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142*x %2B x^3 - 23*x^2 - 120 |
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Answer» x^3 - 23x^2 + 142x - 120 = x^3 - x^2 - 22x^2 + 22x + 120x - 120 = x^2(x - 1) - 22x(x - 1) + 120(x - 1) = (x - 1)(x^2 - 22x + 120) = (x - 1)(x^2 - 12x - 10x + 120) = (x-1)(x(x - 12) - 10(x - 12)) = (x - 1)(x - 12)(x - 10) |
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