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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
E obt08+9+8+V9 WXYZGANOBoer |
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Answer» A+2B+170is correct answer a+2B+170 is the answer A+2B+170 is the correct answer of the given question. A+2B+170 it is a correct answer ........ A + 2B = - 170 is correct answer A+2B=-170 is the correct answer A+2B+170 is the correct answer A+2B+170 is right answer .. |
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| 2. |
TRY THESENazma's sister also has a trapezium shaped plot. Divide it into three parts as shown(Fig 11.4). Show that the area of trapezium WXYZ-h(a+b)1.2-bIf h = 10 cm, c = 6 cm, b = 12 cm.d-4cm, find the values of each ofits parts separetely andhadd to findthe area WXYZ. Verify it by puttingthe values of h, a and b in theyă 2.expression ha +b)2Fig 11.4 |
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Answer» thanks |
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| 3. |
Diagonals of a parallelogram WXYZintersect each other at point O. Find l(WY). |
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| 4. |
(4) Diagonals of a parallelogram WXYZintersect each other at point O. Find I(WY). |
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Answer» Diagonals of a parallelogram bisect each other. soWO=OY=5 cmso WY=WO+OY =2×5 cm =10 cm |
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| 5. |
Construct a parallelogram WXYZ, in which WX = 4.5 cm, WY = 6 cm and XZ-7 cm. |
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Answer» bro not this please again |
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| 6. |
Fig. 6.304yIn Fig. 6.31, if PQ 11 ST. < PQR = 1100 andP Q< RST = 130°, find < QRS.(Hint : Draw a line parallel to ST throughpoint R.1301 10Fig. 6.31 |
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| 7. |
के हक 6+6- कि मी (1 कददनक देह पी द b+ (ot 6 -. (०6९00 [| 1 ३५१०१ ९९९७ 3 9. |
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Answer» (1 + cos/sin - 1/sin ) (1+1/cos + sin /cos ) ( cos + sin - 1) (cos + sin +1 )---------------------------------------cos * sin (cos+sin)² - 1²-----------------cos * sin 1+ 2 cos sin - 1-----------------cos * sin 2 |
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| 8. |
Find the angles between the pairs of straight lines: |
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| 9. |
Find the equation to the straight line cutting offan intercept-5 from the axis ofy and being equally inclinedlto the axes. |
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Answer» SIMILAR QUESTION-find the equation of the line cutting off an intercept -2 from the y axis and equally inclined to the axis . SOLUTION- Since the required line is equally inclined with the coordinate axes, therefore, it makes either an angle of 45° or 135° with the x-axis. So, its slop is either m =tan 45° or m = tan 135° i.e., m = 1 or m = -1. It is given that c = -2. Substituting these values in y = mx + c, we obtain the required equation of the line as: y = 1(x) + (-2) or y = -1(x) + (-2) ⇒ y = x - 2 or y = -x - 2 |
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| 10. |
12. The digit in the units place of (6789) is(A) 6(B) 7 |
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Answer» The digit in the unit place of (6789)^5 is 9. but how please give explanation I got it. |
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| 11. |
हि (५. b+ Qm... 3१५० 6५) 9001 |
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| 12. |
In Δ PQR. D is the mid-point of QR .PM isPD ISIs QM MR? |
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| 13. |
D. In Δ PQR , QMLPR and PR2-PO-QR"Prove that QM-PM × MR |
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| 14. |
Given that PORSWXYZ, find the corresponding parts. |
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Answer» 11. angle Y = angle RRS = YZ |
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| 15. |
プもピanale |
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Answer» let X be the common multiplehence the angles will be 2x,3x,5xnow sum of angles of a triangle are 180°2x+3x+5x=18010x=180X=180/10=18°then the angles are 2x=2*18=36°3x=3*18=54°5x=5*18=90° thanx |
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| 16. |
०८ पीस: Thed >~& U//,a nकि + (कैति $ उंग हु: 5पु धन Sody |
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| 17. |
The distance of the center of the ellipsex2+2y2-2 0 to those tangents of the ellipse which are equallyinclined to both the axes isV2(A)ĺż(B) 2 |
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Answer» y=mx±√2m^2+1,m=±1 The tangents arey=±x±√2+1 y=x±√3 distance of the tangent from origin is d=∣0+0±√3/√1^2+1^2| =√3/2 Answer:√3/2 |
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| 18. |
4 Find the equation of the line cutting off an intercept-2 from the y-axis andequally inclined to the axes |
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| 19. |
Find the equation of the straight lines which cut off an intercept 4 fromthe y-axis and are equally inclined to the axes3. |
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| 20. |
\frac { 4 ^ { 5 } \times a ^ { 8 } b ^ { 3 } } { 4 ^ { 5 } \times a ^ { 5 } b ^ { 2 } } |
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| 21. |
6ntercept ot b units on the negative direction of the y-axis.Find the equation of the line cutting off an intercept-2 from the y-axisequally inclined to the axes.and |
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Answer» intercept at y axis , b=-2 line is qually inclined so the intercept will be equala=b=-2eq. of line with equal intercepts is x+y=aso the equation of required line is x+y=-2 |
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| 22. |
ORS is a parallelogram (Fig 11.23). QM is the height fromQo SR and QN is the height from Q to PS. If SR 12cm andOM-7.6 cm. Find: |
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| 23. |
PORS is a parallelogram (Fig 11.23).QM isto SR and QN is the height from Q to PS. If SRQM 7.6 cm. Find:the height from Q12 cm and |
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Answer» thanks |
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| 24. |
RS is a parallelogram (Fig 11.23). QM is the height from Qto SR and QN is the height from Q to PS. If SR= 12 cm andQM = 7.6 cm. Find: |
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Answer» a) Given, Base = 12 cm, Height = 7.6 cm Area of the parallelogram PQRS = Base××Height=12cm×7.6cm=91.2=12cm×7.6cm=91.2sq cm (b) Given; Base PS = 8cm, Area of the parallelogram(as calculated in the above question) = 91.2 cm2, Height QN= ? Area = Base××Height⇒91.2cm2=8cm×QN⇒91.2cm2=8cm×QNOr,QN=91.28=11.4QN=91.28=11.4cm |
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| 25. |
12. In the given figure, PT = PS and TQ-SR. Prove that QS = RT. |
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| 26. |
2)In △ ABC m<BAC-90 seg BL and iegCMare medians of △ABC then prong that |
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Answer» Given : ABC right angle triangle at A where BL and CM are the medians To prove : 4(BL^2 + CM^2)=5BC^2 Proof :Since BL is the median AL=CL=1/2 AC .............(1) Similarly CM is the median AM = MB = 1/2 AB ........... (2) In triangle ABC BC^2 = AB^2 + AC^2 In triangle BAL BL^2 =AB^2 +AL^2 BL^2 =AB^2 +(AC/2)^2 On further little solving steps 4BL^2 =4AB^2 +AC^2 Then in triangle MAC CM^2 =AM^2 +AC^2 Doing same process here We get 4CM^2 =AB^2 +4AC^2 Like my answer if you find it useful! |
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| 27. |
In Δ ABC,BAC90°seg BL and seg CM are mediansof Δ ABC. Then prove that:4(BL) + CM*) = 5 BC" |
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| 28. |
The multiplicative inverse of -7 /12 |
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Answer» (-7)/12 is multiplicative (-12)/7 |
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| 29. |
POQ. [In a parallelogram PORS, the bisectors of ZP and 4Q meet at O. Find |
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| 30. |
(i) side BC 0) the meuras an angle 30 with s17. Find the equations of the medians of the triangle ABC whose7. Find the equations of the medians of the triangle ABC whose vertices are A(2, 5),B(- 4, 9) and C 2, 1) |
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| 31. |
If two chords of a circle are equally inclined to the diameter throughtheir point of intersection, prove that the chords are equal |
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Answer» given: AB is the diameter of the circle with center O. ∠BAC=∠BAD TPT: AC=AD construction; draw OM⊥AC and ON⊥AD proof: in the triangle OMA and triangle ONA, ∠OMA=∠ONA=90 deg (by the construction) ∠OAM=∠OAN OA is common. therefore by AAS congruency, triangles are congruent. hence by the congruent property of the triangles OM = ON ⇒AC = AD [equal chords are equidistant from center ] which is the required result. |
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| 32. |
In the figure, X is the mid-point of the side RS of a parallelogram PORSR parallel to PX intersects PQ at Y and SP produced to z. Show that PS PZ and3×4=12z. |
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| 33. |
if 2 intersecting chords of a circle makes equal angle with diameter passing through their point of intersection, prove that chords are equal. |
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Answer» Thnks |
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| 34. |
¢l L कुछ इश्क उप P30 2809 ¥12 द८9 का: 1 लिए [कान 102 है. 91८(७५ [कि Bie bhpe b 2l M BEY |
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Answer» hit like if you find it useful |
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| 35. |
PORS is a parallelogram (Fig 11.23). QM is the height from Q7.6 cm. Find:) the area of the parallelogram PQRS (b)QN, if PS 8SR and ON is the height from Q to PS. If SR 12cm and QM |
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| 36. |
ë°260Fia :1Ciii btF cte |
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| 37. |
Fig. 5.16, LPQR LPRQ, then proveFia. 5.16 |
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| 38. |
Multiplicative inverse of -3/5 is - |
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Answer» The multiplicative inverse of -3/5 is -5/3. multpicative inverse of -3/5 is -5/3 |
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| 39. |
ObjectiveMultiplicative inverse of(A)0 |
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Answer» please post a nice image of this question it's really blur it's not understandable what's written in the image (a)-: 0. (b)-: -1 is the correct answer the photo is not clear that's why we cannot answer this question a=0,b=1 is the correct answer |
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| 40. |
e multiplicative inverse of the following: |
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| 41. |
ABCD is a rectangle formed by the points A(-1,一1 ), B(-l , 4), C(5,4) and D(5,-1 ). P.QR and S are the mid-points of AB, BC, CD and DA respectively. Is the quadrilateralPORS a square? a rectangle? or a rhombus? Justify your answer.8.7.5 Summary |
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| 42. |
of medians divides them in the ratio 2:Dmedia3. Medians BE and CF of a triangleAredians BE and CF of a triangle ABC are equaint. Point of intersectionProve gseren isure (1221),PORS is a square andis a square and SRT is an equilateral triangle(NCERT)d. In the given figure10.lathesquare a(ii) <QRT=15" |
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| 43. |
seg BL and seg CM are mediansofA ABC. Then prove thatFia. 232 |
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Answer» thanks for replay |
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| 44. |
Sumoftwonumbers is asIf one breeds thefirstbey16 - fedthe number |
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Answer» 15+x=95×=95-15=80x=80 please like me Let the number are x and x + 15 x+x+15=952x+15=952x=95-152x=80x=80/2x=40replace the value of x,x+15=40+15=55Answer :- 40 and 55 are the correct answer . |
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| 45. |
2. In a parallelogram PORS, the bisectors of 4P and 2Q meet at O. Find POO. |
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Answer» In parallelogram PQRS, ∠P + ∠ Q = 180°So (∠P + ∠ Q)/2 = 180°/2∠OPQ + ∠OQP = 90° ......(1) We know in ∆POQ∠OPQ + ∠OQP + ∠POQ = 180°From (1)∠POQ = 180° - 90° = 90° thanks |
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| 46. |
Bidashisson,lindtheir ages.rs, Monica will be four times as old as she is now. Determine herpresent age. |
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| 47. |
10) The pumbers 4 and 9 have frequencies x and (x-1),respecively. If their arthmetic mean is 6, then x isequal toA) 0.02B) 0.03D) 0.05C) 0.04 |
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Answer» Note in option there is no option for x equal to 3 and that's why possibly qsn is incorrect...and x equal to 3 clearly satisfies the condition. |
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| 48. |
EXAMPLE 40.The sum to n terms of the seriesー+++ IS+、313+1515+17(a) v2n +1(c) v2n +1-1(b) (1/2) v2n +1(d) (1/2) /v2n +1-1) |
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| 49. |
\left. \begin{array} { l } { \text { he value of } \frac { 1 - \operatorname { tan } ^ { 2 } 15 ^ { \circ } } { 1 + \operatorname { tan } ^ { 2 } 15 ^ { \circ } } \text { is } } \\ { 1 } \\ { \frac { \sqrt { 3 } } { 2 } } \end{array} \right. |
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| 50. |
Which of the following are in inverse proportion?The number of workers on a job and the time to complete the joban for a Ä°oumev and the distance tra velled in a uniform speedtok |
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Answer» We know that more is the number of workers to do a job, less is the time taken to finish the So, it is a case of inverse proportion. 1 part are inverse proportion |
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