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For term to be -ve , equate tn with 0

=> 0 = a +(n-1)d=> 21+(n-1)(-3) = 0=> (n-1) = -21/-3=> n-1 = 7=> n = 7+1 = 8

so, 8th term will be 0 and after that 9th term will be first negetive term

the party at the time of independence was national congress party consists of more than 300 member under mahatma Ghandi and pandit Jawaharlal Nehru

what is this

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Petrol tank dimensionsLength = 10m, Width = 4m, Depth =?

Volume of tank = 120000 l = 120000/1000 m^3

Volume of tank = length*width*depth120 = 10*4*depthDepth = 12/4 = 3 m

Let amount of petrol in another tank = n

Then amount of petrol in first tank = 2n

As per given condition2n - 25 = n + 252n - n = 50n = 50

Therefore,Amount of petrol in first tank = 2n = 100 litresAmount of petrol in another tank = n = 50 litres

b)they are conjugates

let z1 = x+iy and z2 = u + iv Rez1*Rez2 - Imz1*Imz2 = xu-vy

now z1z2 = (x+iy)(u+iv) = xu + ixv + iuy + i²vy = (xu-vy) + i(xv-uy)

so, Re(z1z2) = (xu-vy)

=> L.H.S = R.H.S

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(b) DESTINATION

Explanation:Given word does not contain the letter S. Therefore, a word containing S cannot be formed.

Volume of tank = 40*28*25= 28000cm³= 28dm³= 28 LDistance the car can travel = 13.5*28= 378 kms

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rs 151/4 -1 litre cost of 32/5 litre - 151/4/32/5- 755/128 rupees

RS 151/4 - litre cost of 32/5 litre- 151/4/32/5-755/128 rupees

other side is 16 cm ,20+12+16= 50

other side is 16 vm ,20+12+16=50

16m is the right answer

5+6+7-12÷65+6+7-218-216

5+6+7-12÷6=18-2=16

16is the right answer

Polyphase System is a combination of two or more than two voltages having same magnitude and frequency but displaced from each other by an equal electrical angle. As poly means, many (more than one) and phase means windings or circuits. Each of them has a single alternating voltage of the same magnitude and frequency.

volume of sphere =4/3πr^3=4/3π(2r) ^3=4/3π8r^3=>32/3πr^3

32/3 π r^ 3 is the correct answer of the given question

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Let r be the radius and h the height of the inscribed cylinder ABCD.let V be its volume.then , V = πr²h------( 2 )clearly, AC = 2R.ALSO, AC² = AB² + BC²

=> (2R)² = (2r)² + h²=> r² = 1/4(4R² - h²)--------( 2 )

using----( 1 ) & -----( 2 )V = πh/4(4R² - h²)=> dV/dh = (πR² - 3/4πh²)

and d²V/dh² = -3/2πh.

for Maxima or minima, we have (dV/dh) = 0

now, dV/dh = 0=> πR² - 3/4πh² = 0h = 2R/√3.

therefore,[d²V/dh²](at h = 2R/√3) = -3/2π * 2R/√3= -πR√3 < 0.

So, V is maximum when h = 2R/√3.hence, the height of the cylinder of maximum volume is 2R/√3.Largest volume of the cylinder = π×1/4[4R² - 4R²/3] × 2R/√3 = 4πR³/3√3.

1. 3/9 or 1/3

2. 2/9

3. 4/9

Kaisha circles ka hua ha

option d is the correct answer of the given question

Let r be the radius and h the height of the inscribed cylinder ABCD.let V be its volume.then , V = πr²h------( 2 )clearly, AC = 2R.ALSO, AC² = AB² + BC²

=> (2R)² = (2r)² + h²=> r² = 1/4(4R² - h²)--------( 2 )

using----( 1 ) & -----( 2 )V = πh/4(4R² - h²)=> dV/dh = (πR² - 3/4πh²)

and d²V/dh² = -3/2πh.

for Maxima or minima, we have (dV/dh) = 0

now, dV/dh = 0=> πR² - 3/4πh² = 0h = 2R/√3.

therefore,[d²V/dh²](at h = 2R/√3) = -3/2π * 2R/√3= -πR√3 < 0.

So, V is maximum when h = 2R/√3.hence, the height of the cylinder of maximum volume is 2R/√3.Largest volume of the cylinder = π×1/4[4R² - 4R²/3] × 2R/√3 = 4πR³/3√3.

the standard form of a quadratic equation is ax2+bx+c=0

344/12

Cancel using 2

172/6

Cancel using 266/3

Cancel using 322

23/200 can be terminated as0.115so three places after decimal

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please give his formula

Dil Le Koi rokna tha kya hoga hoga Gaya pardesiMera sochna tha

120 hogaord 60 ho jaayega corresponding angle se cro 120 linear angle sum 180

Iska Ans hai 120° kyon ki angle 60 is vertically opposite and then it is alternate interior angle and finally 180-60=120

120° as angle on straight line is 180° and here angle ORD= 60° corresponding anle so angle x= 180-60=120°

using AIA angle and corresponding angle answer is120

This is opposite angle and answer 60

4*2=8x*X=x^2y*y*y=y^38x^2y^3

if length of rectangle is l and breadth b

area is maximum when l=b

so given perimeter( 1 ) 2(l+b)=40

so as l = b l = 10So maximum area is L2=100 cm^2( 2 ) 2(l+b) = 60so as l = bl = 15maximum area is L^2 = 225 cm^2

(b)is correct answer

Higher the perimeter higher will be the area so,PERIMETER: 2(l+b) = 60 l+b= 30 l =15b = 15 AREA: l×b= 15×15 = 225cm²:.AREA IS 225cm²

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