This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
= \frac x %2B 3 x %2B 2 = \frac 3 x - 7 2 x - 3 , x \neq - 2 , \frac 3 2 |
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| 2. |
\frac { 3 x - 2 } { 2 x - 3 } \leq \frac { 3 x - 8 } { x + 4 } |
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| 3. |
solve the following:√5+√13+√5+√16 |
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| 4. |
Find HCF of 81 and 237 and express it as a linearcombination of 81 and 237 ie., HCF (81, 237)81x + 237y for some x and y. |
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Answer» By Euclid's Division Algorithm, 237=81(2)+(75) 81=75(1) + (6) 75=6(12)+(3) 6=3(2)+(0) HCF =3 Expressing it in the form of 237x+81y=HCF 3=75-6(12) { From 2nd last step} 3=75-(81-75)(12) {Substituting} 3=75-(81×12-75×12) 3=75-81×12+75×12 3=75(13)-81(12) 3=(237-81×2)(13)-81(12) 3=237(13)-81(38) 3 = 237 (13) + 81 (-38) {we need an expression in the form 237x + 81y }Therefore, x =13 , y =- 38
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| 5. |
02x+03y=1304x+05y=23 |
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Answer» 0.2x + 0.3y = 1.3 0.4x + 0.5y = 2.3 Multiply 1st equation by 2 and subtract 2nd equation from 1st 0.4x + 0.6y - 0.4x - 0.5y = 2.6 - 2.3 0.1y = 0.3 y = 3 Put value of y in 1st equation 0.2x + 0.3×3 = 1.3 0.2x + 0.9 = 1.3 0.2x = 1.3-0.9 0.2x = 0.4 x = 2 If you find this answer helpful then like it. |
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| 6. |
6.02x + 0.1Ń 252(x 2) - 1.6y 116 |
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Answer» thanks |
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| 7. |
T Addthe following5and9 |
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Answer» 5/9 + (-7/9) 5/9 - 7/9 (5 - 7)/9 -2/9 |
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| 8. |
4. Simplify the following.5-11- |
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Answer» After simplifying17/7*35/6÷34/385/6÷34/385*3/34*6 45thanks After simplifying17/7*35/6÷34/385/6÷34/385*3/34*645 is the answer 17/7*35/6÷34/3 85/6÷34/3 85*3/34*6 =45 please like me |
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| 9. |
(d) 02x+0.3y= 1.304x+0.5y=2.3 |
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| 10. |
(iv) 02x + 0.3y 1.30.4x +0.5y 2.3 |
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Answer» 0.2x + 0.3y = 1.3 , on multiplying it with 2 => 0.4x + 0.6y = 2.6 and other equation is 0.4x + 0.5y = 2.3 subtracting 2 from 1 => 0.6y - 0.5y = 2.6 -2.3 => y = 0.3/0.1 = 3 and then x = (2.6-1.8)/0.4 = 0.8/0.4 = 2 |
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| 11. |
VEDNESDAY2018 W36 248-17dhe non pasaliel sides ea taqpe2iomone eual paove thatit is cycli |
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Answer» InΔAED andΔBFC,AD = BC (Given)DE = CF (Distance between parallel sides is same)∠AED = ∠BFC= 90°ΔAED ≅ ΔBFC (RHS Congruence criterion) Hence ∠DAE = ∠CBF (CPCT) … (1)Since AB||CD, AD is transversal∠DAE + ∠ADC = 180° (Sum of adjacent interior angles is supplementary)⇒∠CBF + ∠ADC = 180° [from (1)] Since sum of opposite angles is supplementary in trapezium ABCD.Thus ABCD is a cyclic trapezium |
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| 12. |
Textbook Page No. 7wer the questaeof a factoryGraph:6Try These : 1• Study the following frequency distribution table and answer thgiven below:Frequency distribution of daily income of 550 workers ofClass intervalFrequency(Daily income in?)(Number of workers)100 - 12545125 - 15025150-17555175 - 200125200 - 225140225 - 25055250-27535275-30050300 - 32520Total550ADRESInsara Platinum(1) What is the size of the class intervals?The size of class intervals.(ii) Which class has the highest frequency?(iii) Which class has the lowest frequency?(iv) What is the upper limit of the class interval 250 - 275 ?(v) Which two classes have the same frequency? |
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Answer» 1) class intervals2) 200-2253) 300-3254) 2755)150-175,225-250 |
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| 13. |
is aparallelogram in which A -110. Find the measure of each of the anglesJ, ABCDB, LC and ZD.to narelleloram are eual. What is the measure of each of |
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| 14. |
the society still short of?15. A man had 10672540 with him. He gave 4836980 to his wife,540 with him. He gave 4836980 to his wife, 3964790 to his son andthe rest to his daughter. How much money was received by the daughter |
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| 15. |
man nad 10672540 with him. He gave 4836980 to his wife, 3964790 to his son ande rest to his daughter. How much money was received by the daughter |
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| 16. |
Karan has n chocolates. He gave his younger brother 5 chocolates and distributed the remaequally between his friend and himself. How many chocolate did his friend get in terms of n? |
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Answer» answer is n+5÷total friends+1 |
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| 17. |
Karan has n chocolates. He gave his younger brother 5 chocolates and distributed the requally between his friend and himself. How many chocolate did his friend get in terms of9. |
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Answer» Karan has n chocolateshe gave 5 to younger brother=n-5distributed to his friendshencen-5/2 |
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| 18. |
cos x=-1/2 x lies in third quadrant |
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| 19. |
। Glodate HCF 8 3 R e |
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Answer» HCF(3³ × 5, 3² × 5²) = 3² × 5 = 45 |
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| 20. |
\cos x=-\frac{1}{2}, x lies in third quadrant. |
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| 21. |
Example 6 If cos x = - - , x lies in the third quadrant, find the values of other fivetrigonometric functions. |
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| 22. |
Example 6 If cos x - -..x lies in the third quadrant, find the values of other fivetrigonometric functions. |
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| 23. |
How Silk Routes link the world? |
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Answer» 1.The silk route connected China to Europe. Chinese silk and Chinese pottery travelled through theses routes. 2. Historians have identified many silk routes in Asia, linking Asia to North Africa. This created a pre- trade system. Indian textiles and spices and Chinese pottery from Southeast Asia travelled to Europe and North Africa. 3. Early Christian Missionaries and later Muslim Preachers travelled through these routes. Buddhist Missionaries used to travel India to China through these routes and Chinese Buddhist used to travel India through these routes. |
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| 24. |
e HCF and LCM of the following5' 5 20 |
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| 25. |
find the HCF of 240 & 228 by E. D. A? |
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| 26. |
20. The coefficient of correlation whencoefficients of regression are 02and 18 is/a) 036(b) 02ic) 06íd) 0-g |
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Answer» aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa given:bxy=0.2byx=1.8 Option (C) is correct |
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| 27. |
Find the HcF e, ko and 432 using Eualand 32 using |
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| 28. |
e. Find the HCF of 45, 60 and 75 using division method. |
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Answer» The HCF of 45,60 and 75 is 15 I Hope this will help you...... 45 =( 3)×3×(5)60=2×2×(3)×(5) 75=(3)×(5)×5Now , the HCF is 3×5=15 45=(3)×3×(5)60=2×2×(3)×(5)75=(3)×(5)×5It's HCF is 3×5=15 |
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| 29. |
1148) (1552)1334.Calculate the correlation coefficient between X and Y and corelationship:mment on2.244 |
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| 30. |
Which is the best linear model, or linear regression, for the data?O y=-621.8x + 16.4Oy=ax + by= 16.4x - 621.8. This data is not linear. |
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Answer» All fo theae are lineras they followy = mx+c |
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| 31. |
If 1|| m, find the values of the unknown angles in thefigure given below7.70°125°P 125 |
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| 32. |
In Fig. 6.35, Δ ODC-d OBA, < BOC = 125。andz CDO-70°. Find < DOC, < DCO and介ーーーーーーーーーOAB.。125Diagonals AC and BD of a trapezium ABCD |
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| 33. |
ङ) निम्न चित्र मेंAODCNAOBADZBOC=125 तथाZCDO= 70°LOAB = ? |
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Answer» 55 degrees is the right answer 55° is the correct answer to this question . 55° is the correct answer of the given question 55°...because angle BOC=angle AOD..then circle =360°..so angle DOC=angle AOB=55°..then sum of all angles in ∆ AOB =180°,then angle OAB = 55° <BOC=<AOD(VERTICALLY OPPOSITE ANGLE )=125LET <DOC=X= <AOB(IT IS ALSO VERTICALLY OPPOSITE ANGLE)X+X+125+125=360(Angle on a point)2x= 360-250x= 110/2=55°<DOC+<ODC+<OCD=180 (sum of internal angle of ∆ is 180)70+55+<OCD=180<OCD= 180-125= 55°<D= <B= 70℃<A=<C=55°<OAB=55° 55° is the right answer angle a aob =55 by using suitable properties |
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| 34. |
EXERCISE 3.21.Find x in the following figures.125°60f70°1250 |
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Answer» (a) x+125+125=360x+250=360x=360-250 =110(b) x+90+60+90+70=360x+310=360x =360-310 =50 |
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| 35. |
12しー11111-2」48 23 1011.Arithmetic mean of two nunbers is 5. If one number is 6, find the other number. |
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Answer» mean = sum of no.s/ total no.sgiven mean=5one no. is 6let other be xthen5=(6+x)/210=6+xx=4 Thanks |
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| 36. |
6. Express the following rational numbers as decimals numbers242i15L) 1000lii7 |
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| 37. |
moth622 |
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| 38. |
10th class ex- 12.3 |
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Answer» I am understanding by 10th class ex-12.3But I am confused in subjects?Please tell me a suitable subject. |
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| 39. |
(h) 4p2 -20pq + 25q2 |
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| 40. |
the equation ax2 + bx + c =0If α, β are roots of x2-px + q = 0 and α-2.316q(r 4 q) 4p2A-8.+2are roots of x?-px+r-othen prove that |
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| 41. |
factories the expression.1) 4p2-9q2 |
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Answer» 4p2− 9q2= (2p)2− (3q)2 = (2p+ 3q) (2p− 3q) [a2−b2= (a−b) (a+b)] |
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| 42. |
2. Factorise 4p2 - 90%() 63a? - 11262(ü) 49x2 - 36 |
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| 43. |
What should be added to 4p2 -12p 6 to make it a perfect square? |
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| 44. |
(vi)Find the place value of 5 in 11.25 |
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Answer» place value of 5 is 1/100 thanks |
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| 45. |
vi) Find the angle x in the adjoining figure.10812570 |
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Answer» b= 180-125= 55c= 180-70 = 110a= 180- 108 = 72so a+b+c+x= 360so x= 123 108+125+70+x 360 x 303-360 x 57 is your answer |
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| 46. |
to Vidhu and111) I had? 200 with me. I gave? x to Anwar,ăçŚFind the amount I gave to Vidhu.1x-2x-2 |
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Answer» please like my answer if you find it useful |
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| 47. |
Identify instances of humour in the story 'Pappachi's Moth'. |
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Answer» 1) Pappachi slouched around the compound in his immaculately tailored suit, weaving sullen circles around the mounds of red chillies and meekly powdered yellow turmeric. 2) He became a familiar sight in Ayemenem, coasting importantly down the narrow road in his wide car, looking outwardly elegant but sweating freely inside his woollen suits. 3) Pappachi’ss Moth was held responsible for his black moods and sudden bouts of temper. pappchi'ss moth was held responsible for his black moods and sudden bouts of temper |
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| 48. |
\int ( \frac { \cot x } { \sin x } - \tan ^ { 2 } x - \frac { \tan x } { \cos x } + \frac { 2 } { \cos ^ { 2 } x } ) d x |
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Answer» Plzz like my ans 🙏🙏🙏 |
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| 49. |
n θ =-, find the other five trigonometric functions, where θ lesin the firstqurdrant)If ta |
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| 50. |
\frac{x y-5 x}{3 x y-4 x^{2}} \div \frac{3 y^{2}-4 x y}{x y+5 x} \times \frac{9 y^{2}-16 x^{2}}{y^{2}-25} |
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