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lfsin 3θcos (9-69) here. 3θ and (8-6) are acute angles, find the value ore. |
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Answer» Sin 3A = cos (A-6) sin 3A = sin (90-(A-6)) ( since sin(90- A) = cos A) therefore, 3A = 90-(A-6) 3A = 90-A+6 3A+A = 96 4A = 96 A = 96/4 A = 24 |
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