Explore topic-wise InterviewSolutions in Current Affairs.

Volume of a cube= a^3= 7*7*7= 343cm^3thanksplease like the solution 👍 ✔️

727 is the right answer

726 is the right answer

The surface area of a cube is = 6 × side6×11² =726cm²

121 is the correct answer because area=side×side

725 is the right answer

value of √3 is 1.732

value of root 3 is 1.732

From which book have you taken this question? Please tell us so that we can provide you faster answer.

oswaal book

let the cost price be xsox - 10% of x = 72x - 10/100 × x = 72x - x/10 = 729x/10 = 72x = (72×10)/9 = 80so cost price be ₹ 80

Cost price= 100*SP/100-loss%=100*72/100-10=7200/90=80

1st place can be filled by 9 digits- 1–9 excluding zero as 0 on first place would not form a 3 digit no.

2nd place can be filled by 9 digits- 0–9 not including the 1st no.

3rd place can be filled by 8 digits- 0–9 not including he 1st 2 nos.

Therefore answer is 9*9*8= 648.

answer is right but your method is wrong

Let 'x' , 'y' , 'z' & 'a' be 1st , 2nd , 3 rd & 4th angle

So, x + y + z = 5a

Sum of all angles of a quadrilateral = 360 deg

x + y + z + a = 360 deg

5a + a = 360 deg

6a = 360 deg

a =360 / 6

a = 60 degrees

Therefore , 4th angle is 60 degree .

Let the measures of the three angles be a, b ,c and that of 4th be d.then a+b+c+d = 3605d + d = 3606d = 360d = 60°

45 + 75 + 105 + x = 360 (Sumof angles of a quadrilateral is 360) 225 + x = 360 x = 360 - 225 = 135

answer is rs 70 . each labour will get ₹ 70

the daily wage of each labour is 70

the daily wages of 25labour is Rs. 1750therefore the daily wages of 25 labour =1750/25 =Rs.70

yes all angle and sides of a quadrilateral are equal and angle are equal to 90 degree

Sum of angle all sides of quadrilateral is 360Let fourth angle be xThen 75 + 90 + 75 + x = 360X + 240 = 360X = 360 - 240X = 120Fourth angle is 120

Given : ABC right angle triangle at A where BL and CM are the medians

To prove : 4(BL^2 + CM^2)=5BC^2

Proof :Since BL is the median

AL=CL=1/2 AC .............(1)

Similarly CM is the median

AM = MB = 1/2 AB ........... (2)

In triangle ABC

BC^2 = AB^2 + AC^2

In triangle BAL

BL^2 =AB^2 +AL^2

BL^2 =AB^2 +(AC/2)^2

On further little solving steps

4BL^2 =4AB^2 +AC^2

Then in triangle MAC

CM^2 =AM^2 +AC^2

Doing same process here We get

4CM^2 =AB^2 +4AC^2

|A|= 3 and |B| = 2

Total number of functions from A to B = |B|^|A| = 2^3 =8.

Therefore, the total functions from A to B = 8.

Like if you find it useful

71x+37y=253 ...(i)37x+71y=287 ...(ii)add (i) and (ii) to get108(x+y)=540= x+y=5 ....(iii)substract (ii) from (i) to get34(x-y)=-34=x-y=-1 ...(iv)add (iii) and (iv)x+y+x-y=5+(-1)=2x=4=x=2putting the value of x in(iii) we get2+y=5y=3hence x=2 and y=3

Like my answer if you find it useful!

Let the length of rectangle be aAnd width of rectangle be bArea = ab

Now,

New length = a + 50% of a= a+ 50a/100= a+a/2= 3a/2

New width = b - 50% of b= b - b/2= b/2

New Area = 3a/2 * b/2= 3ab/4

Decrease in Area = ab - 3ab/4= ab/4

% of Decrease in Area = [(ab/4) * 100] / ab= 100 / 4= 25 %

Average = { (250*2)+(200*2.5)}/ 450= 2.22

If the maximum marks of examination be x then,

x*45/100 = 280 + 80 = 360

=>x = 360*100/45 = 800

30% of 800

= 800*30/100 = 240

= Minumum marks to pass for girls

Required difference

= 240 - 108 = 132

(A) is correct option

galt hai return karo