2)In △ ABC m<BAC-90 seg BL and iegCMare medians of △ABC then prong

1.	2)In △ ABC m<BAC-90 seg BL and iegCMare medians of △ABC then prong that
Answer» Given : ABC right angle triangle at A where BL and CM are the medians To prove : 4(BL^2 + CM^2)=5BC^2 Proof :Since BL is the median AL=CL=1/2 AC .............(1) Similarly CM is the median AM = MB = 1/2 AB ........... (2) In triangle ABC BC^2 = AB^2 + AC^2 In triangle BAL BL^2 =AB^2 +AL^2 BL^2 =AB^2 +(AC/2)^2 On further little solving steps 4BL^2 =4AB^2 +AC^2 Then in triangle MAC CM^2 =AM^2 +AC^2 Doing same process here We get 4CM^2 =AB^2 +4AC^2 Like my answer if you find it useful!

2)In △ ABC m<BAC-90 seg BL and iegCMare medians of △ABC then prong that

Answer»

Given : ABC right angle triangle at A where BL and CM are the medians

To prove : 4(BL^2 + CM^2)=5BC^2

Proof :Since BL is the median

AL=CL=1/2 AC .............(1)

Similarly CM is the median

AM = MB = 1/2 AB ........... (2)

In triangle ABC

BC^2 = AB^2 + AC^2

In triangle BAL

BL^2 =AB^2 +AL^2

BL^2 =AB^2 +(AC/2)^2

On further little solving steps

4BL^2 =4AB^2 +AC^2

Then in triangle MAC

CM^2 =AM^2 +AC^2

Doing same process here We get

4CM^2 =AB^2 +4AC^2

Like my answer if you find it useful!