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ङ) निम्न चित्र मेंAODCNAOBADZBOC=125 तथाZCDO= 70°LOAB = ?

Answer»

55 degrees is the right answer

55° is the correct answer to this question .

55° is the correct answer of the given question

55°...because angle BOC=angle AOD..then circle =360°..so angle DOC=angle AOB=55°..then sum of all angles in ∆ AOB =180°,then angle OAB = 55°

<BOC=<AOD(VERTICALLY OPPOSITE ANGLE )=125LET <DOC=X= <AOB(IT IS ALSO VERTICALLY OPPOSITE ANGLE)X+X+125+125=360(Angle on a point)2x= 360-250x= 110/2=55°<DOC+<ODC+<OCD=180 (sum of internal angle of ∆ is 180)70+55+<OCD=180<OCD= 180-125= 55°<D= <B= 70℃<A=<C=55°<OAB=55°

55° is the right answer

angle a aob =55 by using suitable properties



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