)40 cm (1) 60 cmFind the one having maximum(Nagaland B 2018rectangles,

1.	)40 cm (1) 60 cmFind the one having maximum(Nagaland B 2018rectangles, each of which has perimeterP.B. 2010one having maximum area. Also find that area
Answer» if length of rectangle is l and breadth b area is maximum when l=b so given perimeter( 1 ) 2(l+b)=40 so as l = b l = 10So maximum area is L2=100 cm^2( 2 ) 2(l+b) = 60so as l = bl = 15maximum area is L^2 = 225 cm^2 (b)is correct answer Higher the perimeter higher will be the area so,PERIMETER: 2(l+b) = 60 l+b= 30 l =15b = 15 AREA: l×b= 15×15 = 225cm²:.AREA IS 225cm²

)40 cm (1) 60 cmFind the one having maximum(Nagaland B 2018rectangles, each of which has perimeterP.B. 2010one having maximum area. Also find that area

Answer»

if length of rectangle is l and breadth b

area is maximum when l=b

so given perimeter( 1 ) 2(l+b)=40

so as l = b l = 10So maximum area is L2=100 cm^2( 2 ) 2(l+b) = 60so as l = bl = 15maximum area is L^2 = 225 cm^2

(b)is correct answer

Higher the perimeter higher will be the area so,PERIMETER: 2(l+b) = 60 l+b= 30 l =15b = 15 AREA: l×b= 15×15 = 225cm²:.AREA IS 225cm²