Explore topic-wise InterviewSolutions in Current Affairs.

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1.

2+333

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this answer is 2+333=335

335 this is right answer

335 is correct answer

335 is the correct answer to your question

335 is the right answer

answer of given question is 2+333=335

335 the answer is correct

335 is right ans for your Q

335 is the right answer

2.

4) (अंडे) X ——333 |

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(2^6 × 3^4/6³)² × (3³×2^5/3×8)³

(2^6 × 3^4/(2*3)³)²× (3³×2^5/3×2³)³

(2^(6-3)× 3^(4-3))²× (3^(3-1)×2^(5-3))³

=(2³× 3)²× (3²×2²)³

=(2³)^2*3²×(3²)^3*(2²)^3=2^6 * 3² * 3^6 * 2^6

=2^(6+6)* 3^(2+6)=2^12*3^8

3.

333-44

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Ans :- 333 - 44 = 289

4.

333- 8

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The answer is 333- 8= 325

5.

3+3313333.333....

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3(1+11+111+111.......11111ntimes)3/9(9+99+999+9999.......999ntimes)3/9(10-1+100-1+1000-1........)3/9(10+100+1000......-1-1-1-1....)simplify it

6.

given a, 4, d 2, S,14, find n and a.

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7.

given a. =4,a-2, s-14, find n and a.

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8.

(vii) given a,4, d-2, S,14, find n and a.

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an=a+(n-1)d=4or, a+(n-1)2=4or, a+2n-2=4or, a+2n=4+2or, a+2n=6or, a=6-2n=n/2[2a+(n-1)d]=-14or, n/2[2a+(n-1)2]=-14or, an+n(n-1)=-14or, (6-2n)n+n²-n=-14or, 6n-2n²+n²-n=-14or, -n²+5n=-14or, n²-5n=14or, n²-5n-14=0or, n²-7n+2n-14=0or, n(n-7)+2(n-7)=0or, (n-7)(n+2)=0either, n-7=0or, n=7or, n+2=0or, n=-2∵, n can not be negative ;∴, n=7∴, a=6-(2×7)=6-14=-8∴, n=7 and a=-8 Ans.

9.

LnTH

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(2/3)+(1/5)= ((2*5)+(1*3))/15= (10+3)/15=13/15

10.

f ( x ) = \frac { 7 ^ { 1 + \operatorname { ln } x } } { x ^ { \operatorname { ln } 7 } } \text { then } f ( 2018 ) =

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11.

Find two numbers such that one of them is five times the other and their differe200.

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12.

U-Like Mathematics-X434of an A.P. whose first term is 5 and common difference is 36isis 5. Find n24. The sum of n terms25. In figure, POR is a right angled triangle in which 090. IF OS-S, shnsum of 2n terms of another A.P. whose first term is 36 and common differePR2- 4PS2-3P2Or

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N/2(2*5+(n-1)36)=

2n/2(36*2+(2n-1)5

n/2(10+36n-36)=

n(72+10n-5)

n/2(36n-26)=

n(67+10n)

n/2*2(18n-13)=

n(67+10n)

n(18n-13)=

n(67+10n)

18n-13=67+10n so,8n=80 so,n=10

13.

) ~fam 40 LN gy %‘: )

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tan50= tan(40+10)

we have tan(a+b) = (tan a +tan b)/(1-tan a tan b)

= tan(40+10) = (tan40+ tan10)/(1-tan40tan10)

= tan50 = (tan40+ tan10)/(1-tan40tan10)

= tan50(1-tan40tan10)=tan40+ tan10

= tan50-tan50tan40tan10 = tan40+tan10

and tan50 = tan(90-40) = cot40

= tan50-cot40tan40tan10 = tan40+ tan10

= tan50-tan10 = tan40+ tan10

because cot40= 1/tan40

=tan50 = tan40+2tan10

14.

(реп) | рен)n|onLN

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15.

6./Rchan's school。s 5km775m away prom hi shome. Hew much distance did he covexining o school Pso miercluding sundayc inhis home dusng a Week1

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16.

Find the inverse: f(x)ln(-

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Taking exponent at the both sides

=> e^(f(x)) = x/(x-2)=> (x-2)/x =1/[e^f(x)]=> 1-2/x = 1/e^[f(x)]=> 2/x = 1-1/e^[f(x)]=> 2/x = [e^f(x)-1]/e^(f(x))=> x = 2e^f(x)/[e^f(x)-1]

replace x --- f-¹(x) and f(x)--- x

=> f-¹(x) = 2e^x/[e^x-1]

17.

If A(-3, 5), B (2,-7,ca,-8) and D(6,3) are the vertices of a quadrilateral ABfind its area.CBSE 2

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18.

Point P( x, y ) lies on the line segment AB where coordinates of A and B are (-2. 2) and(2,-4) respectively. Find x and y if AP AB.are (2, -27

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7AP-3AP= 3PB4AP= 3PBAP/PB= 3/4

19.

Swhe thefollowing equations: 5 --21

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thnks

20.

oy .““\N"J\'WJ;"IL Qe लि ०.ind {1 ४.0... P ५o,

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TSA OF A HEMISPHERE = 3πr²3πr²=4623×22/7×r²=46266/7r²=462r²=462×7/66r²=49r=√49=7

volume of hemisphere = 2/3πr³2/3×22/7×7×7×7=

718.6cm³

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21.

Attempt thefollowing:The ratio of two sides of a parallelogram is 7:4and its perimeter is 44 cm. Find the lengths of thesides of the parallelogram.

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22.

ind the differe1.

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Ans :- 5/8 - 1/8 = (5 - 1)/8 = 4/8 = 1/2

23.

वसा दव्वथशमथ्यल बन पव | ०o Life pancss o Hew 0pe Prowsses inteacemerted.2 e g e ks o

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The basic essential activities performed by an organism to withstand itslifeare called aslife processes. These include nutrition, respiration, circulation, excretion and reproduction. Organisms obtain energy from food to perform theselife processes which are essential for survival.

All of these processes are interrelated. No part of the body, from the smallest cell to a complete body system, works in isolation. All function together, in fine-tuned balance, for the well being of the individual and to maintain life.

24.

hew d

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25.

LnLn

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25

5×5 = 25. ............

26.

-14)2 x (21)3 = 75

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14×14×21×21×21÷7÷7÷7÷7÷7=108

108 iS the write answers

14×14×21×21×21÷7÷7÷7÷7÷7=2×2×3×3×3=108is correct answer

14×14×21×21×21÷7÷7÷7÷7÷72×2×3×3×3108 is the answer of this question

14×14×21×21×21÷7^5=108 the answer is correctLike my answer

14×14×21×21×21÷7÷7÷7÷7÷7= 2×2×3×3×3 =4×27=108

14×14×21×21×21÷7÷7÷7÷7÷7=108

27.

8.If sin 6-coso = -ando o90°, then the value of sin1312 -12

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a) is the correct answer

sinx+cosx=7/13......,(1)

let sinx-cosx=t...........(2)square and add both the equations(sinx+cosx)^2=49/169(sinx-cosx)^2=t^2................................................2=49/169+t^2t^2=289/169t=17/13sinx-cosx=17/13

28.

Find the smallest 5-digit number which is divisibie by 12 18 and 30,

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29.

7. Find the smallest 5 digit number which is divisible by 18, 24, and 32.

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Since 288 isdivisible by 18,24 and 32, 1152 is alsodivisibleby all thesenumbers. Therefore, 1152 is thesmallestfourdigit number divisible by 18,24 and 32.

30.

Filマno

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A. B = A1. B1+A2.B2+A3.B3

31.

Kalyan has a quadrilateral shapedthe diagonal of this farm is 220 m andoperpendiculars from both the edges is130 m, then find the area of field.3.andeng80 m

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Area of quadrilateral= Area of Upper Triangle + Area of Upper TriangleArea of Triangle is given by=(1/2) ×Height ×BaseSo Area of Upper Triangle=(1/2) ×80×220= 8800 m2Area of Lower Triangle=(1/2) ×130×220= 14300 m2

SoArea of the field = 8800 + 14300 = 23,100m2

32.

41 इ०0 5 > 300 -ue[I'o]sxlx_,‘— 159972‘6: फण्पा रतण्तत) के 25 28

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LHS = tan-1(root x) = 1/2 x 2tan-1(rootx) = 1/2 x cos-1((1- (root x)2)/(1 + (root x)2) ) = 1/2 cos-1( 1- x / 1+ x) = RHS.

33.

eek312 3y 67 ind TheValue 익 DX

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34.

edian of thefollowingind1. 2, 3, 5, 7, 9

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35.

Conce1. The three angles of a quadrilateralce The other two angies are equal1. FilEXERCISLgles of a quadrilateral are 659 55 and 130°. Find its fourth angle.m e 75 and 125. The other two angles ar

Answer»

x= 360-65+55+130x= 369-120+130x=369-250 x=119

the fourth angle is 119°

let 4th angle be XX+65+55+130=360X=360-250=110

119° is the measureof the forth angle

fourth angle=360-(65+55+130) =360-250 =110° ans

x=360-130+55+65 x=360-250=110 . Fourth angle

the fourth angle is 110°

36.

ind the value d1 a a1 2 3

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37.

tion a candidate is required to pass in 4 derent subjevets ln hew anya ih an examination,ways can be filis

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38.

what is the means of total, lateral and curved surface area of any 3d shapes

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Total surface area :Total surface area in that case means adding up the areas of all the surfaces.

Lateral surface area:Lateral surface area is finding the area of the sides of a three-dimensional geometric figure.

Curved surface area:curved surface area refers to area of only the curved part excluding it's base(s).

39.

POLfind the smallest number to which if 7 be added, the number obtained be exactly divisible by 25, 45,63, 84.

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the smallest number divisible by 25,24 is 600

then subtract 7 as he given in question

the number 8s 593

40.

10. Find the smallest number which when increasedby 11 is exactly divisible by 15, 20, 5411. id

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41.

find the smallest 5 digit number which is exactly divisible by 18,24 and 64.

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42.

1. Find the smallest number which is divisible exactly by 40, 60 and80

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240 is the smallest number which is divisible exactly by 40,60 and 80.

43.

If a*b denotes the larger of a and b andifaando are binary operations.

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5 ° 10 = (5*10) + 3

As 10 is larger than 5 we consider 10 .

5 ° 10 = (10) + 3 = 13

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44.

Prime factor of 12673:(i) 19 × 23 × 29(iii) 29 × 437(ii) 19 × 667(iv) 23 × 551

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45.

Find the smallest 5-digit number which is exactly divisible by 18, 24 and 64.

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46.

3) ind Re he HCF53 and Rio

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55 = 5×11 210 = 2×3×5×7 HCF means common factors of both the numbers HCF = 5

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47.

ind nuode2 3

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48.

urs a day must 4 pumps5. Three pumps working 8 hours a day can empty a tank in 2 days. How many howork to empty the tank in I day?davs will he travel 156 km

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Let the required number of working hours per day be x. More pumps, Less working hours per day (Indirect Proportion) Less days, More working hours per day (Indirect Proportion) Pumps 4 : 3 :: 8 : x Days 1 : 2 4 x 1 x x = 3 x 2 x = (3*2*8)/4X=12 days

49.

lawstIlmllpfind the value of Xandy7

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y= 85° ( Alternate angles) x= 85° ( corresponding angle) is the correct answer of the given question

y=85°.,x=85°Its right

y=85°,. x=85°

n parallel py = 85° is alternative anglen parallel mangle y = x corresponding anglex= 85°

50.

1109. दी गई आकृति में त्रिभुजों की संख्या कितनी| ?कवि |29 (४8) 27| (0) 29 D) 30] . B

Answer»

option b) 27 is the correct answer