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2 ^ { x } + 2 ^ { | x | } \geq 2 \sqrt { 2 } |
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Answer» let us assume |x| as first x and then -x so for x 2^x + 2^x ≥ 2√2 => 2^{x+1} ≥ 2^(3/2) => x+1 ≥ 3/2 so, x ≥ (3/2-1) that is x≥ 1/2 for -x 2^x + 2^-x ≥ 2^{3/2} for this the x belongs to( -∞, -1 ] answer is.. union ( -∞, -1 ] U [ 1/2,∞) |
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