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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
12. The area of a square field is 65536 mº. Find thecost of fencing it at the rate of 5 per metre. |
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Answer» Perimeter = 4 x sidearea = side x side= 65536 = x^2side = √65536= 256 mtotal cost = 4x256x5 rupees area of sq field = 65536m/ss×s =65536 s= √65536s=256 m/s peri meter of square = 4 × side =4×256=1024cost of fencing =₹1024 ×5 =₹5120 |
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| 2. |
A cylindrical bucket, 32cm high and with ra-jdius of base 18cm, is filled with sand, Thisbucket is emptied on the ground and a coni-cal, heap of sand is formed. If the height ofthe concial heap is 24 cm, find the radiusand slant height of the heap. [HSLC 16]4. |
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| 3. |
surface area of the tOyA cylindrical bucket, 32cm high and with ra-ibucket is emptied on the ground and a coni-jdius of base 18cm, is filled with sand, Thiscal, heap of sand is formed. If the height ofthe concial heap is 24 cm, find the radiusand slant height of the heap. [HSLC 16) |
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| 4. |
6. The red colouring material in blood is called haemoglobin. It has 0.335% of iron.Calculate the molecular mass of haemoglobin. |
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| 5. |
8. Neeraj lent? 65536 for 2 years at 120% per annum, compounded annually. How much2more could he earn if the interest were compounded half-yearly? |
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Answer» thnx |
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| 6. |
8, Neeraj lent? 65536 for 2 years at 1202% per annum, compounded annually. How muchmore could he earn if the interest were compounded half-yearly? |
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| 7. |
A rectangular plot 200 m x 150 m has three3 m wide roads along the length of the ploton either side and one in the middle. On eitherside of the middle road there are shops.(a) Find the area covered by the shops.(b) Also, find the cost of reconstructing theroads at the rate of 2225 per m2. |
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Answer» Length of plot,a= 200Breadth of pot,x= 150Total area of plot = a *x= 200 * 150 = 30000m2Now Length of single road , l = length of plot = 200Breadth of single road , b = 3 (a)Area covered by 3 roads = 3 * l * b = 1800 m2Now Area covered by shops = Area covered by plot - Area covered by 3 roads = 30000 - 1800 = 28200 m2 (b)Now , rate of constructing roads = Rs. 225 / m2Thus total cost of constructing 3 roads = 225 * Area covered by 3 |
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| 8. |
A- 0 Find adi AIf A -Find adj |
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| 9. |
1621-2x 1-3x0) |
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| 10. |
x2-7x+ 12x 3= 0, then which of the following is the value of x?(1) 4 (2) 0 (3) -4 (4) 3 |
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Answer» x^2-7x+12 =x^2-3x-4x+12=x(x-3)-4(x-3)=(x-4)(x-3) Dividing it by (x-3) we are left with (x-4) So x-4=0 x=4 So option (1) |
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| 11. |
Find the volume of the Renisph.ve ,if its ro dius is ll2 cm |
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Answer» Volume of hemisphere =2/3 pi r^3here r =11.2 cmnow, volume= 2/3 * 3.14* 11.2*11.2*11.2=2940.98 cm ^3 |
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| 12. |
Find the volume of the Remisph-eve,, if its ra dius is 11-2 |
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Answer» Volume of hemisphere =2/3 pi r^3here r =11.2 cmnow, volume= 2/3 * 3.14* 11.2*11.2*11.2=2940.98 cm ^3 |
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| 13. |
Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Finddius of the base and (ii) total surface area of the cone.(i) ra |
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| 14. |
Find the volume of the fremisch-eve if its ro dius is 12 cm |
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Answer» Volume of hemisphere =2/3 pi r^3here r =11.2 cmnow, volume= 2/3 * 3.14* 11.2*11.2*11.2=2940.98 cm ^3 |
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| 15. |
1) If one angle of a cyclic quadrilateral is 75° then the oppositeangle is |
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Answer» 75 degree because opposite angles are equal if one angle of cyclic quadrilateral is 75° the opposite angle is (180°-75°)=105° 105 degree is right answer answer Is same please like me |
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| 16. |
onstruct a tangent to a circle of radius 4 cm from a point on the concentric circle ofdius 6 cm and measure its length. Also verify the measurement by actual calculation |
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| 17. |
Find the missing number in the series.1, 2, 2, 4, 16,?, 65536(NTSE Stage-i/ Haryanal 2013)(B) 256(A) 276(C) 198(D) 64 |
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Answer» 1*2=22*2=44*4=16then, 16*16 = 256 Hence, option (b) is correct. proof : 256*256 = 64436 we are hero of India and you are a silly boy |
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| 18. |
Q16. If the opposite angle of a parallelogram are (3x-5) and (S1-x)0 find the measure of each angle |
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| 19. |
(276) Perimeter of a rectangular garden is 360 m and its area is 8000 m2. Find the nlength of the garden and also find itsbreadth. (The length is greater than breadth) |
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| 20. |
( 2 x + y + 3 z ) ( 4 x ^ { 2 } + y ^ { 2 } + 9 y ^ { 2 } - 2 x y - 3 y z - 6 x z ) |
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Answer» in question it will be 9z square not 9ysquare |
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| 21. |
l: Find the eigen values and eigen vectors of the matrixration-2 -8-1240 1 |
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| 22. |
Date:_Page:TAGAstate wherther the given rationare equivalent.1:4 and 6:0 1 2 16 and 12:182 |
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Answer» 1 1:4 and 6:8are not equivalent2 2:6and 12:18are not equivalent 1:4 and 6:8 not equivalent 2:6 and 12:18 both are not ewuivalent |
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| 23. |
Fine six ration between 3 and 4 |
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| 24. |
find four ration no between 2/5and-2/5 |
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Answer» 2/5, 1/5, 0, -1/5, -2/5 |
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| 25. |
\left. \begin{array} { l } { 2 x - y + 3 z = 9 } \\ { x + y + z = 6 } \\ { x - y + z = 2 } \end{array} \right. |
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| 26. |
16. If the polynomials az +422 + 3% - 4 and z3 - 42+ a leave the same remainder whendivided by 2-3, then find the value of a. |
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| 27. |
\left. \begin{array} { l } { x + y + z = 6 } \\ { x + 2 y + 3 z = 14 } \\ { x + 4 y + 9 z = 36 } \end{array} \right. |
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| 28. |
4 x ^ { 5 } y z ^ { 2 } , 6 x ^ { 3 } y z ^ { 2 } \text { and } \frac { 1 } { 12 } x ^ { 2 } y ^ { 2 } z ^ { 3 } |
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| 29. |
A chord of a circle of radius 28cm subtends an angle of 45° at centre of the circle, find the area of minor segment |
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| 30. |
Find the volume of the hemieve if its ro dius is ll2 cm |
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Answer» volume of a hemisphere = 2/3 πr³ = 2/3 * 22/7 * 11.2 * 11.2 * 11.2 = 2,943.65 cm³ Like my answer if you find it useful! |
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| 31. |
the opposite angle of parellelogram are (3x+5)and (61-x) find the measures of four angle |
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Answer» the correct answer is 74 |
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| 32. |
EXERCISE 12.3hcostof 7 m of cloth isR 1470, find the cost of 5 m of cloth.lftheEkta earns? 3000 in 1 0 dayIf it has rained 276 mm in thfull week(s. How much will she earn i |
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Answer» Cost of 7 m of cloth is 1470Cost of 1 m of cloth = 1470/7Cost of 5 m of cloth is = 210×5 = 1050 |
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| 33. |
In Δ ABC, angle A= 45°and angle B = 70° find the smallest andgreatest side of triangle. |
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| 34. |
(i) 1000a3+276 |
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Answer» 1000a³+27b⁶ = (10a)³+(3b²)³ = a³+b³=(a+b)(a²₋ab₊b²) = (10a+3b²)(100a²-30ab²+9b⁴) |
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| 35. |
2 x + 9 \geq 3 x - 5 , x \in \{ 10,11,12,13,14,15 \} |
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| 36. |
Q25. If the polynomials az' +4z +3-4 and z 4+ a leave the same remainder when divided byz 3, find the value of a.t nte is douhle the angle subtended by same chord at |
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Answer» Let f(z) = az³+4z²+3z-4zero of the polynomial (z-3) = 3(since,z-3=0⇒z=3)So,replacing z by 3,f(3) = a(3)³+4(3)²+3(3)-4⇒f(3) = 27a+36+9-4⇒f(3) = 27a+41Let g(z) = z³-4z+azero of the polynomial (z-3) = 3(since,z-3=0⇒z=3)So,replacing z by 3,g(3) = (3)³-4(3)+a⇒g(3) = 27-12+a⇒g(3) = 15+aGiven that the two polynomials leaves same remainder when divided by z-3So,g(3)=f(3)⇒15+a=27a+41⇒15-41 = 27a - a⇒-26 = 26a⇒a=-1. Like my answer if you find it useful! |
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| 37. |
( a ) \geq 99 |
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Answer» thanks so much |
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| 38. |
\left. \begin{array} { l } { \text { Find the following product: } } \\ { ( 2 x - y + 3 z ) ( 4 x ^ { 2 } + y ^ { 2 } + 9 z ^ { 2 } + 2 x y + 3 y z - 6 x z ) } \end{array} \right. |
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Answer» (2x-y+3z)(4x^2+y^2+9z^2+2xy+3yz-6xz)=8x^3+2xy^2+18xz^2+4x^2y+6xyz-12x^2z-4x^2y-y^3-9yz^2-2xy^2-3y^2zt+6xyz+12x^2z+3y^2z+27z^3+6xyz+9yz^2-18xz^2=8x^3-y^3+27z^3+18xyz |
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| 39. |
Exercise 12.21. Three more than twice a number is equal to four less than the number. Find thenumberum Ä°s 46 Eind the integers |
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Answer» Let the number be x. So , According to the Question required equation is : 2x+3 = x-4 → 2x-x = -4 - 3 → x = -7 Answer : The number is -7. thanx |
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| 40. |
Four less than thrice a number m is 14. |
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Answer» 4 lesser than 3 times of m is = 3m-4 so, 3m-4 = 14=> 3m = 14+4 = 18=> m = 18/3 = 6 |
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| 41. |
Four less than thrice a number m is 14 |
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Answer» 4 lesser than 3 times of m is = 3m-4 so, 3m-4 = 14=> 3m = 14+4 = 18=> m = 18/3 = 6 |
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| 42. |
20.1. Three more than twice a number is equal to four less than the number. Find theniumber |
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| 43. |
Q 2. If the sides of a triangle are in the ration 12: 14: 25 and its perimeter is255 m, then find the greatest side of the triangle. |
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Answer» let X be common multiplehence12x+14x+25x=25551x=255X=5hence sides are12x=60m14x=70m25x=125m |
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| 44. |
40. A drinking glass is in the shape of frustum of cone of height 28cm. Is the diameter of ts two circular es6cm and 4cm. Find the capacity of the frustum. |
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| 45. |
14. In the given figure, find the area of the shaded region, if AC is the diameter ofeachisemi-circle on AC and BC is the radius of quadrant.fourangle28cmdius |
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Answer» Area of shaded region = area of semicircle of diameter BC - {area of quadrant of radius AB /AC - area of ∆ABC } So, area of semicircle of diameter BC = 1/2 πr² = 1/2 × 22/7 × 7√2 × 7√2 [ ∵ BC is hypotenuse of right angle ∆ABC , here AB = BC = 14 so, BC = 14√2 = 2 × radius ⇒ radius = 7√2 ]= 11 × 7 × 2 = 154 cm² area of quadrant of radius AB/AC = 1/4 πr² = 1/4 × 22/7 × 14 × 14 = 22 × 7 = 154 cm² area of ∆ABC = 1/2 height × base = 1/2 × 14 × 14 = 98 cm² Now, area of shaded region = 154cm² - { 154cm² - 98cm²} = 98cm² Hence, area of shaded region = 98 cm² |
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| 46. |
2 ^ { x } + 2 ^ { | x | } \geq 2 \sqrt { 2 } |
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Answer» let us assume |x| as first x and then -x so for x 2^x + 2^x ≥ 2√2 => 2^{x+1} ≥ 2^(3/2) => x+1 ≥ 3/2 so, x ≥ (3/2-1) that is x≥ 1/2 for -x 2^x + 2^-x ≥ 2^{3/2} for this the x belongs to( -∞, -1 ] answer is.. union ( -∞, -1 ] U [ 1/2,∞) |
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| 47. |
\left. \begin{array} { l } { x + y < 5 } \\ { y + 8 \geq 2 x } \\ { - 3 x + 2 y \geq - 6 } \\ { x > - 3 } \end{array} \right. |
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Answer» kindly mention the name of chapter and exercise |
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| 48. |
f it hasfull week (7 days)? Assume that the rain continues to fall at the same raterained276 mm in the last 3 days, how many cm of rain will fall in one3. I |
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| 49. |
2 x+y \geq 6,3 x+4 y \leq 12 |
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Answer» Area shaded in light blue represents the region. PLEASE HIT THE LIKE BUTTON |
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| 50. |
1440 - 448 y + 32 y ^ { 2 } \geq 0 |
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Answer» It's worong bro |
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