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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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3. Average height of 15 students of class 6 is 140 cm and average height of 10 students of class 7 is 145 cm.What is the average height of the students of both the classes? |
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Answer» your answer is 142 cm please mark as best class 615*140=2100class 710*145=1450then, a/q .2100+1450=3550 Total no of student =15+10=25Total height of the 6 class student =140×15=2100cmTotal height of 7 class student =145×10=1450cmThen total height of class 6&7 students =2100+1450=3550cmAverage height =Total height/Total student Average height =3550cm/25=142cm. (ans) the correct answer is 11.4cm class 615*140=2100class710*145=1450then,2100+1450=35503550/10+153550/25=142 |
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| 2. |
48. The average height of 20 boys is 120 cm and theaverage height of 10 girls is 117 cm. Find the aver-age height of these 30 students. |
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Answer» the average height will be 7.9 120+117/30=237/2=118.5 cm The total average height of these 30 students = The average of boys + the average of girls-------------------------------------------- total no. of student = 120+117 ----------------- 30 = 237 -------- 30 = 7.9 the average height will be 7.9 20*120=240010*117=11702400+1170=3570So 3570/30=119cm |
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| 3. |
6. If x: y 5 : 4 and 2 : X-3 : 8, find the value of y7. Find the value of x, when 2-5:4 x:7-5.8. Show that 2, 12 and 72 are in continued proportion |
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Answer» thnks |
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| 4. |
8. The cost of a chair is1475. Find the cost of 675 such chairs. |
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(756+287)" + (756-287)" 3(756x756+287x287) |
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| u) 8.5 years of these / इनमें से कोई नहींaverage height of 16 students is 142 cm. If the*ht of the teacher is included, the average heightses by 1 cm. The height of the teacher isविद्यार्थियों की औसत लंबाई 142 सेमी. है। यदि शिक्षक कीगई उसमें शामिल कर दी जाए तो औसत लंबाई 1 सेमी. बढ़ती है। शिक्षक की लंबाई है -(COR. BANK SPECIALIST OFFICER 2014 |
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| 7. |
EAERCISE 1.2. Express each number as a product of its prime factors:(i) 140(ii) 756(iii) 3825(iv) 5005(v) 7429 |
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Answer» ) ) 140 = 2 x 2 x 5 x 7 (ii)156 =2 x 2 x 3 x 13 (iii)3825 =3 x 3 x 5 x 5 x 17 (iv)5005 =5 x 7 x 11 x 13 (v)7429 =17 x 19 x 23 l know this answer thanks |
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| 8. |
The average weight of 12 girls in a class in 4 feet and the averheight of 8 boys in 5 feet. Find the combined average heightboth girls and boys. |
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Answer» combined average will be 4feet+5feet/2=9/2=4.5feet |
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Q. 7. (a) Find x + y + z.90°300 |
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Answer» As we knowthatz+30= 180z= 15090+x= 180x= 90nowy= 180-120= 60now60+90+150= 300 |
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9. In a school, out of 300 students, 70% are gris and 30% are boys. If 30 grisand no new boy is admitted, what is the new percentage of girls in the school ?Sole |
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Answer» please write clearly I can't understand |
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| 11. |
31) र्प्द 7 जल 20७ ७) “५5. रे £ind ? P> ! |
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Answer» I don't know whether we need to simply it or not |
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| 12. |
FindAOB in the given figure.o(300 |
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P (x)31-2x2 + 6- -5 है तो()मात करो |
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Answer» I think 23 is write answer |
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| 14. |
p ^2 + 31 pq + 108 q ^2 |
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a Find the equation of the perpendicular drawn from (2, 4, -1) to the lineand obtain the co-ordinates of the foot of the perpendicular |
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| 16. |
he perpendicular drawn from (2, 4,-1) to the lineFind the equation of tand obtain the co-ordinates of the foot of the perpendicular.-9 |
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Example 2.49The foot of perpendicular drawn from the origin to the plane is (4,-2,-5), findthe equation of the plane. |
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Answer» thank you |
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Two rays are drawn through a point A atan angle of 30. A point is B is taken onone of them at distance 'a' from the pointA. A perpendicular is drawn from thepoint B to the other ray. anotherperpendicular is drawn from its foot AB,and so on then the length of the resultinginfinite polygonal line is1) 23a2) a2+/3)4) 4/Ba3) a2-3 |
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Answer» thank you sir |
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| 19. |
n the given figure AS BT, 24-5ZAST, Find the measure of 41 |
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Answer» Given: AS is parallel to BT, and SB bisects angle AST that is () To find: The measure of angle 1 Solution: 1+2+3=180&2=3. because SB. is the bisector 1=4. because corresponding anglesangle 4=180-(2+3). ................ [1]angle 4=180-(3+5)....................[2]From 1&2,2=5 .....................[3]Hence,1+2+3=180&3+5+4=1803*angle 3=180angle 3=60It means angle 1=60 |
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| 20. |
Find the factors of p2-196. |
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Answer» p^2-196=p^2-14^2=(p-14)(p+14) |
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| 21. |
29. If p-Y3+y2 an3-V2V3-V2find p2+q2d q |
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| 22. |
675+97+90+3464+756 =? |
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Answer» 5082 is the correct answer 5082 is correct answer of the questions 5082 is the correct answer 5082 is the right answer 5082 is the correct answer |
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| 23. |
3099+675 |
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Answer» the adittion of 3099+675=3774 |
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| 24. |
nple-4nple-4An observer 1.4 m tall s 25.6 m awayAn observer 1.4 m tallis 25.6 m away fom a tower. The angle of elevationangle of elevationtop ofthe tower from her eyes is 45°. What is the height of the tower? |
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| 25. |
p ^ { 4 } + 9 p ^ { 2 } q ^ { 2 } + 81 q ^ { 4 } i s |
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A pole 50 m high stands on a building 250 mhigh. To an observer at a height of 300m, thebuilding and the pole subtend equal angles.The horizontal distance of the observer fromthe pole is |
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| 27. |
Ď /2Q.14) Evaluate Cos 'x dx. |
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| 28. |
(11) S.P. = 675, M.P.=31,67525 |
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Answer» S. P - M.P 675-1675 =1000 1000 is the right answer 1000is the correct answer Toal discount is 1000 rs. Discount=MP-SP=1675-675=1000 1000 is the right answer 1000 is the correct answer |
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| 29. |
6. In a school,of the students are boys. If there are 300 girly find the number of boys in the school |
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Answer» In school let total number of are x Then, Number of boys = 5x/7Number of girls = x - 5x/7 = (7x - 5x)/7 = 2x/7 So,2x/7 = 3002x = 2100x = 2100/2 = 1050 Therefore, Number of boys in school = 5*1050/7= 5*150 = 750 |
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In a class of 49 students, number of girls isthe class.GNthe boys. Find the number of boy |
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Answer» 35 boys are there in the class please write full solution |
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| 31. |
14, In a class of 49 students, number of girls isthe class.of the boys. Find the number of boys in4:25 |
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Answer» 49 and 2by5 Multiply 35 boys in the class I think that it's answer is 35may be number of boys in the class of 49 students is 35 35 is the correct answer of the given question |
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| 32. |
ORA contractor construct a vertical pillar at a horizopoint. It was decided that angle of elevation of the top of thepoint to be 60° .He finishes ine job by making a piiar such that the angle ofelevation of its top was 30°. Find the height of the pillar to be increased as per theterms of contractntal distance of 300 m from a fixedcomplete pillar from the |
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| 33. |
12. In a class of 49 students, the number of girls is of the number of boys. Find the number of boysand girls in the class. |
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Answer» let no of boys be Xhence girls will be 2/5xhence X+2/5x=497x/5=49X=49*5/7=35.. boyshence girls=2/5x=2/5*35=14 girls |
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| 34. |
In the given figure AS IBT; <4-25SB bisects ZAST. Find the measure of 21bisects At Find the measure of /1 |
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Answer» Given: AS is parallel to BT, and SB bisects angle AST that is angle 2 = angle 3 To find: The measure of angle 1 Solution: 1+2+3=180&2=3. because SB. is the bisector 1=4. because corresponding anglesangle 4=180-(2+3). ................ [1]angle 4=180-(3+5)....................[2]From 1&2,2=5 .....................[3]Hence,1+2+3=180&3+5+4=1803*angle 3=180angle 3=60It means angle 1=60 |
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| 35. |
TOO0O-Q.14 Ifp+q= 12 and pq = 22, then find p2+2- the difference between compound interest and sin |
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| 36. |
Find the co-ordinates of the foot of the perpendicular drawn from the point (2, 3) tothe ine y 3x+4 |
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| 37. |
ine is such that its segment between the straight lines 5r -y-440 is bisected at the point (1,5). Obtain its equation. |
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| 38. |
3. In a box, the ratio of red marbles to blue marbles is 7: 4. Which of the following cobe the total number of marbles in box?(a) 18(b) 19(c) 21 |
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63 p -5 by p44 |
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Answer» hit like if you find it useful |
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| 40. |
Question5A box contains red, blue and green marbles in the ratio 5:3:7. If there arealtogether 90 marbles, find the number of marbles of each colour.(a) |
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Answer» Let the ratio be xSo, red , blue and green are 5x, 3x, 7x respectively. According to question, 5x + 3x + 7x = 9015x = 90x = 90/15x = 6 So, blue marbles are 5 × 6 = 30Red marbles are 3 × 6 = 18green marbles are 7 × 6 = 42 |
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| 41. |
6. कोई धनराशि चक्रवृद्धि ब्याज से पहले वर्ष के अन्त में| 650 तथा दूसरे वर्ष के अन्त में हैं 676 हो जाती है।वह धनराशि है।| (a) * 600।(b)540(९) * 625(d) 560 |
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Answer» right answer is (C) 625rp |
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38. An observer 1.5 m tall is 45 m away from a tower.The angle of elevation of the top of the towerfrom his eyes is 300. The height (in m) of thetower is approximately(a) 25.9(b) 27.5(c) 27.8(d) 29.9 |
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Answer» C, option is correct answer option C. is correct answer. Question no 38 Answer is options is (C) 27.8 option c is the correct answer C , option is right answer |
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| 43. |
Kabir's mother keeps a record of his height on each birthday. When he was oneyear old. his height was 70 cm, at 2 years he was 80 cm tall and 3 years he was00 cm tall. His ount Meera was studying in the 10th class. She said. 'it seems likeabir's height grows in Arithmetic Progression". Assuming this, she calculatedhow tall Kabir will be at the age of 15 years when he is in the 10 She wasshocked to find it. You too assume that Kabir grows in A.P. and find oat hisheight at the age of 15 yearsnce is |
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Answer» As height of kabir increasing in AP which is given by70, 80, 90......... Here, a = 70 and d = 80 - 70 = 10 As we know nth term of an APan = a + (n - 1)d Then,a15 = a + 14d = 70 + 140a15 = 210 Therefore, age of Kabir at the of 15 years will be 210 cm |
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in of boys and girls in a school is 5:3. If there are 300 boys, find the number of girls in the school.The ratio of boys and gi |
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Answer» the number of girls are 180 |
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| 45. |
o In figure, CBAC=LCAD, themeasure of LADE is(2) 650 675 (0.105 (6) 120lb |
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Answer» in ∆abc we have, <a+<b+<c=180. [angle sum property]30+45+c=180.<c=180-75<c=105.BCD IS A STRAIGHT LINE. THEN, ACB+ACD=180.[bcd is a straight line]ACD=180-105ACD=75NOW, ADE=CAD+ACD [bac=CAD=30 given] |
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| 46. |
5. In a school, - of the students are boys. If there are 300 girls, find the number of boys in the school. |
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Answer» So as5/7 are boysremainining 1-5/7= 2/7are girlsso2/7= 3001 /1= 300*7/2= 150*7= 1050now 5/7 of 1050150*5= 750boys are 750 |
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| 47. |
30°, <C-509, AB=5cm, AC =8 cm andIt is given that Δ ABC-ΔDFE, LADF = 7.5 cm. Then find DE and LF |
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Answer» DE = 12 cm,∠F = 100° |
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| 48. |
In a class of 49 students, number of girls is 2/5 of the boys .Find the number of boys in the class |
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Answer» 35 boys is the right answer of this question total students =49number of girls=2x/5number of boys, =xx+2x/5=497x=49×5x=7×5x=35 number of boys=35 ans the correct answer is 3 the correct answer is 35 |
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| 49. |
Custruct the following triangles and measure1. A ABC in which AB = 6 cm. AC = 8 cm, ZBAC |
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| 50. |
19, In figure, S and T trisect the side QR of a right triangle POR, prove that :S TR |
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Answer» Since, S and T trisect the side QR QS = TS = RT Let’s assume QS = TS = RT = x QR = 3x and QT = 2x In Right angled triangle PQR, PR2= PQ2+ QR2 PR2= PQ2+(3x)2 PR2= PQ2+ 9x2 In Right angled triangle PQS, PS2= PQ2+QS2 PS2= PQ2+x2 In Right angled triangle PQT, PT2= PQ2+ OT2 PT2= PQ2+ (2x)2 PT2= PQ2+ 4x2 To prove that, 8PT2=3 PR2+ 5PS2 LHS = 8PT2= 8(PQ2+ 4x2) = 8PQ2+ 32x2 RHS = 3 PR2+ 5PS2= 3(PQ2+ 9x2) – 5 (PQ2+ x2)= 3PQ2+ 27x2+ 5PQ2+ 5x2= 8PQ2+ 32x2 LHS = RHS Hence, proved |
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