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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
P and Q are two elements, which form P2Q3 and PQ2. If 0.15mol of P2Qs weighs 15.9 g and 0.15 mol of PQ2 weighs 9.3 g,what are atomic weights of P and Q? |
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| 2. |
ofa closed wooden cuboidal box are 30 cm x25the wood is 2 cm all around, find the volume of the woodthelevelof5wmhow much more watercm x20External dimensions of a closed woodenthe thickness of the wood is 2 em an the cuboidal box formed. |
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Answer» Like if you find it useful |
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| 3. |
ili) The length of a rectangular plot istwice its breadth. If the perimeter ofthe plot is 240 m, find its area. |
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Answer» let breadth of plot be xSo, length is 2xPerimeter = 2402×(2x+x) = 2406x = 240x = 40So, Breadth is 40Length is 80Area = L×B = 40×80 = 3200 m² |
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| 4. |
The perimeter of a rectangular plot of land is 240 m and its length is 63 m. Find the breadth andarea of the plot.3. |
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| 5. |
In a regular pentagon ABCDE, inscribed in acircle; find ratio between angle EDA and angleADC. |
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| 6. |
, many rectangles can be drawn with 18 cm as the perimeter? |
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| 7. |
8. A regular pentagon ABCDE and a square ABFG are formed on opposite sides of[NCERT Exemplar]AB. Find BCF |
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Answer» ABCDE is a regular pentagon and ABFG is a square. So the sides of pentagon and square are equal. Each angle of square = 90° Each angle of regular pentagon = 108° From the figure <FBC =360 - [<ABF + <ABC] <FBC = 360 - (90 +108 ) =360 - 198 = 162° <BFC = <BCF (since BF = BC, Δ BCF isosceles triangle ) <BCF= 1/2(180 - 162) =9° |
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| 8. |
8. A regular pentagon ABCDE and a square ABFG are formed on opposite sides ofNCERT Exemplar]AB. FindBCF. |
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Answer» ABCDE is a regular pentagon and ABFG is a square. So the sides of pentagon and square are equal. Each angle of square = 90° Each angle of regular pentagon = 108° From the figure FBC =360 - [<ABF + <ABC] <FBC = 360 - (90 +108 ) =360 - 198 = 162° <BFC = <BCF (since BF = BC, Δ BCF isosceles triangle ) <BCF= 1/2(180 - 162) =9° |
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| 9. |
Ifzty-12 and xy-27, find the value ofx, ัะท |
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Answer» (x+y)^3=x^3+3x^2y+3xy^2+y^3 = x^3+y^3+3xy(x+y) x^3+y^3=(x+y)^3-3xy(x+y) = (12)^3-3(27)(12) =1728-972 x^3+y^3=756 Like my answer if you find it useful! |
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| 10. |
27. ABCDEis a regular pentagon. Find the measure of the angles marked x, y and z. |
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| 11. |
What is the coefficient form ofx' |
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Answer» x³ - 1 Standard form : x³ + 0 x² + 0x - 1 So, corresponding cofffcient are 1, 0, 0, - 1 (c) is correct |
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| 12. |
. ABCDE is a regular pentagon and M is the mid-point of AB. Prove thatDMä¸ABA M B |
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| 13. |
13.In Fig., ABCDE is a regular pentagon. Prove that the points A, B, C and E are concyclic.Ef- |
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| 14. |
3.The coefficient of x in the expansion of (x+3) isa).1 b) 9 c)18d)27 |
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| 15. |
13. Top surface of a raised platform is in the shape of aregular octagon as shown in figure. Find the area ofoctagonal surface.(a) 219 m(c) 119 m(b) 129 m(d) 149 m2 |
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Answer» hhdhfhfjfhhjfidkdjhdhfhdudhhdhfhfhfhfh 119 m^2 is the best answer 119m^2 is the best answer 119 m² is the right answer of this question c is the right answer option C is right answer option c right answer 119 m is right answer given in the question C) 119m^2 is correct answer that question length=11mbreadth=5mArea of rectangle=(length×breadth) =(11×5) =55m²and,height=4mfirst side=11msecond side=5mArea of 2 trapezium=½×h(first side + second side) =½×4(11+5)=32×2=64m² 55+64=119m² option (c) is answer to your question |
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| 16. |
ChallengeTop surface of a raised platform is in the shape of a regular octagon as shown inthe figure. Find the area of the octagonal surface.26 cm8 cm5 cm |
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Answer» If you find this solution helpful, Please like it. |
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| 17. |
96sFind the area of square tile whose side is 32 cn |
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Answer» Area= side x side= 32*32= 1024 cm^2 |
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| 18. |
Riverlength of the side along the riverT9. Top surface of a raised platform is in the shape of a regular octagon as shown inil m5mthe figure. Find the area of the octagonal surface.10. There is a pentagonal shaped park as shown in the figure. |
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| 19. |
46 mSolve the followinga) The length of a rectangle is 2 m and its breadth is 1 m. Find itsb) Each side of a square tile is 46 cm. A blue string is placed along thee) Nine square tiles are placed as shown to form a large square. Thed) Each figure below is made up of five 2 cm squares. Find theperimetersides of the square tile. What is the total length of the string?side of each tile is 1 m. What is the perimeter of the larger squaperimeter of each figure. |
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Answer» a) perimeter of a rectangle = 2*2+2*1 = 4+2 = 6 m what is perimeter and area perimeter of a rectangle is 2*(L+B) |
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| 20. |
4. A rectangular plot f Tand i3 UlL5 Perimeter of a square tile is 60 cm. Find its area. |
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Answer» Given: Perimeter=60cm a=60/4 a=15cm area=a^2 =15×15 =225cm^2 |
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| 21. |
Nine square tiles are placed as shown to form a large square. Theside of each tile is 1 m. What is the perimeter of the larger square? |
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Answer» The length of the side of larger square =3*(length of the side of the smaller square) =3*1 =3m Therefore, Perimeter of the larger square =4*3m =12m Ans: Perimeter of the larger square is 12m. |
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| 22. |
t Per ale.15. The floor of a room is in the shape of a square of side 48 m. The floor is to becovered with square tiles of perimeter 1.2 m. Find the cost of covering the floor ifeach tile costs 27. 612 |
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| 23. |
is only one square whose/perimeter and/ area are the same.th of eacieother rectangles whose perimeter and area are the same. Only one of these rectangles has ajength and width which are whole nuengh and w s retangleere is onside of this square?What is the leng |
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Answer» Perimeter is 4*sideand area is side^2hence equate them4*side=side^2side=4units thanx |
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| 24. |
Find three different irrational numbers between the rational numbersand7 |
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Answer» 5/7 and 9/11required rational number = a/b +c/d 5/7+9/11( we add a to c and c to d) 14/18 - first rational number to find second 5/7 +14/18=19/25 so second rational number is 19/25 to find third number 14/18 +9/11=23/29 so, these are your three rational number 5/7 ,19/25 ,14/18,23/29, 9/11 if understand so press on thank you button if not so you can reply tha t I do not understand |
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| 25. |
\left. \begin{array} { l l } { \text { Value of } \frac { 2 ^ { 100 } } { 2 } \text { is } } \\ { ( A ) 1 } \end{array} \right. |
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Answer» 2^100=2*2^99hence 2*2^99/2=2^99 I got the answer .I am just testing this app |
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| 26. |
\left. \begin array l l \text (B) & \frac 100 \sqrt 3 m \\ \text (D) & \frac 200 \sqrt 3 m \end array \right. |
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Answer» Answer:A)100√3 mExplanation: |
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| 27. |
\left. \begin{array} { l } { 4.8 \div 10 } \\ { 18.08 \div 100 } \end{array} \right. |
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Answer» a) 4.8/10 = 0.48 b) 10.08/100 = 0.1008 |
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| 28. |
lixpress o 36 as a fraction in simplest formWrite any three properties of irrational numDivide 315 by 3Simplify:27)(625)-Vrte coefficient ofx' in 2x,+ x2-5x3 + xf P(x)-5-4x +2x, Find (i) P(0) (ii) P(3)Write the factor theorem.actorize: 8(3a -2b) i0(8a-2b) |
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| 29. |
The sides AB and AC of a triangle ABC areproduced; and the bisectors of the externalangles at B and C meet at P. Prove that ifAB > AC, then PC > PB |
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| 30. |
Example 1 : If a line intersects sides AB and AC of a A ABC at D and E respectivelyAD AEand is parallel to BC, prove that = (see Fig. 6.13).â AB AC |
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Answer» Sol:Given that DE || BC . we know that AD / DB = AE / ECDB / AD = EC / AE adding 1 on sides we get(DB / AD) + 1 = (EC / AE) + 1( AD + DB) / AD = ( AE + EC) / AE.AB / AD = AC / AEAD / AB = AE / AC. |
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| 31. |
In Fig. 7.48, sides AB and AC of Δ ABC areextended to points P and Q respectively. Also,L PBC<Z QCB. Show that AC>AB. |
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| 32. |
In Fig. 7.48, sides AB and AC of Δ ABC areextended to points P and Q respectively. Also,QCB. Show that AC > AB.PBC <Fig. 7.48 |
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| 33. |
10) A coin is tossed 60 times and it landstails side up 35% of the time. Find thenumber of times each side turned up.23) |
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| 34. |
gression.+.... upto 8 terms9 3 2 4 |
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Answer» the answer is -6305/2880 by mistake I have forgotten - sign |
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| 35. |
6, In the given diagramPQR-90。, point o is12the centroid of ΔPQR and PQ-: 5 cm, QRcm. The value of OQ is |
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| 36. |
In Δ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values ofsin P, cos P and tan P. |
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| 37. |
. Construct a quadrilateral PQRS, in which PQ-5 cm, QR 7.5 cm, RS PS 6.5 cm, and PR -10 cmMeasure the diagonal Qs. |
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| 38. |
In triangle POR,right angled at Q,PR+QR=25 cm and PQ=5 cm. Determine the values of sin P, cos P and tan P. |
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Answer» 50 X from where |
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| 39. |
10. In Δ PQR, right-angled at Q. PR + QR-25 cm and PQ-5 cm. Determine the values ofsin P cos P and tan P |
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| 40. |
10. In Δ PQR, right-angled at Q, PR-OR-25 cm and PQ5 cm. Determine the values ofsin P, cos P and tan P |
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| 41. |
HT(iii) 15 + 3 + 9 + 5 + 13 +7+17+30TTdeh (upto 30 terms) |
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| 42. |
\left. \begin array l l 100 = 600 & 7 \times 100 = 100 \\ 1000 = & 7 \times 1000 = \\ 10.000 = & 7 \times 10,000 = \end array \right. |
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Answer» 6x1000=60006x10000=600007x1000=70007x10000=70000 |
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| 43. |
\frac{(150-142.5)}{150} \times 100 |
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Answer» 7.5*100/1507.5*10/157.5*2/315/35 (150-142.5)/150 * 100 = 7.5/150 * 100 = 750/150 = 5% |
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| 44. |
100 \times 10 + [ 400 \div \{ 100 - ( 50 - 30 ) \} ] |
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| 45. |
आर बोध >\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{N}}{100} |
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Answer» સરળ રસ = PRT / 100 આ તે ફોર્મ્યુલા છે જેનો ઉપયોગ આપણે સરળ રસ શોધવા માટે કરીએ છીએ |
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| 46. |
\frac { 25 } { 150 } \times 100 = ? \quad \text { and } \quad |
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| 47. |
x = \frac 10,500 - \frac 30,000 5 \frac 30,000 2 \times 100 |
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Answer» [(10500 - 30000/5)/(30000/2)]*100 = [(10500 - 6000)/(30000/2)]*100 = (4500/15000)*100 = 4500/150 = 30 |
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| 48. |
9t -91 92+93 +.upto 100 terms.+ b3a -b2+upto 100 terms. |
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| 49. |
A fair coin isS tossed upto 10 times. Find the probability of exactly 6 heads.upto |
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Answer» Exactly 6 heads chance will be 6Total chances =10Hence probability=6/10=0.6 |
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| 50. |
Find the sum to n terms of the Α.Ρ., whose kh term is 5k + 1. |
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