81279 + Interview Questions in Mathematics QA in Mathematics

1.	In a parking lot, 0.624 of the 125 vehicles were motorcycles and the rest were cars. How many cars were there?
Answer»

Discussion

2.	\frac{\sqrt{49}+\sqrt{64}}{\sqrt{289}-\sqrt{144}}
Answer» In this question answer is 3 In this question answer is 3 (√49 + √64)/(√289 - √144) = (7+8)/(17-12) = 15/5 = 3

2.

\frac{\sqrt{49}+\sqrt{64}}{\sqrt{289}-\sqrt{144}}

Answer»

In this question answer is 3

(√49 + √64)/(√289 - √144) = (7+8)/(17-12) = 15/5 = 3

Discussion

3.	WorksheetTO1. Add the following:TO TO2024+19 11TO22+17o no+31+ 302. Subtract the following:TO TO TO78- 24 -14 -32TO563 4ŃĐž86-26obje94-90TOMamalTOSte3. Solve these sums(a) In a shop, there are 48 red umbrellas and21 green umbrellas. How many umbrellasare there in the shop?(b) Out of 92 chocolates Rohan distributed 41chocolates in his class. How manychocolates are still left with Rohan?(c) There are 36 red cars and 22 white cars!parked under a parking area. How manycars are parked under the parking area?(d) Out of 54 flowers, Seema plucked 22. Howmany flowers are still there in the garden?!TOTO
Answer» a. 39 b. 35 c. 129 d.39 e. 65

Discussion

4.	ets of paper) costs Rs 175. How much does a sheet cost?6. In a parking lot, 0.624of the 125 vehicles were motorcycles and the rest were cars. How manycars were there?
Answer» If 0.624 were motocycles, then (1-0.624) will be cars = 0.376 so, no. of cars = 0.376 of (125) = 47 please explain it

4.

ets of paper) costs Rs 175. How much does a sheet cost?6. In a parking lot, 0.624of the 125 vehicles were motorcycles and the rest were cars. How manycars were there?

Answer»

If 0.624 were motocycles, then (1-0.624) will be cars = 0.376

so, no. of cars = 0.376 of (125) = 47

please explain it

Discussion

5.	A farmer planted cabbages in rows. Each row had 36 cabbages planted at regularintervals of 0.5 m.(a) How many spaces are there in each row?(b) What is the length of each row?
Answer» a) number of spaces = n - 1 = 36 - 1 = 35b) length of each row = 0.5 × 35 m = 17.5m

Discussion

6.	A farmer planted cabbages in rows. Each row had 36 cabbages planted at regularintervals of 0.5 m.(a) How many spaces are there in each row?(b) What is the length of each row?5.
Answer» a) number of spaces = n - 1 = 36 - 1 = 35b) length of each row = 0.5 × 35 m = 17.5m

Discussion

7.	4. The rectangle shown here represents a parking lot at a high school. The width of the parking lot is 66feet661The perimeter of the parking lot is 878 feet. What is the length of the parking lot?A 372 B 132 ft C 296 ft D 810 ft
Answer» Perimeter = 2(length + width) 876 = 2(length + 66)length + 66 = 876/2 = 438length = 438 - 66 = 372 feet Width(w)=66P=2(l+w)876=2*(l+66)876/2=l+66438=l+66So,l=438+66= 372feet 372 feet is the right answer. the right answer is 372feet

7.

4. The rectangle shown here represents a parking lot at a high school. The width of the parking lot is 66feet661The perimeter of the parking lot is 878 feet. What is the length of the parking lot?A 372 B 132 ft C 296 ft D 810 ft

Answer»

Perimeter = 2(length + width) 876 = 2(length + 66)length + 66 = 876/2 = 438length = 438 - 66 = 372 feet

Width(w)=66P=2(l+w)876=2*(l+66)876/2=l+66438=l+66So,l=438+66= 372feet

372 feet is the right answer.

the right answer is 372feet

Discussion

8.	Find the angle between the vectors 2 âkandihjvector product.
Answer»

Discussion

9.	\frac{\cos 37^{\circ}}{\sin 53^{\circ}}
Answer»

Discussion

10.	sin θ613537cos θtan θ
Answer»

Discussion

11.	dot product of a vector with vectors i^ + j^ +k^,i^ + 2j^ + 3k^ & i^ + 3j^ + 4k^ are 7 , 16 & 22 respectively. find vector.
Answer» Please refer to this similar solution!

Discussion

12.	cos(37circ)/sin(53circ)
Answer» cos 37°/sin 53° = sin(90 - 37)/sin 53° = sin 53°/sin 53° = 1

12.

cos(37circ)/sin(53circ)

Answer»

cos 37°/sin 53°

= sin(90 - 37)/sin 53°

= sin 53°/sin 53°

= 1

Discussion

13.	(16) Show thatcos θ + isin θ)'cos 3θ + isin 30
Answer» please give me correct answer

Discussion

14.	58, If A-1 cos θ i sin θi sin θ cos θthen prove by principle of mathematical induction thatn-[cos n θ isin nnisin n θ cos n θfor all n e N.[CBSE 2005]
Answer»

Discussion

15.	The fourth power of the common difference of an arithmetic progression wthe product of any four consecutive terms of it. Prove thaith integer entries is added totthe resulting sum is the square of an integer.A-7.a
Answer» unable to understand

Discussion

16.	19. Find three numbers in A.P., whose sum is 15 and the product is 80.Hist, let the required numbers be (a-d), a, (a + d).]uint, Tat tha r
Answer»

Discussion

17.	16. Find the value of k, if the points A (7,-2), B (5, 1) and C (3, 2k) are collinear[CBSE 20
Answer»

Discussion

18.	2. Isin its simplest form?\frac{49}{64}Fit
Answer» Yes, 49/64 is in simplest form, beacuse HCF(49, 64) = 1 HCF (49,64)49 = 7²64 = 4³So HCF is 1

18.

2. Isin its simplest form?\frac{49}{64}Fit

Answer»

Yes, 49/64 is in simplest form, beacuse HCF(49, 64) = 1

HCF (49,64)49 = 7²64 = 4³So HCF is 1

Discussion

19.	11) Express 1+ cos0-isin®in the form of a ibHint : sin-e + cos2θ-1
Answer»

Discussion

20.	1. Find the solution of 2sin-x + sin-2x-2
Answer» 2sin^2x+ (2sinx.cosx)^2=2 2sin^2x+4sin^2x.cos^2x=2 sin^2x+2sin^2x.cos^2x=1 2sin^2x.cos^2x= 1-sin^2x 2sin^2x.cos^2x= cos^2x 2sin^2x=1 sin^2x= 1/2 sinx= 1/√2 => x= pi/4 or 45 degrees Since the value of sinx repeats after every 180 deg turn, so....you would get the same value of sinx if you add pi to pi/4 or 2pi to pi/4. The solutions are countless. x= pi/4, 3pi/4 etc

20.

1. Find the solution of 2sin-x + sin-2x-2

Answer»

2sin^2x+ (2sinx.cosx)^2=2

2sin^2x+4sin^2x.cos^2x=2

sin^2x+2sin^2x.cos^2x=1

2sin^2x.cos^2x= 1-sin^2x

2sin^2x.cos^2x= cos^2x

2sin^2x=1

sin^2x= 1/2

sinx= 1/√2

=> x= pi/4 or 45 degrees

Since the value of sinx repeats after every 180 deg turn, so....you would get the same value of sinx if you add pi to pi/4 or 2pi to pi/4. The solutions are countless.

x= pi/4, 3pi/4 etc

Discussion

21.	9. (sin 221° + cos222)4虱丽9. Isin 22cos 22刊畝
Answer» Sorry for the inconvinience! We are currently answering only for the questions posted in english!

Discussion

22.	(UP 2004,05, 08)7. If x cos α + isin α.ν cosB+isinß, thenprove that r-y-i tan-. (UP 2004. 05. 15)
Answer» We will use the following formulas, which can be derived from the usual addition formulas:cos x - cos y = -2 sin ((x+y)/2) sin ((x-y)/2)cos x + cos y = 2 cos ((x+y)/2) cos ((x-y)/2)sin x - sin y = 2 cos ((x+y)/2) sin ((x-y)/2)sin x + sin y = 2 sin ((x+y)/2) cos ((x-y)/2) (x - y) / (x + y)= (cos a - cos b + i sin a - i sin b) / (cos a + cos b + i sin a + i sin b)= {[-2 sin ((a+b)/2) sin ((a-b)/2)] + i [2 cos ((a+b)/2) sin ((a-b)/2)]} / {[2 cos ((a+b)/2) cos ((a-b)/2)] + i [2 sin ((a+b)/2) cos ((a-b)/2)]}Divide top and bottom by 2 cos ((a-b)/2):= {[-sin ((a+b)/2) tan ((a-b)/2)] + i [cos ((a+b)/2) tan ((a-b)/2)]} / {[cos ((a+b)/2)] + i [sin ((a+b)/2)]}= {[tan ((a-b)/2)] [-sin ((a+b)/2) + i cos ((a+b)/2)]} / [cos ((a+b)/2) + i sin ((a+b)/2)]= {[tan ((a-b)/2)] [i] [i sin ((a+b)/2) + cos ((a+b)/2)]} / [cos ((a+b)/2) + i sin ((a+b)/2)]= [tan ((a-b)/2)] [i] / 1= i tan ((a-b)/2).

22.

(UP 2004,05, 08)7. If x cos α + isin α.ν cosB+isinß, thenprove that r-y-i tan-. (UP 2004. 05. 15)

Answer»

We will use the following formulas, which can be derived from the usual addition formulas:cos x - cos y = -2 sin ((x+y)/2) sin ((x-y)/2)cos x + cos y = 2 cos ((x+y)/2) cos ((x-y)/2)sin x - sin y = 2 cos ((x+y)/2) sin ((x-y)/2)sin x + sin y = 2 sin ((x+y)/2) cos ((x-y)/2)

(x - y) / (x + y)= (cos a - cos b + i sin a - i sin b) / (cos a + cos b + i sin a + i sin b)= {[-2 sin ((a+b)/2) sin ((a-b)/2)] + i [2 cos ((a+b)/2) sin ((a-b)/2)]} / {[2 cos ((a+b)/2) cos ((a-b)/2)] + i [2 sin ((a+b)/2) cos ((a-b)/2)]}Divide top and bottom by 2 cos ((a-b)/2):= {[-sin ((a+b)/2) tan ((a-b)/2)] + i [cos ((a+b)/2) tan ((a-b)/2)]} / {[cos ((a+b)/2)] + i [sin ((a+b)/2)]}= {[tan ((a-b)/2)] [-sin ((a+b)/2) + i cos ((a+b)/2)]} / [cos ((a+b)/2) + i sin ((a+b)/2)]= {[tan ((a-b)/2)] [i] [i sin ((a+b)/2) + cos ((a+b)/2)]} / [cos ((a+b)/2) + i sin ((a+b)/2)]= [tan ((a-b)/2)] [i] / 1= i tan ((a-b)/2).

Discussion

23.	1, Tatal number of solutions of 20sx= Isin xl in[-2%, 5Ď] is equal to(a) 12(b) 14(c) 16(d) 15
Answer» The graph of 2^cosx will cut \|sin x\| two times in interval of π , so total solutions will be 2×(5+2)=14hence option 2 how to draw graph of 2^cosx

23.

1, Tatal number of solutions of 20sx= Isin xl in[-2%, 5Ď] is equal to(a) 12(b) 14(c) 16(d) 15

Answer»

The graph of 2^cosx will cut |sin x| two times in interval of π , so total solutions will be 2×(5+2)=14hence option 2

how to draw graph of 2^cosx

Discussion

24.	integration of cos3x
Answer»

Discussion

25.	\frac{\sin x-\sin 3 x}{\sin ^{2} x-\cos ^{2} x}=2 \sin x
Answer»

Discussion

26.	sin5x +sin3x÷cos5x+cos3x=tan4x
Answer» Like my answer if you find it useful! good

26.

sin5x +sin3x÷cos5x+cos3x=tan4x

Answer»

Like my answer if you find it useful!

good

Discussion

27.	ntegratethe functio2x1.
Answer» thanks

Discussion

28.	\frac { \sin x - \sin 3 x } { \sin ^ { 2 } x - \cos ^ { 2 } x } = 2 \sin xx
Answer»

Discussion

29.	Bllowing functio\frac{x+1}{x^{2}+5 x+6}
Answer»

Discussion

30.	ă162a a-b-c2a2b2bc-a-b 2cb-c-a\|= (a + b + c)32c[CBSE 1
Answer»

Discussion

31.	34. If x = cosec A + cos A and y = cosec A-cos A then prove thatr+y
Answer»

Discussion

32.	d the range of the following functiof(x) 5+4cosx where x e R
Answer» the range would be 1 to 9 the range is 1to9 in

32.

d the range of the following functiof(x) 5+4cosx where x e R

Answer»

the range would be 1 to 9

the range is 1to9 in

Discussion

33.	up. In a triangle ABC, write cosä˝2C):15. In a triangle ABC, write cosB+C interms of angle A.ICBSE 2016]
Answer» We know in a triangle , A + B + C = 180 B + C = 180° - A (B+C)/2 = 90° - A/2 So, cos ( B+ C)/2 Cos ( 90 - A/2) sin ( A/2)

33.

up. In a triangle ABC, write cosä˝2C):15. In a triangle ABC, write cosB+C interms of angle A.ICBSE 2016]

Answer»

We know in a triangle ,

A + B + C = 180

B + C = 180° - A

(B+C)/2 = 90° - A/2

So,

cos ( B+ C)/2

Cos ( 90 - A/2)

sin ( A/2)

Discussion

34.	1 - cos 21+ cos 2c37. Evaluatedx.
Answer» Please like 👍✔️ the solution

Discussion

35.	EXERCISE 2C1. Write down the reciprocal of(1) 7(iv) 12..
Answer» 1. 8/52. 1/73. 12/1 4. 5/63 1.8/52.1/73.12/14.5/63 18/52.1/73.124.5/63 1. 8/52. 1/73. 12/1 4. 5/63

35.

EXERCISE 2C1. Write down the reciprocal of(1) 7(iv) 12..

Answer»

1. 8/52. 1/73. 12/1 4. 5/63

1.8/52.1/73.12/14.5/63

18/52.1/73.124.5/63

1. 8/52. 1/73. 12/1 4. 5/63

Discussion

36.	Show that the points with position vectors 5 a+6.78 b and 3 a+ 20 b arecollinear.144-220b are
Answer»

Discussion

37.	what that the points A,B,C with poistion vectors (3i^_2j^+4k^) ,(i^+j^+k^) and (-i^+4j^_2k^) respectively are collinear.
Answer»

Discussion

38.	7. If the vectors 2i -3i+k and 4i +mi +2k ae collinear then m is a) -6, b) 3, c)-3, d) 6.
Answer» if they are collinear then their ratio of components must be sameso2/4=-3/m =>m=-6

Discussion

39.	EXERCISE 6.21. Which is greater?(i) 1.07 or 1.076(iv) 46.13 or 38.98(ii) 12.356 or 12.4(v) 1.006 or 1.6Represent the numbers on the number line 0Between which two whole numbers on the nonumber is nearer to the given number?(i) 0.8(ii) 7.84. Convert the following unlike decimals into(1) 2.1, 1.25, 1.284, 1.2(iii) 4.12, 4, 4.2155. Rewrite in ascending order :(i) 18, 17.9, 18.02, 18.6(iii) 1.2, 0.8, 1.08, 1.208CONVERSION OF DECIMAL INTCTo convert a decimal number into a fractionStep 1 : Write the given number withoutStep 2 : In the denominator, write 1 foll
Answer»

Discussion

40.	sia GoP cs30+sin 30 cos 60sec 30° + coses 300S cos 6o° +4 sec 30-tan 45cos 45sin 30° +tan 45 - coses ssec 30° + cos+ col49lo)sin 30° +cos 30°
Answer»

Discussion

41.	lllterniisoftheheight.ena, Beeña and Leena are climbing thes to the hill top. Meena is at step s, Beenais 8 steps ahead and Leena 7 steps behind.Where are Beena and Meena? The total numberof steps to the hill top is 10 less than 4 timeswhat Meena has reached. Express the total(d) Meenumber of steps using s.
Answer» Step at which Beena is = (Step at which Meena is) + 8 =s+ 8 Step at which leena is = (Step at which Meena is) − 7 =s− 7 Total steps = 4 × (Step at which Meena is) − 10 = 4s− 10

41.

lllterniisoftheheight.ena, Beeña and Leena are climbing thes to the hill top. Meena is at step s, Beenais 8 steps ahead and Leena 7 steps behind.Where are Beena and Meena? The total numberof steps to the hill top is 10 less than 4 timeswhat Meena has reached. Express the total(d) Meenumber of steps using s.

Answer»

Step at which Beena is = (Step at which Meena is) + 8

=s+ 8

Step at which leena is = (Step at which Meena is) − 7

=s− 7

Total steps = 4 × (Step at which Meena is) − 10 = 4s− 10

Discussion

42.	\operatorname { cos } x + \operatorname { cos } 3 x + \operatorname { cos } 5 x + \operatorname { cos } 7 x = 4 \operatorname { cos } x \operatorname { cos } 2 x
Answer» LHS=cos x+cos 3x+cos 5x+cos 7x=cos x + cos(7x) + cos(3x) + cos(5x)=cos(4x - 3x) + cos(4x + 3x) + cos(4x - x) + cos(4x + x)= 2 cos(4x)cos(3x) + 2cos(4x)cos(x) (Using the formula 1)= 2 cos(4x) [cos(3x) + cosx]= 2 cos(4x)[cos(2x + x) + cos(2x - x)]= 2cos(4x)[2cos(2x)cosx] (Using the formula 1)=4 cos(4x) cos(2x) cos(x) = 4cosxcos2xcos4x = RHS

Discussion

43.	19. The value of 30+30+ 30-+.
Answer»

Discussion

44.	4. Find the projection of the vector i +3j+7k on the vector 7i-j+8k
Answer»

Discussion

45.	and (4, 24).9. Find the value of k for which the line(k - 3) x (4 -k2) y +2 -7k 6 0 passes through(H.P.B. 2017the origin.
Answer» Thanks 😘 😘

Discussion

46.	Q4. Harpreet's motorbike is facing towards West. He turns left anddrives 10 km and turns left again and drives 10 km. Then he turns rightand drives 40 km. He turns right again and drives 30 km. lastly; he turnsright and drives 50 km. How far is Harpreet from the starting point?
Answer» Ending and starting point are on the same line and they are 20kms away from each other.

Discussion

47.	EXERCISE 13.1ss stated otherwise, take Ď-7cubes each of volume 64 cm3 are joined end to end. Determinsulting cuboid.
Answer» Given, volume of each cube is 64 cm³⇒s³=64⇒s=∛64⇒s=4 cm.When two cubes are joined ,the length of the resulting cuboid(l) = side + side = 4+4 = 8 cmits breadth(b) = side = 4cmAnd its height(h) = side = 4cmTotal surface area of a cuboid = 2(lb+bh+hl)⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]⇒TSA=2(32+16+32)⇒TSA = 2(80)⇒TSA = 160 cm²∴ The surface area of the resulting cuboid is 160 cm².

Discussion

48.	Q4. Harpreet's motorbike is facing towards West. He turns len anddrives 10 km and turns left again and drives 10 km. Then he turns rightand drives 40 km. He turns right again and drives 30km. lastly, he turnsright and drives 50 km. How far is Harpreet from the starting point?I310 km40 km
Answer»

Discussion

49.	Find an anti derivative (or integral of the following functions by the method of inspection.1. sin 2x2. cos 3x3. e^2x
Answer»

Discussion

50.	EXERCISE 7.1(or integral) of the following functio3.2. cos 3x5. sin 2x -4 eegrals in Exercises 6 to 20:2
Answer» 2.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

In a parking lot, 0.624 of the 125 vehicles were motorcycles and the rest were cars. How many cars were there?

\frac{\sqrt{49}+\sqrt{64}}{\sqrt{289}-\sqrt{144}}

ets of paper) costs Rs 175. How much does a sheet cost?6. In a parking lot, 0.624of the 125 vehicles were motorcycles and the rest were cars. How manycars were there?

A farmer planted cabbages in rows. Each row had 36 cabbages planted at regularintervals of 0.5 m.(a) How many spaces are there in each row?(b) What is the length of each row?

A farmer planted cabbages in rows. Each row had 36 cabbages planted at regularintervals of 0.5 m.(a) How many spaces are there in each row?(b) What is the length of each row?5.

4. The rectangle shown here represents a parking lot at a high school. The width of the parking lot is 66feet661The perimeter of the parking lot is 878 feet. What is the length of the parking lot?A 372 B 132 ft C 296 ft D 810 ft

Find the angle between the vectors 2 âkandihjvector product.

\frac{\cos 37^{\circ}}{\sin 53^{\circ}}

sin θ613537cos θtan θ

dot product of a vector with vectors i^ + j^ +k^,i^ + 2j^ + 3k^ &amp; i^ + 3j^ + 4k^ are 7 , 16 &amp; 22 respectively. find vector.

cos(37**circ)/sin(53**circ)

(16) Show thatcos θ + isin θ)'cos 3θ + isin 30

58, If A-1 cos θ i sin θi sin θ cos θthen prove by principle of mathematical induction thatn-[cos n θ isin nnisin n θ cos n θfor all n e N.[CBSE 2005]

The fourth power of the common difference of an arithmetic progression wthe product of any four consecutive terms of it. Prove thaith integer entries is added totthe resulting sum is the square of an integer.A-7.a

19. Find three numbers in A.P., whose sum is 15 and the product is 80.Hist, let the required numbers be (a-d), a, (a + d).]uint, Tat tha r

16. Find the value of k, if the points A (7,-2), B (5, 1) and C (3, 2k) are collinear[CBSE 20

2. Isin its simplest form?\frac{49}{64}Fit

11) Express 1+ cos0-isin®in the form of a ibHint : sin-e + cos2θ-1

1. Find the solution of 2sin-x + sin-2x-2

9. (sin 221° + cos222)4虱丽9. Isin 22cos 22刊畝

(UP 2004,05, 08)7. If x cos α + isin α.ν cosB+isinß, thenprove that r-y-i tan-. (UP 2004. 05. 15)

1, Tatal number of solutions of 20sx= Isin xl in[-2%, 5Ď] is equal to(a) 12(b) 14(c) 16(d) 15

integration of cos3x

\frac{\sin x-\sin 3 x}{\sin ^{2} x-\cos ^{2} x}=2 \sin x

sin5x +sin3x÷cos5x+cos3x=tan4x

ntegratethe functio2x1.

\frac { \sin x - \sin 3 x } { \sin ^ { 2 } x - \cos ^ { 2 } x } = 2 \sin xx

Bllowing functio\frac{x+1}{x^{2}+5 x+6}

ă162a a-b-c2a2b2bc-a-b 2cb-c-a|= (a + b + c)32c[CBSE 1

34. If x = cosec A + cos A and y = cosec A-cos A then prove thatr+y

d the range of the following functiof(x) 5+4cosx where x e R

up. In a triangle ABC, write cosä˝2C):15. In a triangle ABC, write cosB+C interms of angle A.ICBSE 2016]

1 - cos 21+ cos 2c37. Evaluatedx.

EXERCISE 2C1. Write down the reciprocal of(1) 7(iv) 12..

Show that the points with position vectors 5 a+6.78 b and 3 a+ 20 b arecollinear.144-220b are

what that the points A,B,C with poistion vectors (3i^_2j^+4k^) ,(i^+j^+k^) and (-i^+4j^_2k^) respectively are collinear.

7. If the vectors 2i -3i+k and 4i +mi +2k ae collinear then m is a) -6, b) 3, c)-3, d) 6.

sia GoP cs30+sin 30 cos 60sec 30° + coses 300S cos 6o° +4 sec 30-tan 45cos 45sin 30° +tan 45 - coses ssec 30° + cos+ col49lo)sin 30° +cos 30°

\operatorname { cos } x + \operatorname { cos } 3 x + \operatorname { cos } 5 x + \operatorname { cos } 7 x = 4 \operatorname { cos } x \operatorname { cos } 2 x

19. The value of 30+30+ 30-+.

4. Find the projection of the vector i +3j+7k on the vector 7i-j+8k

and (4, 24).9. Find the value of k for which the line(k - 3) x (4 -k2) y +2 -7k 6 0 passes through(H.P.B. 2017the origin.

Q4. Harpreet's motorbike is facing towards West. He turns left anddrives 10 km and turns left again and drives 10 km. Then he turns rightand drives 40 km. He turns right again and drives 30 km. lastly; he turnsright and drives 50 km. How far is Harpreet from the starting point?

EXERCISE 13.1ss stated otherwise, take Ď-7cubes each of volume 64 cm3 are joined end to end. Determinsulting cuboid.

Q4. Harpreet's motorbike is facing towards West. He turns len anddrives 10 km and turns left again and drives 10 km. Then he turns rightand drives 40 km. He turns right again and drives 30km. lastly, he turnsright and drives 50 km. How far is Harpreet from the starting point?I310 km40 km

Find an anti derivative (or integral of the following functions by the method of inspection.1. sin 2x2. cos 3x3. e^2x

EXERCISE 7.1(or integral) of the following functio3.2. cos 3x5. sin 2x -4 eegrals in Exercises 6 to 20:2

Find the angle between the vectors 2 âkandihjvector product.

dot product of a vector with vectors i^ + j^ +k^,i^ + 2j^ + 3k^ & i^ + 3j^ + 4k^ are 7 , 16 & 22 respectively. find vector.

cos(37circ)/sin(53circ)

1, Tatal number of solutions of 20sx= Isin xl in[-2%, 5Ď] is equal to(a) 12(b) 14(c) 16(d) 15

ă162a a-b-c2a2b2bc-a-b 2cb-c-a|= (a + b + c)32c[CBSE 1

up. In a triangle ABC, write cosä˝2C):15. In a triangle ABC, write cosB+C interms of angle A.ICBSE 2016]

EXERCISE 13.1ss stated otherwise, take Ď-7cubes each of volume 64 cm3 are joined end to end. Determinsulting cuboid.