Saved Bookmarks
| 1. |
1.If the equation kor? - 2k+6=0 has equalroots, then find the value ofk. |
|
Answer» Given f(x)=kx²-2kx+6=0Has equal roots ie.. D=b²-4ac=0 Here a=k;b=-2k;c=6 Now (-2k)² -4(k)(6)=04k²-24k=04k²=24kk=24/4k=6 |
|