1.

19, In figure, S and T trisect the side QR of a right triangle POR, prove that :S TR

Answer»

Since, S and T trisect the side QR

QS = TS = RT

Let’s assume QS = TS = RT = x

QR = 3x and QT = 2x

In Right angled triangle PQR,

PR2= PQ2+ QR2

PR2= PQ2+(3x)2

PR2= PQ2+ 9x2

In Right angled triangle PQS,

PS2= PQ2+QS2

PS2= PQ2+x2

In Right angled triangle PQT,

PT2= PQ2+ OT2

PT2= PQ2+ (2x)2

PT2= PQ2+ 4x2

To prove that, 8PT2=3 PR2+ 5PS2

LHS = 8PT2= 8(PQ2+ 4x2) = 8PQ2+ 32x2

RHS = 3 PR2+ 5PS2= 3(PQ2+ 9x2) – 5 (PQ2+ x2)= 3PQ2+ 27x2+ 5PQ2+ 5x2= 8PQ2+ 32x2

LHS = RHS

Hence, proved



Discussion

No Comment Found