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m^2-3m-1=0; m^2-1/2×2×3m-1= m^2-2(3/2)m'-1=0;, m^2-2(3/2) m^2-(3/2)^2-(3/2)^2-1=0; ( m^2-3/2)^2=(3/2)^2+1, ,; m-3/2 =+-V13/2, m/3+-V14/2

2x2+ x -4=02x2+ x = 4x2+ x/2 + 1/4 = 2+1/4(x + 1/2)2= 9/4(x + 1/2) = ± 3/2x = 3/2 - 1/2 = 1orx = 3/2 + 1/2 = 2Hence, x = 1 or 2

the correct answer is 900/12

The correct answer is 900/12

class 6th is the right answer

each person gets 833.333 rupees

the correct answer is of this question is 833

Sum of the ratios: 10+6+9=25

Person A's share:6/25*2500 = Rs 600

Person B's share:9/25*2500 = Rs 900

Person C's share:10/25*2500 = Rs 1000

833.333 Rupees is the correct answer

His speed= 120/4= 30km/hrnow we know thatkm/hr= 5/18m/secnow= 30*5/18= 10*5/6= 50/6m/sec

The solution is (1, 0).

Let the angle be xComplement of x is 90° - xSupplement of x is 180° - x

According to question4(90°-x) = 2(180° -x) - 10360 - 4x = 360 - 2x - 1010 = 2xx = 10/2 = 5

So angle is 5°

percentage of girls = 13/13+7

= 13/20 * 100

= 65%

boys : girls = 11 : 10 now there are 605 boys so number of girls = 605 × 10 / 11 = 55 × 10 = 550

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Hi ,

_____________________________________________________________

The theoretical ( classical ) probability of an event E , written as P(E),

its define as

P(E) = ( Number of outcomes favorable to E) / ( Number of all possible outcomes of the experiment )

According to the problem ,

Number of girls in the line = 13

Number of boys in the line = 15

Total possible out comes = Number of girls + Number of boys

= 13 + 15

= 28 -------( 1 )

The number of outcomes favorable for one student is chosen at

random that probability that he is a boy = 15 ---------( 2 )

P ( boy ) = ( 2 ) / ( 1 )

= 15 /28

(a²-b²)²= ((a+b)(a-b))²

= (a+b)²(a-b)²

thank u

wrong

It's not an answer to my question

4l(10n-3m+21) - 3l(l-4m+5n) = 40ln - 12lm +84l - 3l^2 + 12lm - 15ln= -3l^2 + 84l + 12lm - 12lm + 40ln - 15ln= -3l^2 + 84l + 25 lnif you need further we can take l common= l ( -3l+84+25n)

Thnx

thank you so much

let ' a' be any positive integer and b = 3.we know, a = bq + r , 0< r< b.now, a = 3q + r , 0<r < 3.the possibilities of remainder = 0,1 or 2Case I - a = 3qa2= 9q2= 3 x ( 3q2) = 3m (where m = 3q2)Case II - a = 3q +1a2= ( 3q +1 )2 = 9q2+ 6q +1 = 3 (3q2+2q ) + 1 = 3m +1 (where m = 3q2+ 2q )Case III - a = 3q + 2a2= (3q +2 )2 = 9q2+ 12q + 4 = 9q2+12q + 3 + 1 = 3 (3q2+ 4q + 1 ) + 1 = 3m + 1 where m = 3q2+ 4q + 1) From all the above cases it is clear that square of any positive integer ( as in this case a2) is either of the form 3m or 3m +1.

A) 205 = 7 + (n-1)6 198 = (n-1)6 n-1 = 33 n=34 B) 120 = 4 + (n-1)4 4(n-1) = 116 n-1 = 29 n=30 C) 1.1 = 0.5 + (n-1)(0.03) 0.6 = (n-1)(0.03) n-1 = 20 n=21 D) -47 = 18 + (n-1)(-2.5) (n-1)(-2.5) = -65 n-1 = 26 n=27

Distance = 390 km.Time = 6.5 hours. Speed = Distance/ time= 390/6.5=60 km/hr

right hai answer

thanks

here is your answer

There are 100 girls.So, the number of boys is 1800-100=1700 So the ratio of boys /total no. of students is 1700/1800. =17/18.

(39*x*x*2(25*x*x-49))/(26*x*x(5x+7))=(3×13*x*x(5x+7)(5x-7))/(2×13*x*x(5x+7))=3(5x-7)/2

Solving using ratio nd proportion 1/6 = 24/x So, x= 6×24 = 144 min

great

यह माध्य ज्ञात करने का फार्मूला हैthanks

Answer for question 8- Ila read less as she read 25 pages but lalota red 2/5th of book which means 40 pagesAnswer for question 9- is Rohit as 3/4th of an hour means 45 mins whereas 4/6th means 30 minutes

unit digits are following14169465

No, 6^n cannot end with five.For - "A ^ n"( where A is any integer ), to end with 5 ( or have 5 in unit place )."A"must be in the form of 2 ^ m X 5 ^ n .However, here 6 = 2 X 3ie. 6 cannot be written in the form of 6^n.So, 6 ^n cannot end with five.

And for, 6n.This too can't end with five, as all multiples of 6 end onlywith 0, 2,4, 6,8.