Explore topic-wise InterviewSolutions in Current Affairs.

3x+5y-5x-7y=-2x-2y=-2(x+y)

multiply both mattrix take adj / |A| get answer

[3/6]/ 18 be the answer

Let the base be xThen height = x/3Area of llgm= 108cm²b×h= 108cm²x*x/3= 108x²= 108*3x= √324x= 18cmBase of parallogram= 18cmHeight of the parallogram = x/3= 18/3= 6cm

1) (a)numerator =3denominator=8b) numerator =5denominator=11c) numerator=4denominator=9d) numerator=23denominator=61e) numerator=0denominator=10g)numerator=7denominator=31

a) √3/100 is an irrational number

b) -√2/81 is an irrational number

which of the following is an irrational number?

Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )

So,

if 3 is the factor of p²

So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q²

then, 3 is also factor of q

Since

3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

hence,. √3 is an irrational number

If you find this solution helpful, Please give it a 👍

x=4,x=2/3 this is right answer

x=4 and x=2/3 it is the correct answer

3x+5y = 25 , 7x+6y = 30Using substitution method :3x+5y = 25 --------> (i)7x+ 6y = 30 -------->(ii)

From equation(i)3x= 25-5y x = 25-5y/ 3------->(iii) Putting the value of x in equation (ii)7x +6y =307(25-5y/3) = 30175 -35y +18y = 90175 -90 -17y =085 -17y =0-17y = -85y = 85/ 17y = 5

Putting value of y in equation (iii)x= 25-5y /3x= 25-5(5)/ 3 x= 25-25 / 3x= 0/3x = 0

So value of x= 0 and y= 5

Like my answer if you find it useful!

(7x+y)(x+5y)= 7x²+35xy+xy+5y²= 7x²+36xy+5y²

an=a+(n-1)d=62 and a=8Sn=n/2(2a+(n-1)d)=n/2(8+62)210=n/2(70)so n/2=3so n=6

angle 2 is 150 ° and angle 3 is 360- 150 = 2 1 0°

angle 3 = 30°angle 2 = 180-30 = 150 °

angle 3=30°angle 2= 180-30= 150°

Please hit the like button if this helped you

please give me best and I will give you best

cotθ = q/pcosθ/sinθ = q/ppsinθ + qcosθ = sinθ{(p + q(cosθ/sinθ)} = sinθ{p + q(q/p)} = sinθ(p² + q²)/ppsinθ - qcosθ = sinθ{(p - q(cosθ/sinθ)} = sinθ{p - q(q/p)} = sinθ(p² - q²)/p(psinθ + qcosθ)/(psinθ - qcosθ) = {sinθ(p² + q²)/p}/{sinθ(p² - q²)/p} = (p² + q²)/(p² - q²)

1)4,22)-3/2,7/33)7,74)0,115)-12,-126)0,-1

use identity if a3+b3+c3 = 0then, a3+b3+c3 = 3abc

Given:

7a7=11a11Formula:an=a+(n-1)

a7=a+6d; a11=a+10d

Now 7(a+6d)=11(a+10d)7a+42d=11a+110d4a=-68da=-17d--------(1)

Now,a18=a+17d a18=-17d+17d.....(from (1))

Therefore a18=0

thanks

Let us suppose 3+root 5 is rational.=>3+root 5 is in the form of p/q where p and q are integers and q is not =0=>root5=p/q-3​=>root 5=p-3q/qas p, q and 3 are integers p-3q/3 is a rational number.=>root 5 is a rational number.but we know that root 5 is an irrational number.this is an contradiction.this contradiction has arisen because of our wrong assumption that 3+root 5 is a rational number.hence 3+ root 5 is an irrational number.

Let us assume that 3 + √5 is a rational number.

Now,

3 + √5 = (p /q)

[Here p and q are co-prime numbers]

√5 = [(p /q) - 3]

√5 = [(p - 3q) / q]

Here, {(p - 3q) /q} is a rational number.

But we know that √5 is a irrational number.

So, {(p - 3q) /q} is also a irrational number.

So, our assumption is wrong.

3 + √5 is a irrational number.

Hence, proved.

Like if you find it useful

To make denominator as 40multiply and divided by 5hence7*5/8*5=35/40

thanks

Radius of cone = radius of hemisphere = 1cmheight of cone = r = 1cm

volume of the solid term= volume of cone + volume of hemisphere

=1/3*πr^2h+2/3πr^3= 1 / 3 × 3.14 × 1× 1×1 + 2/3 × 3.14 × 1× 1×1 = 3.14 / 3 + 6.28 / 3= 1. 046 + 0.293= 1 . 339 Sq. cm

Therefore volume solid term is 1.339 Sq. cm

Let p=(x,y) be a point on locus(x-1)^2+(y-2)^2+(x-2)^2+(y+3)^2=2[(x+2)^2+(y-3)^2]=x^2-2x-1+y^2-4y-4+x^2-4x+4+y^2+6y+9=2[x^2+4x+4+y^2-6y+9]=2x^2+2y^2-6x+2y+18=2x^2+2y^2+8x-12y+26=8x-12y+26+6x-2y-18=0=14x-14y+8=02(7x-7y+4)=0 locus of p(x,y) is 7x-7y+4=0

It has something to do with the asymptotes of the hyperbola, even though they are not perpendicular. But it's a start.

First put the equation into the form (x-h)²/a² - (y-k)²/b² = 1.4x² - 9y² = 36x²/9 - y²/4 = 1x²/3² - y²/2² = 1This is a horizontal hyperbola centered at the origin.The asymptotes are y = -2/3x and y = 2/3x.

correct

it is a irrational number

yes it is true 2 is a rational no.

yes √4=2 is rational number

yes √4 = 2

And is a rational number

yes,root 4 =2 is rational number

thanks

Let time =xDistance of a=40*x+15 B=50*xSince;distance a=distance b40(x+15)=50x40x+600=50x600=50x-40x=10xX=600/10=60Answer is (ii) 60

the answer is option (ii) 60

X=60 is the correct answer of the given question