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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A fractory produces 6985 screws per day how many screws will it produce 358 days |
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Answer» the factory will produce 2500630 screws in 358 days 6985×358=2689225 right |
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| 2. |
a factory produces 6985 screws per day. how many screws will it produce in 358 days |
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Answer» the answer will be 6985*358 6985*358 is the right answer of the following no of screws produced by the factory in 358 days=6958×358=2500630 |
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| 3. |
22. In the given figure, m and n are two plane8mirrors perpendicular to each other. Showthat the incident ray CA is parallel to thereflected ray BD.IS2 |
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Answer» que solve |
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| 4. |
SlueIL CUIUulu U2J!18. A factory produces 6985 screws per day. How many screws will it produce in 358 days?1Thell BTO 10 |
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| 5. |
18. A factory produces 6985 screws per day. How many screws will it produce in 358 days?wwwth How much money will he same in 13 years |
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| 6. |
11. A machine produces 2825 screws in a dayWhich of the following is the best estimateof the number of screws to the nearestthousands?(A) 3500(C) 3000(B) 5000(D) 2900 |
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Answer» Nearest thousand = 3000 |
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| 7. |
DOmaking 140 revolutions per minute. If the dig such that the wheels of the cycle areIS 60 cm, calculate the speed per hour withwhich the boy is cycling. |
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| 8. |
. The cost of a chair is Rs 1485. HOw luel wll 100 luHow much money was collected from 1786 students of a school for a charity show if eachstudent contributes Rs 625?ll it nroduce in 358 days? |
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| 9. |
Fig. 6.36. In Fig. 6.33, PQ and RS are two mirrors placedparallel to each other. An incident ray AB strikesthe mirror PQ at B, the reflected ray moves alongthe path BC and strikes the mirror RS at C andagain reflects back along CD. Prove thatAB II CD.ACSFig. 6.33 |
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| 10. |
For what angle between the two plane mirrors, a light ray, after reflection once fromeach of the mirrors becomes parallel to the incident ray direction ?10. |
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| 11. |
division about 700 15 |
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Answer» 140/3 is the correct answer 140/3 is the correct answer |
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| 12. |
sen fgure, I and m are two plane mirrors perpendicularthe given figuI ncident ray CA is parallel to reflected ray BD.how that2 |
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| 13. |
In the given figure, m and n are two planemirrors perpendicular to each other. Showthat the incident ray CA is parallel to thereflected ray BD.2 |
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| 14. |
m and n are two plane mirrorsperpendicular to each other. Show that incident rayQ. 1. Infigure,CA is parallel to neflected ray BD.8rm㪠|
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| 15. |
22. In the given figure, m and n are two planemirrors perpendicular to each other. Showthat the incident ray CA is parallel to thereflected ray BD. |
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| 16. |
A35 cm line segment is dividedbulbs delA factory produces electric bulbs. If 1 out of everyproduces 630 bulbs per day find the number of defective bulbsthe price of a pencil to that of a ball pes if penis |
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| 17. |
IHint i Length of successive semieireles isyrespectively19, 200 logs are stacked in the following manne20 logs in the botom row, 19 in the tethe 200 logsIn how many rows are18 in the row next to it and (see igand how many logs are in the top rowld soon (see Fig 5 5) İn how many rows are the 20() 1Fig. 5.5 |
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| 18. |
U W luul uays.Shekhar is a famous cricket player. He has so far scored 6980 runs in test matchesHe wishes to complete 10,000 runs. How many more runs does he need?In an election the31 |
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Answer» runs he needs = 10000 - 6980=3020 runs he needs = 10000 - 6980=3020 needed= 10000-6980=3020 runs he needed -10000-6980=3020 3020 runs more ..... 3020is correct answer |
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| 19. |
19. Aniali had 12 pencils. Her mother gave her 5 more pencils. Howmany nencils she have now?Low many |
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Answer» 17 pencils hai anjali ke pas Anjali have 12 pencilsmother gave her 5 more pencilsthen she have now 12 + 5 = 17 pencils. |
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| 20. |
How many triangles are there in the given figure ?(2) 19(3) 20(4)21 |
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Answer» Total number of triangles in given figure are 18. Therefore, (1) is correct option option 1 |
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| 21. |
. How many terms of the AP 20 +19+. must be taken so thattheir sum is 300. |
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Answer» How many terms of the A. P. 20 , 19 1\3 , 18 2\3 must be taken so that there sum is 300 |
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| 22. |
The simple interest on a sum of moneywill be Rs. 225 after 3 years. In the next 5years principal becomes 3 times. What wllbe the total interest at the end of the 8thyear? |
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Answer» Let the principal = PA/C to question, the simple interest on assume of money will be 225 after 3 years so, in 1 year simple interest will be 225/3 = 75rs. now, again question said " in the next 5 years principal becomes 3 times "e.g., S.I of 5 years + P = 3P S.I of 5 years = 2PS.I of 1 year × 5 = 2P75 × 5 = 2P 2P = 375 => P = 375/2 rs. now, total interest at the end of the 8 years = S.I of 1 years × 8 + P = 75 × 8 + 375/2 = 600 + 187.5 =787.5 rs. |
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| 23. |
So, Wll8.6 :The diagonals of a parallelogramofaParallelogram-bisect each other. |
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| 24. |
mary deinalplaces wll he de na6.eeina23terminate?24 x53 |
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Answer» 23/2⁴×5³23/(2×5)³ ×223/10³ × 20.0115after four decimal expansion terminate |
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| 25. |
500+700 |
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Answer» If we add this these 500+700=1200 we get this the answer is 500+700=1200 The answer 500 + 700 = 1200 500+200= 1200 if we added 1200 is correct answer. 1200 is the best answer 1200 the correct answer of the given question |
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| 26. |
At what rate per cent per annum wll a sum of money double ltself in eight ye6. |
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| 27. |
| पड (न) ही 2. (2- व.)N3 () - लछ(१5० | |
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| 28. |
-2098 - 12600 %2B 700*(20493/99) |
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Answer» 207*700-12600-2098144900-10502=134398 207*700-12600-2098144900-10502=134398there fore ans is 134398 144900-12600-2098130202 =207*700-70*180-2098=144900-12600-2098=144900-14698=130202 200*700- 12600- 2098 144900-10502=134398 207*700-12600-2098144900-10502134398 130202 First solve ÷ then * then + then - 130,202 is the correct answer 207*700 12600-2098144900-10502=134398 |
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| 29. |
Factorise the following expressions.G) a² + Sa + 16 (i) p²-10 p +25 |
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Answer» t it has it had become (a+4) |
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| 30. |
unmuni profit of the factory when it works at full capacity4.A manufacturer produces nuts and bolts. It takes 1 hour of work on machine Aand 3 hours on machine B to produce a package of nuts. It takes 3 hours onmachine A and 1 hour on machine B to produce a package of bolts. He earns aprofit of Rs17.50 per package on nuts and Rs 7.00 per package on bolts. Howmany packages of each should be produced each day so as to maximise hisprofit, if he operates his machines for at the most 12 hours a day? |
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Answer» 1day is 6 hours of my |
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| 31. |
6. A factory produces 25683 bolts a day. How many bolts will it produce in a leap year if therwill be 85 holidays in the year |
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Answer» a leap year has 366 daysnow there are 85 holidayshence 366-85=381 dayshence number of bolts=35683*381=10,026,923 7217923 |
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| 32. |
POINTS3. A factory produces 25 683 bolts a day. How many bolts will it produce in a leapyear if there will be 85 holidays in the year? |
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Answer» the days in leap year is 366 85 holidays so 281 days no of bolts produced in 1 leap year 281×25683 281×25683 is the right answer |
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| 33. |
ăsce |
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Answer» Let sec^-1(2/√3) = ∅ = π/6=> sec∅ = 2/√3 => cos∅ = 3/√2 or ∅ = cos^-1(3/√2) = sin^-1(1/2) = cosec^-1(2) = tan^-1(1/√3) = cot^-1(√3) |
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| 34. |
न करनी. “Lh ही कक. क ८2 s et कि.4-८ ० Sce था. कि.o |
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Answer» hit like if you find it useful thanks a lot mam |
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| 35. |
28. गदि sin 4 =c0s A, तो 2 tan 4 -2 sce- 4 -5 के मान ज्ञात कीजिए। |
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Answer» Sin A = cos A when A= 45°so2 tan^2 A - 2 sec^ 2 A +52(tan ^ 2 45° ) - 2 sec^2 45° +52(1)-2(√2)^2 + 52 - 2(2) +52-4+5-2+5=3 |
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| 36. |
45960931)sin AN32tan At altehe ecosve A Not defiued2lesce ACot A Not defined |
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Answer» BBC difficult also da idk Ka to is still map lakes bowl ya so is smaller isthmus week is so idk Ka chi Kung jug KDDI Panama subsidy Paola Palau pal pal all pa pa pa app app pa app pa app mailbox |
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| 37. |
Factorise p? - pq6. |
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| 38. |
(c)2rrh sq.units(d) none of t47. If the height and the radius of a cone are doubled, the volume of the cone becomes(a) 8 times(b) 6 times(c) 4 times(d) none of t |
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Answer» photo sahi se nahi dikhraha |
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| 39. |
A committee of two persons is selected from two men and two womon. What is theprobability that the committee will have,(i) no man ?(ii) one man?3S) |
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| 40. |
cach oneof the following angles as right, straight, acute, obtuse or reflex: |
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| 41. |
A committee of 7 has to be formed from 9 boys and 4 girls.In how many days can this be done when the committee consists of(i) exactly 3 girls?(ii) at least 3 girls? |
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| 42. |
1. A and B do a work together in 24 days and B and C do the same worktogether in 18 days. Similarly A and C do that work together in 12 days. Tell, in howmany days A will flnish alone that work. |
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Answer» (A+ B)’s 1 day’s work = 1/24(B + C)’s 1 day’s work = 1/18(C + A)’s 1 day’s work = 1/12On adding,2(A + B + C)’s 1 day’s work = 1/24 + 1/18 + 1/12 = (3 + 4 + 6)/72 = 13/72 ∴ (A + B + C)’s 1 day’s work = 13/144∴ A will finish alone this work in= 13/144 - 1/18= (13 - 8)/144= 5/144 A alone will finish work in 144/5 = 28.8 days |
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| 43. |
3ay68/A and B together can do awork in 10 days. B and C to-gether can do the same workin 6 days. A and C togethercan do the work in 12 days.Then A, B and C together cando the work in |
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| 44. |
Write the following sets in the set-builder form:(6) (3,6,9, 12)(iv) 12, 4, 6,. () (1,4,9,. . . 100)(ii){2,4,8,16,32) |
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| 45. |
tiveA can do a piece of work 15 days.A and B complete the work togetherand were paid 2 56 and 272 respectHow many days mast they have takento complete the work together? |
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Answer» he lo helo helo heli helihsgjddjdhbdvgxgdhdh agar A ne Woh Kam Kar liya toh B kyu karega fir se |
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| 46. |
27) A is 50% as efficient as B. C does half of the work done by A and B together ircadoes the work in 40 days, then A, B and C together can do the work in |
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Answer» C does half work of A & BWork done by C in a day is 1/40C = 1/(A+B) 21/40 = 1/(A+B) 22/40 = 1/A+B1/A+B = 1/20So A & B together take 20 days to complete a workNow A, B & C together take1/A + 1/B +1/C= 1/20 + 1/40= 3/40= 40/3 days= 13.33 days |
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| 47. |
Time and Work1613.A can do a piece of work in 12 days, and B can do the same work in 20 days. They work togetherEx,for 3 days and then 4 goes away. In how many days will B finish the work ?Inl day A and B together can do (1+1) of the work. ie., 2 of the work.1 1 5+3 |
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Answer» in question A can do the work in 12 days not 20 B can do the same work in 20 days not 15 read the question sometimes this types of mistakes happen |
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| 48. |
A can complete a work in 24 days and B can complete the same work in18 days. A and B started doing the work together. After 4 days, A discontinuedworking. How many days would the work take to be completed?6 |
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Answer» A can complete work in 24 days so in 1 day A can do 1/24 of work.B can complete work in 18 days so in 1 day B can do 1/18 work.now up to 4 days they are working together.so total.work done = 4(1/24+1/18)=4(3+4)/72=28/72so still 44/72 work incomplete.so no of days B will take to complete work is=(44/72)/(1/18)=(44*18)/72= 11 days. |
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| 49. |
FactoriseP power 3 + 27 |
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| 50. |
Q.1In the curve (sce figure)haif tevenghisA B(1)AB2)BDE)DE(4AE |
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Answer» (2) BDBD = BC + CDBC and CD are quarter of a wavelength and they add to half of a wavelength.AC and CE is half wavelength. But they are not given in the options. One wavelength is AE.AB and DE is quarter of wavelength. |
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