Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
a cinema hallneeded for one person ?60 m × 50 m × 15 m, how many persons should be seated if 50of air is |
| Answer» | |
| 2. |
(D)4t y7.A quadratic polynomial has no real zero, then the graph(A) touches x-axis at any point(B) intersect x-axis in two disti40) intersect y-axis in two distinct point D is in one hall plane |
|
Answer» C) is the correct option |
|
| 3. |
7. A shopkeeper buys an article for375. At what price must be mark it so that after allowing adiscount of 10%, he still makes a profit of 20%. |
|
Answer» CP of article = 375Let marked price be MPSP = 375 + 375x20/100= 375(1 + 1/5)= 375 x 6/5= 450 SP = MP - MP(10/100)= MP(1-1/10)= MP(9/10) MP(9/10) = 450MP = 4500/9MP = 500 MARKED PRICE IS RS. 500 |
|
| 4. |
Example 14. The area of a rectangular prayer hall is 300 m2. If the length of the hall (in metres) isone more than twice its breadth, then find the dimensions of the prayer hall.(CBSE 2007 |
| Answer» | |
| 5. |
7Represent 2 + 73 on the number line. |
| Answer» | |
| 6. |
8. Represent 0.23 in the form of m/n |
|
Answer» Let 0.23 bar =x As there is 2 numbers are under bar, multiply by 100 on both sides, 100*0.23 bar =100*x 23.23 bar =100x-0.23 bar = -x [subtract x from both sides] 23=99x 23/99 =x Now, 0.23 bar in p/q form is equal to 23/99 |
|
| 7. |
The length, breadth, and height of a hall are 5 m, 6 m, and 7 m, respectively. The hall has one door ofa 1 m × 0.5 m. Find the cost of painting the walls (only the walls) at the rate of90 per square metre.are |
| Answer» | |
| 8. |
7.A conference hall is 14 m long, 8 m wide and 4 mhigh. There are four windows and one door in it. Thedoor measures 1 m by 2 m and each windowmeasures 1 m by 1.5 m.(i) How many litres are needed to paint all thewalls of the hall if one litre is enough forcovering 18 m2?(i) What will be the cost of painting the hall if1litre costs 225? |
|
Answer» L=14B=8H=4Lsa=2 (l+b)×H =2 (22)×4=176door=1×28=284 windows=4×1×1.5=6So the area to be painted =176-(6+28)=176-34=142 m^2Litres required=142/18Cost=142/18×225=1775 |
|
| 9. |
s. A conference hall is 14 m long, 8 m wide and 4 m high. There are four windows and onedoor in it. The door measures 1 m by 2 m and each window measures I m by 1.5 m.(a) How many litres are needed to paint all the walls of the hall if one litre is enough forcovering 18 m2(b) What will be the cost of painting the hall if I litre costs 225Calculate the nerimator |
|
Answer» Assurface area of walls is 2h(l+b) or 2*4(14+8) or 8*22=176area of windows = 4(1*1.5) or 6area of door =1*2 or 26+2=8(176-8)18=168/18 or 28/3 or 9 and 1/3 litres |
|
| 10. |
E,AD and BE are altitude of triangle ABCperimeter of Î ABC.. If AB = 12, AC=9.9, AD = 8.1 and BE = 7.2 then find the perimeter of triangle ABC |
| Answer» | |
| 11. |
2. (i) Construct a triangle similar to a given triangle ABC with its sides equal to3th of the correspondingsides of triangle ABC i.e. of scale factor-(iy Construct a triangle similar to a given triangle ABC with its sides equal toth of the correspondingh of the corres pondingsides of triangle ABCi.e. of scale factor |
|
Answer» Keep the angles same and just construct the second triangle with sides 5/3a,5/3b,5/3c where a,b,c are the sides of the original triangle ABC. |
|
| 12. |
BE and CF are two equal altitudes of a triangle ABC. Usingare two equal altitudes of a triangle ABC. Using RHS congruencerule, prove that the triangle ABC is isosceles. |
| Answer» | |
| 13. |
Be and CFare two equal altitudes of a triangle ABC. UsinyRurule, prove that the triangle ABC is isosceies.ABC. Using RHS4. |
| Answer» | |
| 14. |
10, The line x- 1 = 0 is the directrix of theparabola y2-kx +8 0. Then one of thevalues of k is(a) 3 (b) 4(c) 5(d) 8 |
| Answer» | |
| 15. |
6., If the line x - 1 = 0 is the directrix of the parabolay? - kx + 8 = 0, then one of the values of k is(a) 1/8(b) 8(c) 4(d) 1/4 [2000] |
|
Answer» 1/8 right ............ |
|
| 16. |
men point P (, 2) is the mid-point of the line segment joining thepoints Q(-5,4) and R(-1,0).2. Find the value ofk, for which one root of the quadratic equation kx"-l4xs edisORFind the value(s) of k for which the equation x2 + 5kx +16 = 0 has real and equal roots.3. Write the value ofnt |
| Answer» | |
| 17. |
= kx-6, find r. |
|
Answer» The answer is 234 it is very easy question keep it up 234 is your right answer 234 is answer this question 234 is the right answer 234 is the right answer 234 is your answer of questions 234 is the answer of the following |
|
| 18. |
ct a triangle ABC in which BC = 7cm、A =nstruct a triangle ABC in which BC- RR45° an |
| Answer» | |
| 19. |
Cales larks Each.(4 x6-2(18) lf α and β are the zeroes of the polynomial x2 + 4x + 3, find the polynomialwhile zeroes are 1 and 1+2 |
|
Answer» Given equation = x² + 4x + 3 Factorising it by middle term splitting :-x² + 4x + 3x² + 3x + x + 3x ( x + 3 ) + 1 ( x + 3 )( x + 3 ) ( x + 1 ) ( x + 3 ) = 0x = ( - 3 ) ( x + 1 ) = 0x = ( - 1 ) So, alpha = - 3, beta = - 1 • The zeros of new equation are :- (1+alpha)/beta and (1+beta)/alpha (1+alpha)/beta = (1-3)/-1 = 2 (1+beta)/alpha = (1-1)/-3 = 0 So, the Zeros of new equation are 2 and 0 • Sum of the Zeros are :-0 + 2 = 2 • Product of the Zeros are :-0 × 2 = 0 To form the quadratic equation we have formula as :-x² - ( sum of Zeros )x + (product of Zeros) Putting value in it, we get x² - 2x + 0 So, the required quadratic equation is x² - 2x |
|
| 20. |
Example 7 Represent the complex number z=1+13 in the polar form |
| Answer» | |
| 21. |
0-8Represent v5 on the number line. |
| Answer» | |
| 22. |
\frac { x ^ { 2 / 7 } } { z ^ { 1 / 2 } } \times \frac { x ^ { 2 / 5 } } { z ^ { 2 / 3 } } \times \frac { x ^ { - 9 / 7 } } { z ^ { 2 / 3 } } \times \frac { z ^ { 5 / 6 } } { x ^ { - 3 / 5 } } |
| Answer» | |
| 23. |
3 x y + 5 y z - 7 z x \text { from } 5 x y - 2 y z - 2 z x + 10 x y z |
| Answer» | |
| 24. |
Add :5 x - 8 y + 2 z , 3 x - 2 y - 7 z , x + 5 y + 3 z |
| Answer» | |
| 25. |
\left. \begin{array} { l } { \text { Add } 2 x y + 3 y z - 6 x z , 4 x y - 2 y z + 7 x z \text { and } - x y - 2 y / z + 4 x z } \\ { \text { Subtract } x ^ { 2 } - \frac { 5 } { 2 } x + 7 \text { from } \frac { 1 } { 3 } x ^ { 2 } + \frac { 1 } { 2 } x + 2 } \end{array} \right. |
| Answer» | |
| 26. |
10. Except which value of k does the simultaneousequations 5-kx = 10y and x + 15y = -1 have aunique solution? |
|
Answer» A is the right answer..... a is the right answer Option a is the answer A is Answers is correct in this questions |
|
| 27. |
- Ifx - 2y = 3, find the value of x* + |
|
Answer» x - 1/2x = 3 squaring on both sides; (x-1/2x)^2=3^2; x^2+1/4x^2-2x/2x=9; x^2+1/4x^2-1=9 x^2 + 1/4x^2=9-1=8 |
|
| 28. |
-A(3, -3).HwFig. 7.2MPLE Y Draw a graph of the line x - 2y = 3. From the graph, find the coordinates of(ii) y=0ITION We haver-2y=3 = |
|
Answer» x-2y=3 1.x=-3(X)-2y=33-2y=3-2y=3-3-2y=0y=1/2 2.y=0x-2(y)=0x-2(0)=0X=0 coordinate are (0,1/2) |
|
| 29. |
4. Find the solution of 2y -3 = 7 |
|
Answer» 2y - 3= 72y =7+3 = 10 2y =10y =10/2 =5 2y=7+32y=10y=10/2y=5 2y-3=72y=10yy=10/2y=5 y=5 is the correct answer y=5 is the correct answer of the given question y=5 is the right answer...... |
|
| 30. |
(a) If the slope of the line kx+2y +3 0 is 3, then find k. |
|
Answer» We know thatY= mx+cwhere m is the slopenow herem= k= 3so k= 3 |
|
| 31. |
(a) If the slope of the line kx + 2y +3 0 is 3, then find k. |
|
Answer» kx + 2y + 3 = 02y = -kx -3y = (-k/2) +(-3/2)slope = -k/2 = 3k = -6 |
|
| 32. |
e A aandaB in &O kn apart from Cach othgrOkn apart from each thraonhitocu da can. Stay t from A and anotheγ、from Batthe ame tine ne they move in a same dvection theMeet in 8hour angka, If the move toward eaC4 other γrcy |
|
Answer» Let speed of A be a km/hr and speed of B be b km/hrdistance = 80kmATQ80=(a-b)*8 and 80 =(a+b)*(4/3)a-b =10 and a+b=60a= 35 , b= 25 |
|
| 33. |
रु 1 'जुडटतFUTY ESI |
| Answer» | |
| 34. |
DATEa.statethethahetheorenWhatcongruunttriangles |
|
Answer» a) if a line is parallel to a side of a triangle which intersects the other sides into two distinct points, then the line divides those sides in proportionb) Congruent Triangles. When twotrianglesarecongruentthey will have exactly the same three sides and exactly the same three angles. The triangles..having same shape..size..and all of there sides and angles are equal to each other..are called congruent triangles...😊😊🤗..they can overlap one another... |
|
| 35. |
The value of K for which the equations Kr-y=2 and 6x-2y=3 has a uniquesolution5·A) -3B) 3C) #0 |
| Answer» | |
| 36. |
Nomon-has tha eetimes-as mane tuer 14 eesCoins es he has ice TcsCoins If hehas -to lal monty _ 구구 hoa-mana coinsthaee times as many foyーeach types hehas |
|
Answer» Let x be the amount of x of 5 rupeeso 3x amount of 2 rupee so total of 5*x+2*3x=77x=7 Naman has 7 X Rs5 & 21 XRs2 |
|
| 37. |
kx + 2y3Find the value(s) of k for which the pair of equations3x + 6y 10has a unique solution |
|
Answer» for Unique solution |
|
| 38. |
912. Find the values of p for which the given pair of linear equations have a uniquesolution4x+py + 8 = 02x+2y + 2=0SECTION-C |
|
Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. |
|
| 39. |
2% of 25 students are good in mathematics. How many are notA football team won 10 matches out of the total number of matches they played1heir win percentage was 40, then how many matches did they play in al?good in mathematicses out of the total number of matches they played. |
| Answer» | |
| 40. |
4A quadratic polynomial has no zero. Its graph .....(a) touches X-axis at any point(b) intersects X-axis at two distinct points(d) does not intersect X-axis at two distinct points(d) is in any one half plane of X-axis |
|
Answer» option d is correct dude option d is the correct answer according to your question option d. is the right answer d is correct answer of ypur question option d is the correct answer option d is correct because here roots are imaginary. |
|
| 41. |
line which intersects a circle at two distinct points is known as- |
|
Answer» A line that interests a circle at two points in a circle is called A SECANT. |
|
| 42. |
If a line parallel to a side of a triangle intersects the remaining sides in two distinct points, then the line divides the sides in the same preperation. |
|
Answer» it is not theorem |
|
| 43. |
esi prepertianality theorenbcorem: Ifa line parallel to a side of a triangle intersects the remaining sides totwo distinct points, then the line divides the sides in the uoepropertion. |
| Answer» | |
| 44. |
Let's learn.oportionality theorem:If a line parallel to a side of a triangle intersects the remaining sides itwo distinct points, then the line divides the sides in the samproportion. |
|
Answer» #thanx |
|
| 45. |
∆ABC is an isosceles triangle in which AB =AC. Show that <B=<C(Hint: Draw AP BC) (Using RHS congruence rule) |
| Answer» | |
| 46. |
\log _{2}^{x}+\log _{4}^{x}+\log _{16}^{x}=\frac{21}{4} |
|
Answer» log base 2 x = log(x) / log(2)log base 4 x = log(x) / log(4) = log(x) / log(2^2) = log(x) / ( 2 log(2) )log base 16 x = log(x) / log(16) = log(x) / log(2^4) = log(x) / (4 log(2) ) log base 2 x + log base 4 x + log base 16 x = log(x) / log(2) + log(x) / ( 2 log(2)) + log(x) / ( 4 log(2))= (log(x) / log(2) )( 1 + 1/2+1/4)= ( 1 + 1/2+1/4) (log(x) / log(2) )= (7/4) log (base 2) x = 21/4multiply both sides by 47 log(base 2) x = 21divide both sides by 7log(base 2) x = 3x = 2^3x = 8 |
|
| 47. |
\left. \begin{array} { l } { \operatorname { log } _ { 2 } ( \operatorname { log } _ { 3 } ( x ^ { 2 } - 1 ) ) = 0 } \\ { \sqrt { 5 - \operatorname { log } _ { 2 } x } = 3 - \operatorname { log } 2 x } \end{array} \right. |
|
Answer» ssryy2 to the power 4= 16 |
|
| 48. |
Represent --and-on same number line.S10 |
|
Answer» take LCM of 5 and 10 is 10 now multiply -2/5 by 2=-4/10 so now show them on number line |
|
| 49. |
\operatorname { log } _ { 2 } x + \operatorname { log } _ { 4 } x + \operatorname { log } _ { 16 } x = \frac { 21 } { 4 } , \text { find } x |
|
Answer» loga[x] = logx/loga so, log2[x] +log4[x] +log16[x] = 21/4=> logx/log2 +logx/log4 +logx/log16 = 21/4=> logx[1/log2 +1/2log2 +1/4log2] = 21/4=> logx/log2[ 1+1/2+1/4] = 21/4=> log2[x]*(7/4)=21/4=> log2[x] = 3=> x = 2³ = 8 |
|
| 50. |
z^{4}-10 z^{2}+9=0 |
|
Answer» nice |
|