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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If the intercept of a line between the coordinate axesis divided by the point (-5, 4) in the ratio 1:2, thenfind the equation of the line.NCERT Exemplar) |
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| 2. |
(5) (198) A |
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Answer» 7762392 we can find it by multiplying 198with 198 and the product with 198 again.... 🔥 🔥 🔥 🔥 |
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| 3. |
portion of it between the axes iš divided yZ. Find the equation of the straight line which passes through the point (3, 2) and cutsoff positive intercepts on the x-axis and y-axis which are in the ratio 4: 3. |
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| 4. |
52. If (23x-1 + 10) * 76, thern X =यदि (23x-: +10) +7 = 6, तब x |
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| 5. |
16. Find the equation of the line which passes through the point (3, 4) and is such thathe portion of it intercepted between the axes is divided by the point in the ratio2 |
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| 6. |
6.Find the equation of a line passing through the point (7, 9) and which is suchportion of it between the axes is divided by the point in the ratio 3 1. |
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Answer» Wher z the answer |
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| 7. |
Find the equation of a line passing through the point (7, 9) and which is such that theportion of it between the axes is divided by the point in the ratio 3 1.6. |
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| 8. |
(23x)ă1340 |
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Answer» Given is staright line so sum og angles are 180° 23x + 134 = 180 23x = 180 - 134 = 46 x = 46/23 = 2 x = 2 |
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| 9. |
Q4. Find all zeroes of the polynomial 3x3 + 10x2 – 9x – 4, if one of its zeroes is 1. |
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Answer» All zeroes are 1 , -4 & -1/4 Step-by-step explanation:We are given with one Zero of polynomial 3x³ + 10x² - 9x - 4let say, p(x) = 3x³ + 10x² - 9x - 4 & zero = 1Thus,one factor of p(x) = ( x - 1 ) We get another factor of p(x) by dividing it with x - 1On division, quotient we get is 3x² + 13x + 4⇒p(x) = ( x - 1 ) ( 3x² + 13x + 4 )= ( x - 1 ) ( 3x² + 12x + x + 4 )= ( x - 1 ) [ 3x(x + 4) + (x + 4) ]= ( x - 1 ) ( x + 4 ) ( 3x + 1 )For zeroes put p(x) = 0⇒ ( x - 1 ) ( x + 4 ) ( 3x + 1 ) = 0x + 4 = 0& 3x + 1 = 0x = -4&x = -1/4Therefore,All zeroes are 1 , -4 & -1/4 |
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| 10. |
ABCD is a rectangle in which diagonal AC bisects Z A as well as C. Show thatO ABCD is a square (ii) diagonal BD bisects Z B as well as ZD.8. |
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| 11. |
. ABCD is a rectangle in which diagonal AC bisects Z A as well as 4 C. Show t() ABCD is a square (ii) diagonal BD bisects Z B as well asD |
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| 12. |
ei class:-, B,CExFind the valuas of이㈩3x (금)" |
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Answer» Please hit the like button if this helped you |
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| 13. |
23x 6 |
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Answer» 23 × 6 =138 is the answer |
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| 14. |
cinterceptedIf the coordinates of the middle point of the portion of a line intercepted vthe coordinate axes is (3, 2), then the equation of the line will be(A) 2x + 333.between12(B) 3x +2y12(C) 4x-3y-б(D) 5x-2vy |
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| 15. |
11. What real number should be subtracted from the polynomial 3x3 +10x2 -14x+ 9 so that(3x - 2) divides it exactly? |
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| 16. |
11. What real number should be subtracted from the polynomial 3x3 +10x2 -14x+ 9 so that(3x -2) divides it exactly? |
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| 17. |
3 If the co-ordinates of the middle pointof the portion of a line interceptedbetween coordinate axes (3,2), then theequation of the line will be [RPET 198(a) 2x + 3y 12(c) 4x-3y-6(b) 3x +2y 12(d) 5x-2y 10 |
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| 18. |
The projections of a directed line segment on thecoordinate axes are 12,4,3. The direction cosines of the lineare |
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| 19. |
9. Find the equation of the straight line passing through the origin and the mid-pointof the portion of the line ax + by + c # 0 intercepted between the axes. |
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| 20. |
O x=2+/3 20, रजत शानR R 2 ()23 (©)4 (d)2-3 |
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| 21. |
18. Pind the equation of the line paening through the point (3, 2) and the portion ofthe line intercepted between the axes ie divided by the point in the ratio 1:2 |
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| 22. |
XERRCISE 6.3he following system of inequalities graphically:23, y 2 2+y26, 3x + 4y-122. 3x+2y12, Х21,4. xty 4, 2x-y+ y2 8, x + 2y 2 10+4y S 60, x +3y 30, x 20, y20 |
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Answer» 2) |
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| 23. |
aryEI: ILy-2) &.1), find the valuesof s and y |
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Answer» thanx |
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| 24. |
8. ABCD is a rectangle in which diagonal AC bisects Z A as well as(G) ABCD is a square (ii) diagonal BD bisects 2 B as well as Z D.C. Show that |
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| 25. |
6.In the adjoining figure, it is given that CE || BA. ZBAC 80and ZECD-35°Find (i) <ACE.(ii)ACB,(iii)ABC.35* |
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| 26. |
8. ABCD is a rectangle in which diagonal AC bisectsA as well as 2 C(i) ABCD is a square (ii) diagonal BD bisects < B as well as < D. |
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| 27. |
ABCD is a rectangle in which diagonal AC bisects A as well as 2 C. Show that(i) ABCD is a square (ii) diagonal BD bisects Z B as well as D. |
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| 28. |
8) Find the number which is(i) 10% more than 80 (ii)!(iii) 25% less than 240 (iv) I |
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| 29. |
what comes next in the series? 2,3,6,10,17,28,? |
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Answer» 2+3 = 5 +1 = 6 3+6 = 9 +1 = 10...17+28 = 45 + 1 = 46 |
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| 30. |
What comes next in the series? 2, 3, 6, 10, 17,28, ? |
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Answer» Each number is a combination of the two before it + 1. 2 + 3 + 1 = 66 + 3 + 1 = 1010 + 6 + 1 = 1717 + 10 + 1 = 2828 + 17 + 1 = 46 thanks |
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| 31. |
If y = x,If y=x", then he is equal tothans equal todx |
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| 32. |
x^{3}+10 x^{2}+23 x+14 |
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| 33. |
solve for x: 2(2x-1/x+3)= 3(x+3/2x-1) given that x is not equal to -3 and x is not equal to 1/2. |
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Answer» Bas itna hi h |
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| 34. |
If a, b, c are in A.P., then prove that the straightline ax + by+c 0 will always pass through thepoint (1,-2) |
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Answer» a,b,c are in A.P then a+c=2b =>a−2b+c=0 =>ax+by+c=0by comparing we can see the cofficient of a and b it passes through(1,−2) |
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| 35. |
. If a, b, c are in harmonic progression, then straight line x/a+y/b+z/c always passes through a fixed pointi)(-1,-2)ii)(-1,2)iii)(1,-2)iv)(1,-1/2) |
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| 36. |
1. Ifa, b, c are in A.P., then prove that the straightline ax+ by+c 0 will always pass through thepoint (1,-2)8. |
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Answer» If a,b,c are in A.P thena + c = 2 b=> a − 2 b + c = 0=> ax + by + c = 0it passes through (1, − 2) |
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| 37. |
If the straight line ax + by+c-0 always passes through (1,-2)then a, b, c areIn A.P(b) In H.P.(d) of thesec) In G.P |
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| 38. |
142*x %2B x^3 - 23*x^2 - 120 |
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Answer» x^3 - 23x^2 + 142x - 120 = x^3 - x^2 - 22x^2 + 22x + 120x - 120 = x^2(x - 1) - 22x(x - 1) + 120(x - 1) = (x - 1)(x^2 - 22x + 120) = (x - 1)(x^2 - 12x - 10x + 120) = (x-1)(x(x - 12) - 10(x - 12)) = (x - 1)(x - 12)(x - 10) |
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| 39. |
23 X 220 X 444 X 2 |
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| 40. |
Find lim.Is it equal to lim. Is it equal to limthan?rl[x} :Greatcst integer less than or cqual to x |
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| 41. |
1.1Which of these sets are equal:(x, y,z},{z,y, z.x},{y, x, y,z),(y, z. x,y)?They are all equal. Order and repetition do not change a set. |
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Answer» {x,y,z} { z, y, z, x} = {x,y,z} {y, x, y, z} = {x,y,z} {y, z, x, y} = {x,y,z} Set have only distinct elements. Yes they all are equal |
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| 42. |
ABCD is a rhombus. Show that diagonal ACbisects Z A as well as Z C and diagonal BDbisects 2 B as well as Z D |
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| 43. |
ABCD is a kite in which AB - AD and BC DC.The kite is symmetrical about(a) the diagonal AC (b) the diagonal BD (c) none of these |
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| 44. |
6. It Ldx is equal t1 + xTAdx is equal to- |
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Answer» It is equal to1/x+1 dx= logx+x+c |
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| 45. |
Find the 10th term of series --, -1/2, 1/2, 3/2, ...... |
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| 46. |
. What comes next in the series?2, 3, 6, 10, 17, 28, ?(A) 38(B) 48(C) 46 (D) 42 |
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Answer» 2+3 = 5 +1 = 6 3+6 = 9 +1 = 10...17+28 = 45 + 1 = 46 |
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| 47. |
| 8 के asee of o ’“u-u"h“‘""25 21, 1L 2) B(33,5) dss 0 |
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Answer» Like if you find it useful |
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| 48. |
Find the 10th term of series-, -1/2, 1/2, 3/2, ...... |
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| 49. |
. u{> gl s, Lol i o) Aok B o) A AP Blan o fos Alok. . e- s =0o= % 5 4 S U S oy SR AN सहन, |
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Answer» Thank you so much |
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| 50. |
13. Factoriser'-23r-142 T |
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Answer» Hey mate,... -> X³ - x²- 22x2+22x+120x-120 -> x² (x-1) -22x(x-1) +120 (x-1) -> (x²-22x+120)(x-1) -> (x²-12x-10x+120)(x-1) -> {x (x-12)-10 (x-12)}(x-1) -> (x-10)(x-12)(x-1) Your answer... √√💯💯 Hope it helpsyou |
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