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\left. \begin array l \angle P %2B \angle Q = 90 ^ \circ \text then show that \\ \sqrt \frac \operatorname sin P \operatorname cos Q - \operatorname sin P \operatorname cos Q = \operatorname cos ^ 2 P \end array \right. |
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Answer» sqrt(sin P/cos Q) - sin P cos Q= sqrt(sin P/cos(90-P) - sin P cos Q= 1 - sin P cos (90-P)= sin^2 P + cos^2 P - sin P sin P= sin^2 P + cos^2 P - sin^2 P= cos^2 P |
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