1.

यदि (3,2) समीकरण ३४-KY-5 का हल है तब रका मान है-(4)1(b) ३(C) 4(d) 2

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(d) 2

3x - Ky = 5

x = 3, y = 2

=> 3(3) - K(2) = 5=> 9 - 2K = 5=> 2K = 4=> K = 2

k=2. is answer

d is the right abswer



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