Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

४ हक G) d=i-j+2kb=i+j+kand é=2i~j+k ZA F O W निर्मम S T4 G5 =167 =2and ¢F =5 9% «f Fra =)

Answer»
2.

21. Two equal circles intersect in P and Q. A straightline through P meets the circles in A and B. Provethat QA QB.

Answer»
3.

13. Two equal circles intersect in P andQ. A straight line through P meetsthe circles in A and B. Prove thatQA = QB.

Answer»
4.

Comhateim

Answer»
5.

( i j f ( x + 1 ) ( x + 2 ) ( x + 6 ) = x ^ { 3 } + 9 x ^ { 2 } + 4 ( 7 x - 1 )

Answer»
6.

Page NoDate:Holiday Homew carte1. The length of a rectangle is 15 cm greaterthan its besteath. Its her perimeter is 156 cmFind its dimension of the rectangle?

Answer»

breath is 30 cmand length is 45 cm

7.

Page No.6uestion Bank C-1Linear Equation In Two Variablesvi)in the figure, the sides of a rectangle are given. The lengths arein cm. Find the length and breadth of the rectangle.4x4272844+23x-y +32x + 3y + 4

Answer»

length is 14 cm and b is 13 cm

8.

DATEPAGE NO3completethe following2x tyto24 Rectangle Ixt 4 -42-yTwo equation inxandy!Tvaluesofysy

Answer»
9.

P2Q² + (Pa2 Hate

Answer»
10.

Two equal circles intersect in PQ. A straight line through P meetsthe circles in A and B. Prove thatQA QB.13.and

Answer»
11.

3. Two equal circles intersect in P andQ. A straight line through P meetsthe circles in A and B. Prove thatQA QB

Answer»
12.

13. Two equal circles intersect in P andQ. A straight line through P meetsthe circles in A and B. Prove thatQA QB.

Answer»
13.

いrtn a class of 40 pupils, 35% are girls. How many girls are there in the class? How many of thepupils are boys?

Answer»

35 percentage of 40= 40*35/100= 14 girls26 boys

14.

002. In the given fig. I is parallel to m and pll q. Find the measure of each of the anglesa,b,c,d.Тр100!

Answer»

100°=angle D (vertically opposite)as angle D=angle B=100°(alternative interior angles) angle B=angle B=100°(alternative interior angles)angle besides to 100°=80°(straight line)as angle 80° =angle A=80°(alternative interior angles)

angle A=80°angle B=100°angle C=100°angle D=100°

aA=80°aB=100°aC=100°aD=100°

aA=80 degree aB=100 degree aC=100 degreeaD=100 degree

Angle A= 80° Angle B=100° Angle C=100° Angle D=100°

aA=80° aB=100° aC=100° aD=100°

<A = 80,<B = 100,<C= 100,<D = 100 is right answer

15.

lfsin 3θcos (9-69) here. 3θ and (8-6) are acute angles, find the value ore.

Answer»

Sin 3A = cos (A-6)

sin 3A = sin (90-(A-6))

( since sin(90- A) = cos A)

therefore,

3A = 90-(A-6)

3A = 90-A+6

3A+A = 96

4A = 96

A = 96/4

A = 24

16.

6.Simplify.5 15 20

Answer»

(-4×12-3×4+7×3)/60=(-48-12+21)/60=-39/60=-13/20

Thank u

17.

There are 38 boys and 27 girlsin a class. How many pupilsare there in the class?

Answer»

In the class boys are=38 & girls are=27. so The total students in the class are=38+27.

The total number of pupils are 65. *

18.

B and CD are two parallel lines and a transversal I intersects AB at X andCD at Y. Prove that the bisectors of interior angles form a rectanglePage 1 of4

Answer»
19.

In the given figure, AB I| CD and PQ, QRintersects AB and CD both at E, F and G, Hrespectively. Find the value of x.120°80°(A) 40° (B) 20° (C) 100° (D) 30°

Answer»

1

2

20.

In the given figure&lt;122 and ΔNSQsANATR, then prove thatOr

Answer»

the triangles PTS and PQR, let us assume that Q = angle 3 and R = angle 4.

So, angle 1 = angle 3 (corresponding angles)

and angle 2 = angle 4 (corresponding angles)

Angle P is common angle.

By AAA similarity triangle PTS is similar to PQR.

Hence proved

hit like if you find it useful

21.

In Δ PQR. If PQ &gt; PR and bisectors of &lt;Q and &lt;Rintersect at S. Show that SQ &gt; SR.Fig. 3.58

Answer»
22.

7Two equal circles of radius r, intersect such that each passes through the centreof the other. The length of their common chord isb. 2rd.2

Answer»
23.

. Solve:4x2 + 4bx-(a2-b2)=0

Answer»

yes it is right

24.

26/ The diagonals of a trapezium ABCD with AB | DC intersect each other at point O. IfAB 2CD, find the ratio of the areas of triangles AOB and COLD

Answer»
25.

is a trapezium in which ABIICD andCD. Its diagonals intersects each other at O6ABCDthen what is the ratio of the areas of the trianglesAOB and COD ?(A) 1 2(B) 2 1

Answer»
26.

of the students are boys. If there are 240 girls, find the number of51520a schoolthe school.many nages are there in the booka

Answer»

what is the difference between 40% of 60 and 60% of 40?

27.

27. In a school, 8 of students are boys. If there are 240 girls, find the number of boys in the school,8

Answer»
28.

IfAB|| CD, findx, y and z from the given figure:002B1300

Answer»

bcz AB ll DC

z =180-130 =50x = 130y = 130

29.

14. The product of two fractions is 9 ore Un18. In a school of the students are boys. If there are 240 girls, find the number ofthe schoolnades are there in the booles

Answer»
30.

6.In a school the ratio of boys togirls is 3:5. If there are 240 boys,how many pupils are there in thatschool?A. 400 B. 640C. 144 D. 384

Answer»

Let the number of be 3x and number of girls be 5x

Then,3x = 240x = 240/3 = 80

Therefore, total number of pupil in school = 3x + 5x = 8x= 8*8 = 640

(B) is correct option

31.

-/a2+b2 , 0 &lt; θ &lt; 90 thenfind the values of secθ and tan8.

Answer»
32.

(ii) x2 2x-9 0Solution : Compare x2 + 2x-9 = 0 withax2 + bx + c = 0b= 2, c=1,b2-4ac- 22-4xD-4-□D= 40,'. b2-4ac &gt; 0the roots of the equation are real andunequal.

Answer»

a = 1, b = 2, c = - 9

b^2 - 4ac = 2^2 - 4*1*-9D = 4 - (-36)D = 40

33.

Diagonals AC and BD of a quadrilateralABCD intersect at O in such a way thatar (AOD) ar (BOC). Prove that ABCD is atrapezium.C

Answer»
34.

If ad(abe then prove that the equation2 + b2)x2 + 2(ac + bd)x + (c2 + d2)(,0 has no real roots.

Answer»
35.

21. Diagonals of a trapezium ABCD with AB II CD intersects at O. If AB = 2CD, find the ratio ofareas of triangles AOB and COD

Answer»
36.

i6. Diagonals of a trapezium ABCD with ABlIDC intersect each other at the point O. IA-2CD,find the ratio of the areas of triangles AOB and COD

Answer»

Like if you find it useful

37.

Diagonals of a trapezium ABCD with AB | DC intersect each other at the point O.IfAB 2CD, find the ratio of the areas of triangles AOB and COD.

Answer»
38.

In the given figure, AOB is a straight line and the rays OC and OD stand con it.If ZAOC 65°, BOD70° and CoD, find the value of x6570

Answer»
39.

| DC intersect each other at the point O.IfAB 2 CD,findDiagonals of a trapezium ABCD with Aratio of the areas of triangles AOB and COD.21.B

Answer»
40.

18. Diagonals of a trapezium ABCD with AB I DCintersect each other at the point O. If AB 2CD,Find the ratio of the areas of triangles AOB and COD

Answer»
41.

15.4 cm, find BC.Diagonals of a trapezium ABCD with ABDC intersect each other at the point o.IfAB 2 CD, find the ratio of the areas of triangles AOB and COD.

Answer»

thank u ... ☺☺

42.

2. In a school, of the students are boys. If there are240 girls, find the number of boys in the school?

Answer»
43.

If \mathrm{ad} \neq \mathrm{bc}, then prove that the equation(a2 + b) x+ 2 (ac + bd)x+ (e + d) 0 has no real roots.

Answer»

(a²+b²)x²+2(ac+bd)x+(c²+d²)=0a=(a²+b²) b=2(ac+bd) c=(c²+d²)putting a,b,c in formula[-b +/-√(b²-4ac)]/2a{-2(ac+bd) +/-√[4(ac+bd)²-4(a²+b²)(c²+d²)]}/2(a²+b²)[-2(ac+bd) +/-√4a²c²+4b²d²+8abcd-4a²c²-4a²d²-4b²c²-4b²d²]/2(a²+b²)-2(ac+bd) +/-√ - (4a²d²-8abcd+4b²c²)Hence root cant be negative.So, it has no real roots.

44.

Solve the following equation for X: 4x2 +4bx- (a2 -b2)=0

Answer»

4x² +4bx -(a² -b²) = 0

4x² +4bx -a² + b² =0

(2x)² + 2.(2x).b + b² -a² =0

(2x + b)² -a² = 0

use formula,

a²-b² = (a -b)(a + b)

{2x + b -a}{2x + b +a} =0

Therefore, x = (a - b)/2 , - (a + b)/2

45.

== v&amp; Sk, SISsec? (tan~" 5) + cosec? (cotโ„ข} ยง) =

Answer»

Please hit the like button if this helped you

46.

Solve the following systems of linear equation:a(x+y) _ b (x-y)-a2 + ab + b2[HOTS

Answer»

please like my answer if you find it useful

47.

a का 2% = b, तो 10 का b%,बराबर होगा |(Aa का 200%Ba/100 का 20%Ca/10 का 20%(Da/10 का 200%

Answer»

c answer a/10 ka 20% was the answer

48.

डिक डी ~ ) TL हे... /5

Answer»

(5/3)^-(n-1)=( 5/3)^n-3n-3= -n+12n= 4n = 2

49.

()Tl).}S

Answer»

{((x^(-5))^(2/3)}^(-3/10)

{x^(-10/3)}^(-3/10)

x^1

=x

50.

In a trapezium ABCD if AB|ICD and diagonals intersect at O, prove that AO.OD BO.OC16. The angles of a triangle are x, y and 40°. The difference between the twoangles r and y is30°. Find r and y

Answer»

x-y=30 →equation 1

x+y+40 = 180 (since sum of angles of a triangle = 180)

x+y=140 →equation 2 (variables on one side,constants on one side)

equation 1 → x-y=30

equation 2 → x+y=140

⇒ 2x= 170 (∵ -y+y=0)

⇒x = 170/2

⇒ x = 85

substitute x in equation 1 (or equation 2.its your choice. you'll get the same answer)

equation 1 → x-y=30

85-30 = y (substituting x and bringing 30 on one side and y on one side)

55 = y

∴x=85

y=55