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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
85% of 720 |
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| 2. |
The numerator of a fraction is 2 less than the denominator. If 1 is added to both numerator anddenominator the sum of new and original fraction is 19. Find the original fraction.15 |
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Answer» thanks |
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| 3. |
find the value of kif (2-1) is a factor of443 4343_44 tk.Hurry guys, |
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Answer» Given:f(x)=4x^3+3x^2-4x+k=0(x-1)is a factor Thus x=1 f(1)=4(1)+3(1)-4(1)+k0=4+3-4+k k=-3 |
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| 4. |
the 00I0I |
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Answer» Explanation : 1 पैसा = 0.01 रुपये 10 पैसा = 10×0.01 = 0.1 रुपये Solution : 0.1 रुपये If you find this answer helpful then like it. |
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| 5. |
e of pand x = pv/7, then find the value ofp. |
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| 6. |
Change into like fraction |
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Answer» Step-by-step explanation: Conversion of Unlike Fractions to Like Fractions Step1. Find the LCM of the denominators of the given fractions. Step2. Find the quotient by dividing the LCM by denominator of the given fractions. Step3. Multiply the numerator by corresponding quotient. Example: Convert 2/9 and 5/6 to like fractions. Step 1: LCM of 9 and 6 = 2 x 3 x 3 = 18 2 9,6 3 9,3 3 3,1
1,1 Now, we have to adjust the numerators to the LCM =18 Step 2: Convert 2/9 Numerator to be multiplied by (18/9 = 2) Changed numerator = 2 x 2 = 4 2/9 (old fraction) = 4/18 (new fraction) Convert 5/6 Numerator to be multiplied by (18/6 = 3) Changed numerator = 5 x 3 = 15 5/6 (old fraction) = 15/18 (new fraction) Therefore; 4/18 and 15/18 are the required like fractions. |
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| 7. |
On reducing the value of a chair by 6% it becomes(b)17.658, The original value of the chair is(a)750720(c) 500(d)700 |
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Answer» let original price be xx-6÷100×x=65894x÷100=65894x=65800x=65800÷94x=700 |
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| 8. |
he numerator and denominator of a fraction arein the ratio of 2: 3. If 6 is substracted from thenumerator, the result is a fraction that has a value 2/3of the original fraction. The numerator of theoriginal fraction is: |
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| 9. |
OrPind the relation xeguidistene feom the plns (3, 6) and (3. 4)beiveen x and y such that the point (xBAKDE |
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| 10. |
el & e(ni) 135° |
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Answer» 135° = π /180*135°= 3π/4radian equivalent thanks |
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| 11. |
Worksheet-44. Find the square as20409 |
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Answer» find its answer 347. |
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| 12. |
Which of the following pairs represent the same rational number?-7 3-16 , 20-2 2(2025-24-5 150 1 and(iii)_anu 3- an3(v) and12(V) and(vi) รทand20-5 5-99vi)and |
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| 13. |
6Sin 20°-8Sin^3 20° |
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Answer» 6 ×0.34 - 8 (0.34)^3=2.04 - 8×(0.34)^3=2.04 - 8×0.04=2.04 - 0.32 =1.72 |
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| 14. |
6 Sin 20°-8 Sin^3 20°=? |
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| 15. |
Tuniisametationalnumber?andand20(in) and-33-12andS24-S 153 20(vi)÷andaiethe fallowingrmcal curzhers in the |
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| 16. |
5^{2}+6^{2}+7^{2}+\ldots+20^{2} |
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Answer» 2840 and |
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| 17. |
2, 5.39. 2. 20 2.ŕ¤ŕ¤ž |
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Answer» 2, 5, 9, ? , 20, 27 Observe 2 2 + 3 = 5 5 + 4 = 9 9 + 5 = 14 14 + 6 = 20 20 + 7 = 27 So, ? = 14 |
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| 18. |
[ 20 - 2 \{ 5 + ( - 12 ) \} \times \{ 2 ( 5 - 2 - 9 ) \} ] |
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| 19. |
Find the base of a triangle whose area is 220 cm2 and height is 11cm. |
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| 20. |
9. Find the height of a triangle whose area is 224 mand base is 28 m. |
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| 21. |
Mental Maths1. One of the equal angles of an isosceles triangle is 50°. Find all the angles of this triangle. |
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| 22. |
find the altitude of a triangle whose area is 784 Sq. cm and base is 32cm |
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Answer» Area of triangle = 1/2*base*altitude784 = (1/2)*32*altitudeAltitude = 784/16 = 49 cm Thank u |
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| 23. |
12) Ifsin (3-20°)# cos (3y+20") then, what s the value of (x +y)? |
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| 24. |
2.Find the altitude of a triangle whose area is 42 cm2 and base is 12 cm |
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| 25. |
3*y^2 - 20=-2*y^2 %2B 160 |
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Answer» 3y^2-20=160-2y^23y^2+2y^2=160+205y^2=180y^2=36y=+-6y=6,y=-6 |
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| 26. |
1/2 %2B 4/15 %2B 3/10 |
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Answer» first take lcm in denominator in this case it would be 30.... 8+9+15/30=32/30 the answer to this question is 16/15 16/15 is the correct answer of the given question a+vf+−12equals−12+a+vfOR−0.5+a+vf |
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| 27. |
-2/5 %2B 3/10 %2B 4/7 |
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| 28. |
16.Simplify : - 3 (x + 5) + 20 = - 10 (x - 3) + 4 |
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Answer» (a) 22/13 my Answer right |
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| 29. |
what is the correct formula of F° change into C°? |
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Answer» (°F − 32) × (5/9) = °C (°F − 32) × (5/9) = °C (°F − 32) × (5/9) = °C all other answers are for Kelvin to change into degree F°-32*5/9=C° is correct answer °C=°F-32×5 divide by 9 |
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| 30. |
Worksheet 4Expand the following:1. (x- 2y 3z)24. (3a - 5b-7c)27. (1 + 2x-3y)2 |
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| 31. |
e 100 m(d)5012 m(a) 15u m11·The area of an equilateral triangle is 413 cm2. Its perimeter is |
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| 32. |
3 + 20 × 3 |
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Answer» 63 is the answer multiply 20 by 3 answer 60and 60 plus 3= 63 Using BODMAS3+20×3=3+(20×3)=3+60=63Answer=63 Right answer is 63.... =3+20×3=3+60=63understand 63 is the correct answer 63 is the answer of the following |
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| 33. |
2. Find the altitude of a triangle whose area is 42 cm2 and base is 12 cm |
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| 34. |
Date:Worksheet 4Mental Maths1. Fill in the blanks.a. 1 followed by 7 zeroes is oneb. 7 millions =millions + 30 ten thousandsC. 1 lakh =thousands |
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Answer» 1 lakh = 100 thousand a = one crore b= ??? c=thousand a=1 croreb= 6.7 millionc.100 A.10000000C. 100 thousand |
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| 35. |
1*3+2*3+3*3+........+20*3 |
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Answer» remove 3 as common3(1+2+3+..20)now 1+2+..20 forms an aphenceS=n/2(a+l)dS=20/2(1+20)*1S=10(21)=210hence total sum will be 210*3=630 |
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| 36. |
10*x^2 %2B 20*x %2B 10=0 |
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Answer» 10x²+20x+10=0sum =20 ; product=100numbers=10 ,10 10x²+10x+10x+10=010x(x+1)+10(x+1)=0(10x+10)(x+1)=0x=-10/10=-1or x=-1 |
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| 37. |
12/((-10)) %2B (-3)/10 %2B 14/10 |
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Answer» -1/10 is the correct answer of the given question -1/10 is right answer..... |
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| 38. |
23(c) 5203a)23 |
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| 39. |
3 x ^ { 2 } - 4 x + \frac { 20 } { 3 } = 0 |
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| 40. |
( x ^ { a + b } ) ^ { a - b } \times ( x ^ { b + c } ) ^ { b - c } \times ( x ^ { c + a } ) ^ { c - a } = 1 |
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Answer» x^(a^2-b^2)×x^(b^2-c^2)×x^(c^2-a^2)=x^(a^2-b^2+b^2-c^2+c^2-a^2)=x^0=1 |
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| 41. |
4 \left( \cos ^ { 3 } 10 + \sin ^ { 3 } 20 ^ { \circ } \right) = 3 \left( \cos 10 ^ { \circ } + \sin 20 ^ { \circ } \right) |
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| 42. |
9. From the adjoining figure, find(0) the area of AABCa lengéh of BCthe length of altitude from A to BC.4 cmA 3cm |
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| 43. |
D) 15U cm2212. The sides of a triangle are 11 cm, 15 cmand 16 cm. What is the measure of thealtitude to the largest side? |
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| 44. |
Worksheet 4The area of a triangle is 90 cm2. If its base is 15 cm, find its altitude.08 dlm2 and altitude is 8 cm. |
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Answer» 90 =1/2(15*x)180 =15*xx=180 /15x=12 |
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| 45. |
15. The base of an isosceles triangle is 18 cm and its area is 108 cm2. Find its perimeter. |
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Answer» If you find this solution helpful, Please like it. |
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| 46. |
a^4 - 11*a^2 %2B 10 |
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Answer» a^4 - 11a^2 +10=a^4 - 10a^2 - a^2 +10=a^2 ( a^2 - 10) -1(a^2 -10)=(a^2-1)(a^2-10)=(a-1)(a+1)(a-√10)(a+√10) |
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| 47. |
3*x - y/11 - 7/11 %2B 2=10 |
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Answer» 33x-y+7+22=110; 33x-y=110-30=80,; 14y+x+11=70; 14y+x=70-11=59; 14y+×=59; 33x-y=80; |
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| 48. |
The length of the shadow of a tower standing on the level plane is found to be 2x m longer when thesun s altitude is 30° than when it was 450 Prove that the height of the tower is x(v0. |
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| 49. |
(-5*sqrt(3) %2B 10*sqrt(6))/(-3*sqrt(7) %2B 11*sqrt(2)) |
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| 50. |
11/8 - 15/8 - 3/2 %2B 10 |
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Answer» 10 - 2 3/4 - 3 5/8 + 11/8 = 10 - 11/4 - 29/8 + 11/8 = (80 - 22 - 29 + 11)/8 = (91 - 51)/8 = 40/8 = 5 |
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