1400cm1400:735200:10540:21 is the right answer 7m35cm=735 cm14m=1400cm:. Ratio=1400:735Simplest form=200:105=40:21 is coorect answer |
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| 46. |
What is the radius of a circle whose circumference is 44 cm ?BY 7 |
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Answer» Circumference of a circle = 2πrandGiven, 2πr = 44cm So,πr = 44/2 = 22 r = 22 × 7/22 r = 7cm is the answer. |
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| 47. |
(7m-3n-4k)² |
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Answer» (7m-3n-4k)(7m-3n-4k) using below formula (a+b+c)(a+b+c) = a*a+b*b+c*c+2ab+2bc+2ca = 49m*m+9n*n+16k*k-42mn+24nk-56mk If you find this answer helpful then like it. |
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| 48. |
If cos © +sin B = J2 cos 8, prove that :cos O —sin 0 = J2 sin® |
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Answer» cosθ+ sinθ= √2 cosθ--> sinθ= √2 cosθ- cosθ=>sinθ =( √2 - 1 ) cosθ => [ sinθ/ ( √2 - 1 ) ] = cosθ=> [ sinθ( √2 + 1 ) / ( 2 - 1 ) ] = cosθ 0_0 --> We rationalized the denominator in the 2nd step =>[ √2 sinθ+ sinθ] = cosθ=> cosθ- sinθ= √2 sinθ |
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| 49. |
8, पमत शोधों : J2+/3या. गाल |
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| 50. |
21. The angles of a triangle are in A.P. whose common difference is 20°. Find the angles. |
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Answer» We know that sum of angles of triangle is 180°so x+x+20+x+40= 1803x+60= 1803x= 120x= 40other angles will be40+20= 60° and 60+20° 80° |
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