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) ~fam 40 LN gy %‘: ) |
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Answer» tan50= tan(40+10) we have tan(a+b) = (tan a +tan b)/(1-tan a tan b) = tan(40+10) = (tan40+ tan10)/(1-tan40tan10) = tan50 = (tan40+ tan10)/(1-tan40tan10) = tan50(1-tan40tan10)=tan40+ tan10 = tan50-tan50tan40tan10 = tan40+tan10 and tan50 = tan(90-40) = cot40 = tan50-cot40tan40tan10 = tan40+ tan10 = tan50-tan10 = tan40+ tan10 because cot40= 1/tan40 =tan50 = tan40+2tan10 |
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