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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(vii) (-60)-((viii) (-31)+()=-59)=-40 |
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Answer» (-60)-x=-59X=-60+59=-1-13+X=-40X=-40+13=-27 |
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| 2. |
find the sum of 1005 and -277 |
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Answer» 728 is correct answer..... 728 the correct answer of the given question 728 is the answer...... 728 is the right answer 728 is the right answer 728 is the right answer 728 is the right answer 728 is the correct answer 728 is the right answer |
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| 3. |
यदि (3,2) समीकरण ३४-KY-5 का हल है तब रका मान है-(4)1(b) ३(C) 4(d) 2 |
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Answer» hope you understand it please like it as a best (d) 2 3x - Ky = 5 x = 3, y = 2 => 3(3) - K(2) = 5=> 9 - 2K = 5=> 2K = 4=> K = 2 k=2. is answer d is the right abswer |
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| 4. |
21tARX = Y COS-= Z COS--, thenky + yz + ZX =(A)-1(C) 1(B) O(D) 2 |
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| 5. |
Ex. 10: Find the value of k so that the lines3x-y-2 0, 5x + ky - 3-0 and 2x ty-3-0are concurrent. |
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| 6. |
Check the divisibility of the following numbers both by 5 and 10:100, 130, 155, 20003, 2695, 1005, 6007 |
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Answer» If the number ends with 0 it is divisible by both 5 and 10. So, then numbers divisible are 100 and 130 only. |
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| 7. |
6. How many whole numbers are there between(i) 6 and 54(ii) 1005 and |
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Answer» 54-6=48 whole nmbrs are there in between 54 and 6 54-6=48 whole numbers are there in between 54 and 6 54-6-1=47whole numbers are there in between 54 n 6. |
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| 8. |
Ex.1. The arithmetic mean of runs scored by3 batsmen Varad, Viraj and Akhilesh in thesame series are 50, 58 and 21 respectively. Thestandard deviation of their runs are 11, 16 and 5respectively. Who is the most consistent of thethree? If one of the three is to be selected, whowill be selected? |
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Answer» akhilesh is most consistent of the three and if one is to be selected , viraj will be selectedis the answer viraj will be selected. |
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| 9. |
Sagar and Aakash ran 2 km race twice. Aakash completed the first round 2 minutesier than Sagar. In the second round Sagar increased his speed by 2 km/ hour andreduced his speed by 2 km/hour Sagar finished 2 minutes earlier than AakashAakashFind their speeds of running in the first round. |
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Answer» Let the speed ofSagar be considered as x km/hr.And speed of Aakash be y km/hr.Therefore, time taken by Sagar = 2/x hrs.And time taken by Aakash = 2/y hrs.Now, according to the question.2/x - 2/y = 2/601/x - 1/y = 1/60 ..................(1)(y - x)/xy = 1/6060(y - x) = xy ...................(2) Now, according to the second condition.Speed of Sagar = (x + 2) km/hr.Speed of Aakash = (y - 2) km/hr⇒ (2/y-2) - (2/x+2) = 2/60⇒ (1/y-2) - (1/x+2) = 1/60⇒ {(x+2-y+2)/(y-2)(x+2)} = 1/60⇒ 60(x-y+4) = xy+2y-2x-4Now, substituting the value of xy in the above, we get.⇒ 60(x-y+4) = 60(y-x)+2y-2x-4⇒ 30(x-y+4) = 30(y-x)+y-x-2⇒ 30x-30y+120 = 30y-30x+y-x-2⇒ 30x+31x-30y-31y = -2-120⇒ 61x-61y = -122⇒ x-y = -2⇒ x = y-2Substituting the value of x in (1), we get.⇒ {1/(y-2) - (1/y) } = 1/60⇒ (y-y-2)/(y²-2y) = 1/60⇒ y²-2y = 120⇒ y²-2y-120 = 0⇒ y²+10y-12y-120 = 0⇒ y(y+10) -12(y+10) = 0⇒ (y+10) (y-12) = 0⇒ y = -10 is not possible. So, y = 12 is correct value.Substituting the value of y = 12 in x = y - 2, we get.⇒ x = 12 - 10⇒ x = 10So, speed of Sagar in the first round was 10 km/hr and speed of Aakash was 12 km/hr. |
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| 10. |
l decimalat 6 a.m. and stopped in between for 30 minutes. It reached Nagur a6:30p.m. on the same day,.ifithe total distance covered bythe busis 300 km findtre speesof the bus. |
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Answer» Speed = Distance / TimeDistance = 300kmTime = 12 hoursSpeed = 300/12= 25 km/hr PLEASE HIT THE LIKE BUTTON |
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| 11. |
10. Manish drove to his friend's house. He left at 11:30 a.m. and reached at 5.20 p.m. Howmany hours and minutes did the journey take? |
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Answer» 5 HR 49 min takes by manish |
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| 12. |
CLASS-VIII) |
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Answer» 3/8 is the answer of 3/8 is correct answer of1/2 × 3/4 3/8 is the correct answer of the given question 3/8 is the answer of 1/4 × 3ufuf 3/8 is the correct answer 3/8 is the correct answer correct answer is 3/8 3/8 is the correct answer 3/8 is the correct answer 3/8 is the correct answer |
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| 13. |
(viii) 0.163 |
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| 14. |
and Ro.let A f62,3,4,5,453be the relation defined as 'is Squareon A-Wuhe Ras a subset ofAxa also send the domain andpage of R. |
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Answer» A=[1,2 ,3,4____45] squares=(1, 4. 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, ) A[1,2,3,4_ 45 ] square= (1,4,9,16,25,36,38,49 ) A (1,2,3,4_45) square =(1,4,9,16,25,36,38,49) is the correct answer |
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| 15. |
f 69. The sum of the seriest.00 is1x3 3x5 5x7ISequal to |
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| 16. |
( \frac { \operatorname { tan } 60 ^ { \circ } + 1 } { \operatorname { tan } 60 ^ { \circ } - 1 } ) ^ { 2 } = \frac { 1 + \operatorname { cos } 30 ^ { \circ } } { 1 - \operatorname { cos } 30 ^ { \circ } } |
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| 17. |
\frac { \operatorname { sin } \theta \operatorname { cos } ( 90 ^ { \circ } - \theta ) \operatorname { cos } \theta } { \operatorname { sec } ( 90 ^ { \circ } - \theta ) } + \frac { \operatorname { cos } \theta \operatorname { sin } ( 90 ^ { \circ } - \theta ) \operatorname { sin } } { \operatorname { cosec } ( 90 ^ { \circ } - \theta ) } |
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| 18. |
() 3x-2y=27x+3y=43 |
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Answer» 3x - 2y = 2 7x + 3y = 43 Multiply first equation by 3 and second equation by 2 and add both the equation. 9x - 6y + 14x + 6y = 6 + 86 23x = 92 x = 4 3*4 - 2y = 2 2y = 12 - 2 2y = 10 y = 5
If you find this answer helpful then like it. |
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| 19. |
3y + 7/3 = 43/3 |
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| 20. |
l, Find the value of 'k for which the system of equations+3y 1,12x + ky 2 has nosolution. |
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| 21. |
Without using trigonometric tables, evaluate:\frac{3 \tan 25^{\circ} \tan 40^{\circ} \tan 50^{\circ} \tan 65^{\circ}-\frac{1}{2} \tan ^{2} 60^{\circ}}{4\left(\cos ^{2} 29^{\circ}+\cos ^{2} 61^{\circ}\right)} |
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| 22. |
\cos 60 ^ { \circ } = \frac { 1 - \tan ^ { 2 } 30 ^ { \circ } } { 1 + \tan ^ { 2 } 30 ^ { \circ } } |
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| 23. |
Mathematics - VIII40/ |
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| 24. |
(viii(-a + c)(-a + c) |
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Answer» -a(-a+c)+c(-a+c)a square-ac-ac+c squarea square-2ac +c square -a(-a+c)+c(-a+c)a square-ac-ac+c squarea square-2ac+c square |
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| 25. |
(viii) Rs.105.00+15 |
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Answer» 1). 105.00/15 is answer is (7) |
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| 26. |
(viii) 3x-52-12 |
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| 27. |
(viii) 25x2 30x+7-0 |
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| 28. |
(viii) 6y - 6 рди 60 |
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Answer» If you like the solution, Please give it a 👍 |
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| 29. |
8 Find a number wRICR RAS Itlfx, y, s are in proportion, find xify-6and ะะไ2. |
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Answer» x/y=y/z;x/6=6/12;x=3 |
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| 30. |
atem' 5 60° —2sin30° || cot 45° cosec30°45° cos 0° sec 60° sin 90°(10CLE 160™ |
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Answer» hit like if you find it useful |
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| 31. |
Compare the equations $\frac{x}{3}+\frac{3}{2} y+4=2 y-3$ and $6 x+m y-n=0$ and write the value of $\ell, m$ and $n$ |
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| 32. |
sec(60)/cot(45) %2B tan(45)/((30*cosec)) - 2*sin(90)/cos(60) |
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Answer» tan 45/ cosec 30 + sec60/cot45-2 sin90/ cos60= 1/2 +2/V3/1 - 2(1)/1/2=1//2+2/V3-4=2+2/V3-4=2v3-2 |
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| 33. |
sec(60^circ)/cot(45^circ) %2B tan(45^circ)/((30^circ*cosec)) - 5*sin(90^circ)*1/(2*cos(0^circ)) |
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| 34. |
Express each of the following ratios in simplest form(i) 24: 40(ii) 13.5 15 |
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| 35. |
1095/1168when expressed in simplest form is:(a) 13/16(b) 15/16(c) 17/29(d) 25/26 |
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Answer» option b) 15/16 is simplest form |
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| 36. |
ell borss 1,3,5,1,9, 1,13,15 |
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Answer» 11+13 + 3!(=6) = 30 3! = 3*2*1 = 6 nahi samajh mein Aaya Aap kya bhej |
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| 37. |
MATASw Eunlado.(32375.(A) 2 (B) u (c) 8 (0)16. |
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| 38. |
. (v) 9.90(vi) 1.UUUT2. Express each of the following decimals in the form(1) 0.3 (i) 0.37 (ii) 0.54 (iv) 0.621(v) 125.3 (vi) 4. (wi 0.47 INCERT] |
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| 39. |
\ell . c . m \cdot ( 15,24,40 ) = |
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Answer» 15 =( 3×5 )24 = 2×122×2×6(2×2×2×3 )40 = 2×202×2×10(2×2×2×5)3 common number = no2 common number = 2,2,2,5,3non common = no 2×2×2×3×5 = 120 |
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| 40. |
Jyoti and Sushma together can do a piece of work in 6 days and Sushma alone can do the samework in 9 days. In how many days can Jyoti alone complete the work ?Naresh and y |
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| 41. |
daul anmgles 0F a par allelogram are in the ratio 4 : 5. Find the meadjĂĄÄellangles. |
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| 42. |
x+5 xx +9 x- 20ell: |
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Answer» (x+5)(x-2)-x(x+9)=0 x²+3x-10-x²-9x=0 -6x=10 x=-5/3 |
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| 43. |
28. The equation of the straight line cutting off an intercept 8 on x axis andmaking an angle of 60° with the positive direction of y-axis is |
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Answer» Y= mx+cm= tan 60°m= √3y= √3x+8please like the solution 👍 ✔️ |
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| 44. |
40. Find the equation of the straight lines passing through the originInter 90making an angle 45 with straight line 3x + y 11. |
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| 45. |
Equation of the straight line making equal intercepts on the axes and passing through the point (2,4) is(a)17.4x-y-4=0(b) 2x ty-8 0(d) x+2y-10-0C)x+y-6=0 |
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Answer» Let the equation of the line be x/a + y/a =1 since it passes through (2,4) 2/a +4/a = 1 6/a = 1 , this implies a = 6 Hence the equation of the line is x+y = 6 |
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| 46. |
9. Find the equation of the straight line passing through (3, -2) andmaking an angle of 60 with the positive direction of y-axis, |
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| 47. |
EXERCISE 10.11.Express each of the following as fractions in the simplest form15(i)75%(ii) 0.25%(iii)-%(iv)140%2 |
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Answer» 1)75/100 = 3/42).25/100 = 1/4003) (15/2)÷100 = 3/404) 140/100 = 7/5 |
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| 48. |
2. Find the value of a, for which the polynomial 2x2 + ax +v2 has 1 asits zero. |
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Answer» hit like if you find it useful |
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| 49. |
3. From A point on the field the angle of elevation ofa tower is θ , tan θ =-After coming12192m towards the tower theangle of elevation φ and tan-find the height of the tower.12 |
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| 50. |
10. Iftan 2Aan24- cot(A-12°), where 2A is an acute angle, find the value oncute angle, find the value |
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