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Answer»

Euclid’s division Lemma

Given positive integers a and b, there exist unique integers q and r satisfying

a = bq + r, 0 ≤ r < b.

2. 140=2*7070=2*3535=7*5Therefore 140=2*2*5*7

3. 135 and 225Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45.

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