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( x ^ { a + b } ) ^ { a - b } \times ( x ^ { b + c } ) ^ { b - c } \times ( x ^ { c + a } ) ^ { c - a } = 1 |
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Answer» x^(a^2-b^2)×x^(b^2-c^2)×x^(c^2-a^2)=x^(a^2-b^2+b^2-c^2+c^2-a^2)=x^0=1 |
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