Saved Bookmarks
| 1. |
1. Find the solution of 2sin-x + sin-2x-2 |
|
Answer» 2sin^2x+ (2sinx.cosx)^2=2 2sin^2x+4sin^2x.cos^2x=2 sin^2x+2sin^2x.cos^2x=1 2sin^2x.cos^2x= 1-sin^2x 2sin^2x.cos^2x= cos^2x 2sin^2x=1 sin^2x= 1/2 sinx= 1/√2 => x= pi/4 or 45 degrees Since the value of sinx repeats after every 180 deg turn, so....you would get the same value of sinx if you add pi to pi/4 or 2pi to pi/4. The solutions are countless. x= pi/4, 3pi/4 etc |
|