1.

lfsin 3θcos (9-69) here. 3θ and (8-6) are acute angles, find the value ore.

Answer»

Sin 3A = cos (A-6)

sin 3A = sin (90-(A-6))

( since sin(90- A) = cos A)

therefore,

3A = 90-(A-6)

3A = 90-A+6

3A+A = 96

4A = 96

A = 96/4

A = 24



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