ăsce – InterviewSolution

1.

ăsce

Answer»

Let sec^-1(2/√3) = ∅ = π/6=> sec∅ = 2/√3 => cos∅ = 3/√2

or ∅ = cos^-1(3/√2) = sin^-1(1/2) = cosec^-1(2) = tan^-1(1/√3) = cot^-1(√3)

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