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As(a-b)^2= a^2+b^2-2absox^2y^2+y^2z^2-2xy^2z

=0.00032 this is the answer

0.00032 is the correct answer

Answer will be 0.00032

the answer is 0.00032

0.00032 the correct answer of the given question

32/100000=0.00032 is the correct answer

=0.00032 is the correct answer

the question is not clear

1/

we can write as2²+x ² in denominator and then use the formula for1/ a²+x²

Here i hope u will understood thank u

it's right answer is π/4

yadi eak sanku ki uchai and sautan kramsh :15cm and 500π cm3 hai tab sanku ke aadhar ki tirijya gyat kijiye

π/8 is the currect answer

your answer is pai by 8

no this is wrong

let y = sin x/(1-cos x)

we need to find t such that

tan t = y ..1

we know sin x = 2 sin x/2 cos x/2cos x = 1- 2 sin^2 x/2so 1-cos x = 2 sin ^2 x/2

now y = sin x/(1-cos x) = (2 sin x/2 cos x/2)/(2 sin ^2 x/2)

so y = cot x/2 = tan (pi/2 - x/2) as cot a = tan (pi/2 -a)

using 1 t = pi/2 - x/2

orarctan ( sin (x)/(1-cos x)) = pi/2 - x/2

2/6 * 148200= 148200/3= 49400option c

operation (c)is the correct answer

option, c rs 49,400is the right answer

option, c 49,400 is the right answer

the correct answer is operation c

21kg is the correct answer

option (D) is the right answer.

option d is the correct answer of the given question

opction D is right answer

21kg is the correct answer

21kg is the best answer

Option D is the right answer

tanx +secx +c is the right aswer

(Sinx -cosx)^2 = sin^2x + cos^2x -2sinx.cosx =1-2sinx.cosx =1-sin2x

Sin^2x -cos^2x =-cos2x

Integration -cos2x/(1-sin2x)

1-sin2x = t

-2cos2x dx =dt

Integration (-cos2x /t ) × dt/-2cos2x

Integration 1/2 (1/t dt) =1/2 log|t| + log c

log (1-sin2x )^1/2+logc

log [(1-sin^2x)^1/2 ×c]

It's a 0/0 form so diffrentiated both numerator and denominator

= 11cos(11x)/1now putting limit= 11cos(0)= 11

Let the two numbers be x and yx - y = 50y/x = 1/33y = x3y - y = 502y = 50y = 25x = 3(25) = 75

let x be included in this ratio3x-x=502x=50x=251st integer=252nd integer=25×3=75

Numbers are in 3:7 ratio suppose numbers are 3x and 7x 3x + 7x = 70 10x = 70 x = 7 numbers are 21 and 49.

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1st positive integer=2x2nd " " =5xA/Q5x-2x=303x=30x=30÷3x=101st integer=2x=2×10=202nd integer=5x=5×10=50

prime factorization of q =2^m 5^n

thanks

Decimal expansion = 43/4*1250.086 after decimal three digits are there

35/50

=35/2*5^2

=35*2^2*5^2/2*2*5^2

=35*4*25/2^2*5^2

=3500/10^4

=0.35

it is not clear image

due to their brutal behaviour towards indians

TheIndian Statutory Commission, commonly referred to as theSimon Commission, was a group of seven British Members ofParliamentunder the chairmanship ofSir John Simon. The commission arrived inBritish Indiain 1928 to study constitutional reform in Britain's largest and most important possession. One of its members wasClement Attlee, of the Labour Party, who became committed to Indian independence by 1934 and achieved that goal asPrime Ministerin 1947 in the .granting of independence to India and Pakistan.[1]

At the time of introducing theMontagu–Chelmsford Reformsin 1919, the British Government declared that a commission would be sent to India after ten years to examine the effects and operations of the constitutional reforms and to suggest more reforms for India.[2]In November 1927, the British government appointed the Simon Commission to report on India's constitutional progress for introducing constitutional reforms, as promised.

The Commission was strongly opposed by many in India . It was opposed by Nehru, Gandhi, Jinnah, theMuslim LeagueandIndian National Congressbecause it contained seven members of the British Parliament but no Indians. Indians saw it as a violation to their right of self determination and insult to their self respect. Prominent Indian nationalistLala Lajpat Railed a protest inLahore. He suffered a police beating during the protest, and died of his injuries on 17 November around 1928.

Every point on a circle is at the same distance from the centre. A diameter = 2 × radius

Amixed numberis a combination of a whole number and a proper fraction.example are:2 1/2

All sets are proper subsets except the set that contains all of the elements. The number of subsets is always 2^n where n is the number of elements in the set; in this case 5. There should be2^5=32 subsetsincluding the empty set and the set itself.

{ a, b, c}

Number of proper subsets = 2ⁿ

n is number of elements in set

2³ = 8

b) is correct

sqrt(sin P/cos Q) - sin P cos Q= sqrt(sin P/cos(90-P) - sin P cos Q= 1 - sin P cos (90-P)= sin^2 P + cos^2 P - sin P sin P= sin^2 P + cos^2 P - sin^2 P= cos^2 P