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A point P moves such that the tangents PT1 and PT2 from it to the hyperbola 4x2-9y2-36 aremutually perpendicular. Find the locus of P5. |
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Answer» It has something to do with the asymptotes of the hyperbola, even though they are not perpendicular. But it's a start. First put the equation into the form (x-h)²/a² - (y-k)²/b² = 1.4x² - 9y² = 36x²/9 - y²/4 = 1x²/3² - y²/2² = 1This is a horizontal hyperbola centered at the origin.The asymptotes are y = -2/3x and y = 2/3x. |
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