Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The exterior angles obtained on producing the base of a triangleboth ways are 104° and 136°. Find the angles of the triangle.

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2.

1. The exterior angles obtained on producing the base of a triangleboth ways are 104° and 136°. Find the angles of the triangle.

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3.

18. /The exterior angles obtained on producing thebase of a triangle both ways are 104° and 136°Find all the angles of the triangle

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4.

&+ 3y = 10o~y =4

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2x+3y=103x-y=4Multiply equation 2 with 32x+3y=109x-3y=12Add equations11x=22x=2y=3x-4y=6-4=2

5.

| (iii) + 2x =14

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6.

(i) 3 x 5x = ( )(iii) 2x x 0 = ( )

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(i) 3 * 5x = 15x(iii) 2x * 0 = 0

7.

(3y^2 + 5y-4) - (8y-y^2-4)

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8.

If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then findthe volume of the solid so obtained. Find also the ratio of the volumes of the twosolids obtained in Questions 7 and 88.

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9.

If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then findthe volume of the solid so obtained. Find also the ratio of the volumes of the twosolids obtained in Questions 7 and 8.

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10.

If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then findthe volume of the solid so obtained. Find also the ratio of the volumes of the twosolids obtained in Questions 7 and 8.

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11.

1. एक 250 मी लम्बाई की ट्रेन 350 मी लम्बाईके प्लेटफॉर्म को 50 सेकण्ड में पार कर जातीहै। 230 मी लम्बाई के प्लेटफॉर्म को वह ट्रेनकितने समय में पार करेगी?(8) 60 सेकण्ड (0) 45 सेकण्ड(८) 40 सेकण्ड (0) 55 सेकण्ड

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Solution :-

Speed of train :-

= > ( train length + platform length ) / time

=> Speed of train =(250+350)/50

=> 12m/s

Time taken to cross platform of 230+250

=> 480/12

=> 40 sec

Therefore time taken is 40 second Ans.

12.

For each equation in 1-3, list the slope, y-intercept and whether or not it is proportional2.3.3y 1.25xSlope_Slope:y-intercept:Proportional?:m:b:y-intercept:Proportional?Proportional?:

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13.

lu) slope - -5 and y-intercept- -3

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14.

3. Find x-intercept and y intercept offo5x-15 (i) y-7x (ii) x -5

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1) Y = mx+cX intercept -3and y = 15 for this

2) y= 7xx and y intercept will be(0,0)

3) x= 5for this there is not any y intercept as it's having a constant value of 5

15.

3.Find x-intercept and y-intercept of : (1) y- 5x-15 (ii) y-7x (ili) x5

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16.

off an intercept 2 on the y-iiS.7. Find the equation of a straight line cutting off an intercept-1 from the y-axisbeing equally inclined to the axes.icht line which cuts off an intercept of length 3 on

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17.

23. A circle is tangent to the y-axis at y 3 and has one x-intercept at 1.(e) Determine the other a-intercept. (b) Deduce the equation of the circdle.

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18.

The x-coordinate of a point on the line joining the points P(2, 2, 1) andQ(5, 1,-2) is 4. Find its z-coordinate.

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19.

2x+3y=103y-2x=5

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20.

Example 16.Find the equation of a curve passing through the point (O, L), if the slope ofthe tangent to the curve at any point (x, yis equal to the sum of the x-c0ordinate and the productof the x-coordinate and y-coordinate of the point.NCERT

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21.

2x+3y=10

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22.

[Prove that the lines 2x-3y+10,xty 3,2x-3y 2 andx 4-y forma parallelogram.]

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23.

812x+3y = 9.35 (ii) x-X-10-0 (iii)-2x+3y-6 (iv) x-3y(vi) 3r+20 vi) y2(vii) 52(i)(v)

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24.

. For a pair of equations 2x +3y 10 and 3x-y 4. x-. x-

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25.

If the point (m-2 ,2m+1) lies on equation 2x+3y-10=0 Find the value of m

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26.

Us Practice problemscost of 7kg of onions isIf the cost of 7kg84 find the followingWeight of the onions bought for(i) Weight of th180 (0) The cost of 3 kg of onions

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i)cost of one kg = 84/7=12 12 rs----------- = 1kg 1180rs ---------- = ----- x 180 12 = 15 kg ansii).cost of one kg = 84/7=12cost of three kg = 12*3=36Ans.36 Rs

36 is the correct answer of the given question

27.

Rina lost her weight in the ratio 5:3. Her original weight was 80 kg. What is herCeIn

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28.

Sin (300) Ce (360+9) Che in(230 0

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29.

sin 60°53. The value of tan 60° is

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√3/2/√3/11/√2is the correct answer

1/2 is the correct answer

1√2 is correct answer for your questions

sin60/tan60=√3/2 / 1/√3= √3/2 ÷ 1/√3=√3/2×√3/1=3/2

1/2 is the correct answer

sin 60° = √3/2 and tan60° = √3 ,,,, then sin60°/tan60° = √3/2/√3 = √3/2√3 = 1/2 answer

30.

rLxercise-.3I.A trader marked his goods 20% above the CP. He also allows aper cent.The sugar is sold at? 5.4 per kg at a loss of 10%. At what pridiscount of 10% on the goods. Find his gaince should it be sold per kg to earn a profit of2.20%?

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31.

By how many kg is 850 g greater than 255800 mg?A) 0.005942 kgr5.942 kg(B) 0.05942 kgE) of these

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1 mg =.001 g

Then, 255800 mg = 255.8 g

Difference of 850 g and 255.8 g = 850 - 255.8 = 594.2 g

1 gm =.001 kg594.2 g =.5942 kg

Thus, in kg 850 g greater than 255800 mg by .5942

32.

3 dozen pens cost is Rs. 72 How much 2 dozen pens cost?

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1 dozen = 12 units3 dozen = 36 unitsso, cost of 3 dozen is Rs 72Cost of one pen Rs 72/36 = Rs 2So, 2 dozen is 24 pens cost of 24 pens is Rs 2 × 24 = Rs 48So, cost of 2 dozen pen is Rs 48

33.

11,980 copiesHousection

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simple, 1 copy =12 pages.so 11980 copies = 11980×12 = 143760 pages.

34.

e S RSN AReled A ।१ शत ७०९ 2०80: 6- = Yafe -{ e OMRES eSoge -\ Sedp-tsede _ iSN Qe (e .

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35.

E GEOMETRY /唱//ua 21 Qu If the point (0.2) is equidistant from the points (3,k) and (k,5), find thevalue of k

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36.

कि RSN AWES Red ol1o 14 सेमी ुजा के वर्ग में बने अन्त: वृत्त की परिधि ज्ञात कीजिए ।

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37.

> i R P RSN+40" =81 + 1600 = 1631P}__ ¥ कि. नीचे दिए गए त्रिक पाइथांगोरर12.15) (2501525 71गी : हमारे देश में संख्याओं का यह सम्बन्ध बह

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38.

rsn denotes the sum of the first n terms of an AP., prove that S30-3 (S20-S10).

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39.

The angle between two lines is 45° and the slope of one of them isFind the slope of other2line.

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40.

In rectangle ABCD, the slope of ABState theslope of(a) BC(b) CD(c) DA

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We know that each angle of a rectangle is 90°, so

angles A = B = C = D = 90°

We know that when two lines are perpendicular to each other then the product of their slopes is -1

Slope of AD = 5/6

Since AD is perpendicular to DC,

Slope of DC = -1/slope of AD

= -1/(5/6)

= -6/5

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41.

2. Express the following linear equations in the form ax + byc 0 and indicatethe values of a, b and c in each case:(i) 2x + 3ys 9.35 (ii) x-y-10(v) 2x -5y0(iii)-2x + 3y-b(iv) x-3y(Vİ) 3x+2+0(vii) y-2:0 (viii) 5-2xVil.

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42.

Iff(x) = x and g(x) = ld, then f(x) + g(x) is equal toa) 0 if x <013.b) 2x if< 0c) 2x if x20d)- 2x if x20

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43.

07. Sunita bought a 10kg of grapes from the market. She gave 35 kg of the grapes to her friend Sonand 25 kg grapes to Anita. How many kg left with her.

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44.

15. Mr Soni bought some bagsmond Cuts 46 mol cloth puceSoni bought some bags of cement, each weighing 49.8 kg. If the total weightbags is 1792.8 ko, how many bags did he buy?

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45.

625 Âť 13 + 8382 + 66 - 916

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625 x 13 + 8382 ÷ 66 - 916Using BODMAS rule= 8125 + 127 - 916= 8252 - 916= 7336 ans

46.

1.2.The cost of 5 kg of rice is 82.50. Find out the cost of 7.5 kg of riceA car needs 19 kg of CNG for covering a distance of 171 km. How much CNG is needed to cover 320 km?nensis53 60 Eind out the cost of47 such nens

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19kg for 171 km so for 1 km = 171/19= 9kgnow for 320 km320*9= 2880kg

cost of 5kg rice= 82.501kg rice`s cost= 16.5cost for 7.5 kg = 7.5*16.5= 123.75 rs

47.

2. A car travel 432 km in 48 I of petrol How far ao3. If the cost of 24 kg sugar is t 624, what is thecost of 19 kg sugar ?he hought for74

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Ans :- Cost of 1 kg sugar = 624/24 = 26 rs. Cost of 19 kg sugar = 26 × 19 = 494 rs.

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21 kg sugar costs Rs 378 what is the cost of 14 kg?

48.

lll 2 hours and a train covers 120Ill 2 hours and a train covers 120Which ratio is larger in each of the following pairs:(i) 4:7 or 5: 8

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i) 4:7 = 4/7 = 0.57 5 : 8 = 5/8 = 0.62 so 5:8 is larger

49.

HindtheratloofFindtheratioofA bus covers 128 km in 2 hours and a train covers 240 km in 3 hours.their speeds.

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50.

Two lines(and m intervect at the poiDt O and Pis a point on a line s pasing through the point O suchsthat P is equidistant from landm. Prove that n is the bisector of the angle formed by land m

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