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\operatorname { log } _ { 2 } x + \operatorname { log } _ { 4 } x + \operatorname { log } _ { 16 } x = \frac { 21 } { 4 } , \text { find } x |
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Answer» loga[x] = logx/loga so, log2[x] +log4[x] +log16[x] = 21/4=> logx/log2 +logx/log4 +logx/log16 = 21/4=> logx[1/log2 +1/2log2 +1/4log2] = 21/4=> logx/log2[ 1+1/2+1/4] = 21/4=> log2[x]*(7/4)=21/4=> log2[x] = 3=> x = 2³ = 8 |
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