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4. Use Euclid's division lemma to show that the square of any positive integer is either ofthe form 3m or 3m + 1 for some integer R.[Hint: Let x be any positive integer then it is of the form 37, 39 +1 or 39+2. Now squareeach of these and show that they can be rewritten in the form 3m or 3m +1.] |
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Answer» let ' a' be any positive integer and b = 3.we know, a = bq + r , 0< r< b.now, a = 3q + r , 0<r < 3.the possibilities of remainder = 0,1 or 2Case I - a = 3qa2= 9q2= 3 x ( 3q2) = 3m (where m = 3q2)Case II - a = 3q +1a2= ( 3q +1 )2 = 9q2+ 6q +1 = 3 (3q2+2q ) + 1 = 3m +1 (where m = 3q2+ 2q )Case III - a = 3q + 2a2= (3q +2 )2 = 9q2+ 12q + 4 = 9q2+12q + 3 + 1 = 3 (3q2+ 4q + 1 ) + 1 = 3m + 1 where m = 3q2+ 4q + 1) From all the above cases it is clear that square of any positive integer ( as in this case a2) is either of the form 3m or 3m +1. |
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