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where is the answere

One side is 40m and diagonal is 50m so other side is 30m Area = 40*30 = 1200 sq.m.

Please post a complete question.

please post a complete question

Since it passes through the points (4,3) and (-1,4) these points will satisfy equation of ellipse

4^2/a^2+ 3^2/b^2= 1 and (-1)^2/a^2+ 4^2/b^2= 1

Take 1/a^2= x and 1/b^2= y. ----------(1)

Now the above 2 equations become as- 16x + 9y = 1----------(2)

and x + 16y = 1----------------(3)

Solving the equations(2) and (3) we will get y= 3/49 and x = 1/49

From (1) we get a^2= 49 and b^2= 49/3

Substituting a^2b^2in equation of ellipse when major axis is along x axis we will get-

x^2/49 + 3y^2/49 = 1

Thanks

LHS(1/cosecA-cotA)-(1/sinA)={1/(1/sinA-cosA/sinA)}-(1/sinA)=[1/{(1-cosA)/sinA}]-(1/sinA)=sinA/(1-cosA)-(1/sinA)=(sin²A-1+cosA)/sinA(1-cosA)={(1-cos²A)-(1-cosA)}/sinA(1-cosA)={(1+cosA)(1-cosA)-(1-cosA)}/sinA(1-cosA)=(1-cosA)(1+cosA-1)/sinA(1-cosA)=cosA/sinA=cotARHS(1/sinA)-(1/cosecA+cotA)=(1/sinA)-{1/(1/sinA+cosA/sinA)}=(1/sinA)-1/{(1+cosA)/sinA}=(1/sinA)-sinA/(1+cosA)=(1+cosA-sin²A)/sinA(1+cosA)={1+cosA-(1-cos²A)}/{sinA(1+cosA)}={(1+cosA)-(1+cosA)(1-cosA)}/{sinA(1+cosA)}=(1+cosA)(1-1+cosA)/sinA(1+cosA)=cosA/sinA=cotA∴, LHS=RHS

LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ)= (tanθ + secθ - 1)/(tanθ - secθ + 1)

Multiply (tanθ - secθ) with both Numerator and denominator = (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ)= {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ)= (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ]= -1/(tanθ - secθ) = 1/(secθ - tanθ) = RHS

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Since the set contains. only those real no's such that t³ = t so, t³-t = 0or t(t²-1) = 0 , therefore t can be 0, or t² = 1=> t = ±1

so, elements are -1,0,1

set in roster form D = {-1,0,1}

I can't understand

from whare1is originated

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The SSA congruence Criterion for two Triangles is not sufficient to determine the congruency.

The SSA Postulate does not exist because an angle and two sides do not guarantee that two triangles are congruent.

After independence, various efforts have been made to improve the socio­economic conditions of the tribals and to sustain the constitutional safeguard given to them The Central and State Governments have made incessant efforts in the direction of tribal welfare and development. Special programmes for their development have been undertaken in the successive Five Year Plans. The aim was to bring them on par with other developed sections of the society. But the results are not encouraging in all cases with an introduction of development plans, some societies have found themselves disintegrated.

1 litre for 12so 240 litre= 240x 12=288 0

Answer is 12multipy by 240 answer will be ₹2880

right answer is 2880

240×12=240+480= 2880

12(240) = 2,880That is the correct answer

the right answer is 2,880 of the following

correct answer 2,880 of the following question

2880 is the correct answer of the given question

-17 is the right answer.

plz accept as best as

5500×15%=825

10% increase5500+550=6050

6050×13%=786.5

Decrease in savings =825-786.5=38.5

Thanks

Let the number be x

Then,x÷7 = 11

x = 11*7 = 77

Therefore, Number is 77

7 multiply 11=77 so answer is 77

77 is the correct answer

this

There are two parts of this Question:

Part 1- Divided by 2, 3, 4, 5 and 6 leaves the remainders 1, 2, 3, 4, 5 respectively.

Part 2 - Least multiple of 7

SOLUTION:

If the difference between the divisor and the remainder is SAME, then there is aneasyway of solving the remainder questions.

Part 1:

divisor is 2 and remainder is 1. Difference is 1 (2–1)

divisor is 3 and remainder is 2. Difference is 1 (3-2)

and so on, you can see that the difference is 10 in all the cases.

Number Would be:

LCM of divisors - difference ,OR, LCM (2, 3, 4, 5, 6) - 1 = 60 - 1 = 59

Next numbers satisfying the property in part 1 will be obtained by adding LCM to 59. So next number is 119, 179 and so on.General format of these numbers is 60K + 59.

Part 2:

Finding a number of the format60K + 59 which is divisible by 7.

Put K = 0, number is 59 which is NOT divisible by 7.

Put K = 1, number is 119 which is divisible by 7.

Hence answer is 119.

NOTE - You might have observed it while solving part 1 only that 119 is divisible by 7. Such an elaborated Part 2 solution is required only if you are NOT able toobservethe answer quickly.

As ownership rights in a partnership are divided among two or more partners, separate capital and drawing accounts are maintained for each partner.

Investment ofcash.

Investment of assets other thancash.

Profitand loss account.

Statement of partners' equity.

Equity section of the balance sheet.

Equal partners.

The expenses which can be specially incurred for a particular departments like salary to salesman, can be charged directly to the department, but the expenses which could not be allocated precisely to a particular department may be divided among the different departments are as follows:

1. Sales Of Each Department* Salesman's commission* Discount allowed* Bad debts* Carriage Outwards* Advertisement* Packing expenses* Provision for discount on debtors* Traveling salesman's salary and commission

2. Purchase Of Each Department* Discount received* Provision for discount on creditors* Carriage Inward* Freight* Duty

3. Area Of Floor Space Of Each Department* Rent* Rates and taxes* Repair and maintenance Of building* Insurance on building* Air conditioning expenses* Heating

4. Value Of Assets In Each Department* Depreciation Of Machinery* Repairs and maintenance of plant* Insurance premium5. Number Of Workers*Workmen'scompensation insurance* Canteen expenses* Labor welfare expenses* Time keeping* Personnel office* Supervision

6. Direct Wages* Compensation to workers* Holiday pay* Provident fund contribution* Group insurance premium

7. Number Of Light Points* Lighting expenses

8. Horse Power Of Machine And /Or Production Hours* Electric Power

9. Time Devoted By Him For Each Department* Work manager's salary

1 kg is of 50 so 25 kg is of 1250 so CP = 1250 PROFIT = 10% so SP = 1375 2 kg were rotten so SP of 1 kg 1375/23 = 59.7826

Total cost = 25 x 50 = 1250.Now he have 23 kg left.He wants to gain 10% so gain = 125Total selling price = 1375Per kg price = 1375/23 = 59.78 ₹.

56÷4=16. area of square = 16×16=256

Area of square = side x side = 16x16= 256

square perimeter = 56 4X. = 56 X = 56/4 = 14 area of square. = 14×14 = 196

4L÷4=Larea=L×L =L²

Solution:CP = 854.90

Explanation:CP + gain % of CP = SP

Let x be the CP.

x + (2/100)x = 872

102x/100 = 872

102x = 87200

x = 87200/102

x = 854.90 rupees

thanks

p=144 s= Xp=X× 4144/4= 36

thank u so much for my help

Answer : D)60,15Let the number be x and yx-y=45x=4ynow 4y-y=453y=45y=45/3y=15

Now x=15×4=60Thus x=60; y=15

D is the correct answer......

D is the correct answer.......