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4x*x + y*y + z*z - 4xy - 2yz + 4xz = (2x)(2x) + (-y)(-y) + z*z + 2(2x)(-y) + 2(-y)(z) + 2(2x)(z) = (2x-y+z)(2x-y+z)

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4x2-88-80answerthis is the correct answer

Use the BODAMAS to get the answer=4×2–8=8–8=0.

4 x 2 - 8 = 8 - 8 = 0

4×2-88-80OK OK OK ok

8-8=0 is right answer.

0 is a correct answer

0 is the right answer

4*2=88-8=0 is the correct answer

correct answer is 0

Given f(x)=kx²-2kx+6=0Has equal roots

ie.. D=b²-4ac=0

Here a=k;b=-2k;c=6

Now (-2k)² -4(k)(6)=04k²-24k=04k²=24kk=24/4k=6

ratio of water to milk 3:1so for 3 part of water we have 1 part of milk to make a teaso for 4 cups of tea we need3×4 : 1×4 12:4 so ratio requried is 12:4

We know, that we can write 100000 = 10 * 10 * 10 * 10 * 10Alsofactors of 10 are = 5 * 2

100000 = 5 * 2 *5 * 2 *5 * 2 *5 * 2 *5 * 2100000= 5 * 5 * 5 * 5 * 5 * 2 * 2 * 2 * 2 * 2100000 = 3125 * 32

So we can say

X = 3125Y = 32

sin10sin30 sin 50 sin70 = 1/16

=1/2 (sin10 sin50 sin70)

=1/2 (sin50 sin70) sin10

​=1/2 (sin(60-10)sin(60+10)) sin 10

=1/2(sin260-sin210)sin10

​=1/8(3/4-sin210)sin10

=1/8(3-4sin210)sin10

=1/8(3sin10-4sin310)

​=1/8(sin3X10)

=1/16

from snell's law

n1sini = n2 sinr

=> sini/sinr = n2/n1 = nr/ni

The area formed by the 4 quadrants is equal to the area of a circle. so we have to subtract the area of a circle from the area of the square. the radius of the circleis 6cm

∴l²-πr²12×12-3.14×6×6144-113.0430.96 cm² the shaded region is 30.96cm²

The shepherd hadn't been to school because

(ii) There were very fewschoolsin those days .

2. One daythe king of that countryvisited the shepherdin disguise. Hevisited the shepherdbecause he had heard that theshepherdwas very wise and understood people's sorrows and troubles, and helped them face their problems with courage and common sense.

study

1.

In figure PS is the median Triangle PTS is a right angled triangle. Therefore according to figure angle PTS is a right angle. Therefore both the anlge that is angle TPS and angle TSP are not right angles but both of them are acute angles. Therefore if angle TSP is acute then angle PSR has to be an obtuse angle.Consider triangle PTRangle PSR is an obtuse angle which I already proved.There is a theorem which states relation between side opposite to obtuse angle with two remaining sides. According to that theorem PR^2 = SR^2 + PS^2 + 2SR*STIt can be rewritten as PR^2 = PS^2 + QR*ST + (QR/2)^2SR^2 is rewritten as (QR/2)^2 and 2SR is rewritten as QR Hence, proved.

tan60 = 3^0.5.cos30 = (3^0.5)/ 2sin45 = 1/ (2^0.5)

4/ (tan60)^2 + 1/ (cos30)^2 - (sin45)^2= 4/3 + 4/3 - 1/2= 8/3 - 1/2= 13/6

Right answer

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Preventative weed control refers to any control method that aims to prevent weeds from being established in a cultivated crop, a pasture, or a greenhouse. Examples of preventative weed control would be using certified weed free seed, only transporting hay that is weed free, making sure farm equipment is cleaned before moving from one location to another, and screening irrigation water to prevent weed seeds from traveling along irrigation ditches.

The money obtained by c is RS. 45

45 is the correct answer

45 is your correct option

the money obtained by c is 45 rupees

wieght of box= 1.75total no. of chocolates= 35

weight of each chocolate is= 1750/35 (1kg=1000g)

weight of each chocolate is 50g (or) 0.05kg

Weight of each chocolate=17500/35=500

The weight of each chocolate =17500/35=500g

weight of each chocolate is 50g or 0.05kg

weight of each chocolate is 50 g

Let α and β are the roots of quadratic equation x² - 4kx + k + 3 = 0∴sum of roots = - coefficient of x²/coefficient of x α + β = -(-4k)/1 = 4k

Product of roots = constant/coefficient of x²αβ = (k + 3)/1 = (k + 3)

A/C to question, sum of roots = 2 × product of roots (α + β ) = 2αβ⇒4k = 2(k + 3) ⇒ 4k = 2k + 6 ⇒ 4k - 2k = 6 ⇒ 2k = 6 ⇒ k = 3

Hence, answer is k = 3

12=1*1+15=2*2+116=5*3+165=16*4+1326=65*5+1so next term is 326*6+1=1957

x-1/x+1+x+3=x-3/x+1x-1/2x+4= x-3/x+1x^2-1=2x^+2x+4x+40=x^2+6x+5x= -6+-√36-4×4/2

X=5. X=-5 is the right answer

x=5 is the best answer

x=5 & x=-5 are the correct answers

x-1/x+1+x+3=x-3/x+1x-1/2x+4=x-3/x+1x^2-1=2x^+2x+4x+40=x^2+6x+5x=-6+36-4×4/2

x=5 &x=-5 are the correct answers

12=1*1+15=2*2+116=5*3+165=16*4+1326=65*5+1so next term is 326*6+1=1957

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Use concept , हमें ज्ञात हैlogx + log y = logxy

given, दिया गया हैlog2x + log4x +log16x = 21/4

log{ 2x.4x.16x } = 21/4

log { 128x³} = 21/4

log(128) +logx³ = 21/4

7log2 + 3logx = 21/4

3logx = 7{ 3/4 -log2}

logx = 7/3{ 3/4 -log2 }

x = 10^[7/3{3/4-log2}]अतः सिद्ध हुआ

If the cost of 7 pencils is 30rs then the cost of 1 pencil is 7/30=0.233

If 3 pencils cost Rs 7, then 1 pencil should cost 7/3 = 2.333Rs. Therefore 5 pencils should cost 5x2.333Rs = 11.665Rs.

21/30=.7 is the correct ans ok

Let cost of pen=x cost of pencil=ythen 5x+10y=30and x=3+y => subtituting in the first equation5(3+y)+10y=3015+15y=3015y=15y=1x=3+y => x=3+1=4

cost of pen =4 cost of pencil =1

7 pencil is rs 30 than 1 pencin is rs 4.28 than 3 pencin =12.84 rs

12.857 is the correct answer

cost of 7 pencil is 30cost of 1 pencil is 30÷7=4.285coat of 3 pencil is =3×4.285=12.857

12.857 is A correct answerplz mark as best

Given that

cosec x +cot x = k --------------(1)we know thatcosec^2x -cot^2 x = 1(cosec x +cot x)(cosec x -cot x) = 1k (cosec x-cot x) = 1(cosec x-cot x) = 1/k ------------------(2)

from (1) &(2)cosec x+cot x = kcosec x-cot x = 1/k

2cosec x = k+1/k2cosec x= k^2+1/kcosec x = k^2+1/2ksin x = 2k/k^2+1we know thatcosx =√1-sin^2 xcos x =√1-[2k/k^2+1]^2cos x =√1-4k^2/(k^2+1)^2cos x =√(k^2+1)^2-4k^2/(k^2+1)^2cos x =√(k^2-1)^2/(k^2+1)^2 {·(a+b)^2-(a-b)^2 = 4ab}cos x =√[k^2-1/k^2+1]^2cos x = k^2-1/k^2+1

Hence proved

Thank you but can you send another simple method

34 is the correct answer of the given question.