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y^2-(-5y^2)=y^2+5y^2=6y^2

As height of tower is 50√3 m

Distance of observer 50 m

In a right angle triangle perpendicular and base is given.

and we know that from trigonometric ratio

tan thetha = perpendicular/ base

tan thetha = 50√3/50tan thetha = √3

angle of elevation = tan-1 (√3)angle of elevation = 60°

if we assume that the largest value is 14 and the smallest one is 3 then the range is 11 so3=<x<=14now if x = 8 then :3 7 8 8 8 14 and the median is (8+8)/2=8if x=7 then3 7 7 8 8 14 and then the median is (7+8)/2=7.5 so x =/= 7if 3<=x<7 then3 x 7 8 8 14and the median is 7.5 which is wrongif 8<x<=14 then3 7 8 8 x 14 then the median is 8+8/2=8

so x can be any number from 8 to 14 meaning thatx = 8 or 9 or 10 or 11 or 12 or 13 or 14

what is the range of the following data 31,14,0,12,47?

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As height of tower is 50√3 m

Distance of observer 50 m

In a right angle triangle perpendicular and base is given.

and we know that from trigonometric ratio

tan thetha = perpendicular/ base

tan thetha = 50√3/50tan thetha = √3

angle of elevation = tan-1 (√3)angle of elevation = 60°

As mod value is always true that is

| x | = x , x is positive

So, |-4 | < |-5| is true

Second option is correct

4x^2 - 5 = 0(2x)^2 - (sqrt(5))^2 = 0

Using a^2 - b^2 = (a + b)(a - b)

(2x + sqrt(5))(2x - sqrt(5)) = 0

x = - sqrt(5)/2, sqrt(5)/2

Therefore, Zeroes are - sqrt(5)/2, sqrt(5)/2

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(4x+2)²= (4x)²+(2)²+2(4x)(2)= 16x²+4+16x= 4(4x²+4x+1)

(4x+2)×2 = 8x+4 = 4(2x+1)

square asil ne into2

Sum of these two vectors = 3i + 6j -2kunit vector parrell can be achieved by dividing it by its magnitude, √(3^2 + 6^ 2 +(-2)^2)=7unit vector parrell to it = 3/7i + 6/7j - 2/7k

Total cost price of 4 sweaters CP = 4*250 = 1000

Total selling price of 4 sweaters SP = 4*275 = 1100

Then, Profit % = [(SP - CP)/CP]*100= [(1100 - 1000)/1000]*100= 100/10= 10%

thanks

Profit = 275-250 = ₹ 25Profit percent = (25/250)*100 = 10%

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(4x×3-1)÷3+2-11x=0 12x-1+2-11x=0×3 so, x+1=0 answer

-67/156 is the correct answer of the given question

-(3/11×-5/6)=-(18×-55/66)=-(18×5/6)=-108/6=-18; -(9/12 × 4/3)=-(3/3)=-1; (5/13 × -6/15)=(-78/3)=(-26); -18-1-26=-45

numbers are conjugateso x^2+y=-3 so x^2=-3-yx^2y=-4(-3-y)y=-4-3y-y^2=-4y^2+3y-4=0(y+4)(y-1)=0so y=-4 or y=1if y=-4 then x=-3+4=1if y=1 then x=-3-1=-4

If they are in order ,then A+C = B+D

then , 6 + 9 = 8 + p (from x coordinates)p = 7

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thnx bro

20 drops of water in 1 min rate

(2-i)/(1-2i)^2=(2-i)/1-4-4i=(2-i)/(-3-4i) Rationalising=(2-i)*(-3+4i)/(-3-4i)(-3+4i)=-6+8i+3i+4/25=-2+11i/25hence they are complex conjugates

coordinate of S=(13/2,1)

slope of ps=(1-2)/13/2 -2)=(-1)/(9/2)=-2/9

Eq. of the line passing through (-1,1) and parallel to PS is

y-1=(-2/9)(x+1)

9(y-1)=-2x-2

9y-9+2x+2=0

2x+9y-7=0

thank u sir

When the vehicle is in motion,due to friction in air,the body of the vehicle gets charged.if accumulated,charge becomes excessive,sparking May occur and inflammable materials may catch fire.therefore metallic chains touching the ground are introduced so that the charge quickly leaks to the earth.hence the danger of fire is avoided.so,vehicles carrying inflammable materials usually have metallic ropes touching the ground during motion.

conduct charge to earth

Length is 10mBreadth is 5mHeight is 6mArea of 4 walls is 2(l+b)h=2*15*6 sq m=180Cost of painting 180*4Rs 720

a) 7:15

b) 9:30

c) 2:45

3×5x=? 3×5x=15