Explore topic-wise InterviewSolutions in Current Affairs.

seven is the answer to the question.

c) is the right answer of the following

c is the correct option

c option is right answer

Let total displacement be 3x and it's 1/3rd part is x, x and x

average velocity = total displacement /total time

ER. RAVI KUMAR ROY

For T1(time ) =displacement/time =x/2sec

T2 = x/3 sec

T3 = x/6 sec

Total time = x/2+x/3+x/6

=6x/x

=X(total time)

Now,average velocity = 3x/x= 3 m/s ANS...

c is the correct answer

c is the correct answer

inner circumference = 220

2 π r = 220

r *2* 22 = 220 * 7

r = 35 m [ inner radius ]

inner radius , r₁ = 35 mouter radius , r₂ = 35 + 7 = 42 m

outer circumference = 2 π r ₂

= 2 * ( 22 / 7 ) * 42 = 264 m

Cost of fencing = Rs 2 * 264 = Rs 528

Let the side of the larger square be x.Let the side of the smaller square be y.According to the question, x2 + y2 = 468 --------- (1)Perimeters of the squares = 4x and 4y.⇒ 4x - 4y = 24⇒ x– y = 6⇒ x= 6 + yx2 + y2 = 468Substituting the value of x in equation (1)⇒ (6+y)2 + y2 = 468⇒ 2y2 + 12y + 36 = 468⇒ y2 + 6y + 18 = 234⇒ y2 + 6y - 216 = 0⇒ (y – 12)(y + 18) = 0⇒ y = 12 or -18Since y denotes a length, it cannot be negative.∴ y = 12⇒ x = (12 + 6) = 18 m

∴ Sides of the squares are 18 m and 12 m.

(B) We know that, when we increases the speed, then the time taken by vehicle decreases.Hence, speed and time taken vary inversely with each other.So, option (B) is correct.

So2/5*35/6+1/3*(12/11)70/30+12/332.33+0.362.69

They are in direct variation

wrong hai

this is inverse variation 😠👎

By euclid's division algorithm225=135×1+90135=90×1+4590=45×2+0hence the hcf is 45

Let's B alone take x days to finish the work.B’s 1 days work = 1/x

A alone can finish the work in = x - 10A’s 1 days work= 1/(x-10)

Given: A and B together can finish the same work in 12 days.(A and B)'s 1 days work = 1/12

A’s 1 days work + B’s 1 days work = 1/x + 1/(x-10)

ATQ1/x + 1/(x-10) = 1/12(x-10) + x / x(x-10) = 1/12x-10 + x / x² -10x = 1/122x -10 / x² -10x = 1/1212(2x -10) = x² -10x24x -120 = x² -10xx² -10x -24x +120= 0x² -34x +120= 0x² 30x -4x +120= 0x( x -30) -4(x -30)= 0(x-30)(x-4)= 0(x-30) = 0 or (x-4)= 0

x = 30 or x= 4 The value of x cannot be less than 10, so x= 30

Hence, the time taken by B to finish the work in 30 days.

Euclid’s division Lemma

Given positive integers a and b, there exist unique integers q and r satisfying

a = bq + r, 0 ≤ r < b.

2. 140=2*7070=2*3535=7*5Therefore 140=2*2*5*7

3. 135 and 225Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45.

Like my answer if you find it useful!

A composite 4,6probability =2/6=1/3Number divisible by 3 =3,6probability =3/6=1/2

the sample spaces of rolling a dice is {1,2,3,4,5,6}

so, probability of a) getting 5 = 1/6 b) getting 7 = 0/6 c) getting 3 = 1/6

Hence, a common divisor of a and b is a common divisor of b and r. EuclidsDivision Algorithmis a technique to compute the Highest Common Factor (HCF) of two given positive integers. Recall that the HCF of two positive integers a and b is the largest positive integer d that divides both a and b.

By euclid's division algorithm225=135×1+90135=90×1+4590=45×2+0hence the hcf is 45

Awsm 😎

3÷7of mean ×and2÷5then3÷7×2÷5=6÷35

6/35 is correct answer as we multiply numerators and denominators

6/35 is the correct answer of this question

3/7of2/5= 3/7*2/5 =6/35

3/8 is greater than 8/35 is the correct answer of the given question

So2/5*35/6+1/3*(12/11)70/30+12/332.33+0.362.69answer

so2/5*35/6+1/3*(12/11)70/30+12/332.33+0.362.69

4km/hr. may be the answer.

the average speed = 6+3/2 =4.5therefore 4.5 is the correct answer to this question

4km/hr. may be the correct answer

his average speed = (6+3)/2 = 9/2 = 4.5 km/hr (ANS)

what the hell is going on, why my answers gets an issue mark, would you be able to explain it..

(C) 4.5 km/hr (answer)

AVG.speed 6+3/2=4.5km/hr

average speed=6+3/2=4.5,

Total speed = 6+3m/sec= 9m/secTotal time = 2 hr.So, average speed = 9/2 m/sec= 4.5 m/sec AnsSo, option (C) is correct Ans.

4.5 is the right answer

4.5 is the correct answer

the average speed = 6+3/2 =4.5therefore 4.5 is the correct answer to this question

correct answer is (c)

the average speed = 6+3/2 = 4.5therefore 4.5 is the correct answer to this question

his average speed is 4.5

thank u

b. the area of a square is = 49 sq.meter the side length of square is=√49 = 7 meter

c. a cube has edge length= 3 volume = l×b×h = 3×3×3 = 27

c is correct answer

.

c is the correct answer

Total student = 25Student taken maths = 12Students taken only maths = 8So total student taken only biology = 13Students taken both maths and biology = 4 As we know out of 12 maths student 8 are only studing maths Therefore 4 students are those who study both maths and biology.

A) Ethanol can be converted to ethene in presence of concentrated sulphuric acid. It is called as dehydration reaction.CH​3-CH2-OH → (Concentrated H2SO4) CH2=CH2 + H2O

Number of days in the month of January in a leap or non-leap year = 31There are four complete weeks in the month of January.There are three more extra days in the month.If the month starts on Saturday or Sunday or Monday, there are 5 Mondays in the month of January.So, the probability of getting 5 Mondays in the month of January (or any month with 31 days) = 3/7.

plz give me a call

Like my answer if you find it useful!

the price of scooter will be 24000

purchased =₹60000value decreased every year =20%price after 2 years =?value decreased first year

60000×20 ------------------- = 1200 =60000-1200 100 =48000 48000×20----------------. = 9600 =48000-9600 100.

=38400🅰️ns

For first yearI = P*R*T/100I = 6000*12*1/100 = 720

A = 6000+720= 6720

Principal for second year = 6720-3000=3720

For second year

I = 3720*12*1/100 = 446.4

A = 3720+446.4

Amount owe after second payment = 3720 - 446.4 = Rs 3273.6

Sorry wrong calculation

Total amount after second year= 3720 + 446.4=4166.4

Amount owe after second repayment= 4166.4 - 3000= Rs 1166.4