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1.If the equation kor? - 2k+6=0 has equalroots, then find the value ofk.

Answer»

Given f(x)=kx²-2kx+6=0Has equal roots

ie.. D=b²-4ac=0

Here a=k;b=-2k;c=6

Now (-2k)² -4(k)(6)=04k²-24k=04k²=24kk=24/4k=6



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