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option c is the right answer

agar ek seller man rs 7 banana bechata hai to 36.1% loss

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Total Pairs of Jeans Ankit had = 2Cost of each pair = Rs. 990

Now, let's calculate the amount for the first pair.

C.P = Rs.990Profit = 10%

Hence profit = Rs.99So, the final price will be Rs.990 + 99 = 1089

Now, calculation for the 2nd pair of jeans

C.P = Rs.990Loss = 10%

Hence, loss = Rs.99So, the final price will be Rs.990 - 99 = 891

Now, verify profit or loss

Price of 1st pair + Price of 2nd pair = 1089 + 891 = 1,980Original price of 1st pair + Original price of 2nd pair = 990 + 990 = 1,980

S.P = C.P,Hence , no profit no loss

total C.P.=5000×100=500000S.P. of 50 articles=50*5000*0.9=225000now no profit no lossso S.P.=C.P.so 500000=225000 + S.P. of remaining 50so S.P. of remaining 50 articles=5500so with 10% profit he has to sell

let x=speed of steamer in still waterx+3=speed of steamer downstreamx-3=speed of steamer upstreamdistance=travel time*speed (same for both directions)..15(x+3)=20(x-3)15x+45=20x-605x=105x=21distance=15(x+3)=15*24=360distance between two towns=360 km

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A fraction where the numerator ( the top number ) is less than the denominator ( the bottom number ) eg. 1/4 , 5/6



Afractionwhere the numerator (the top number) is less than the denominator (the bottom number).Example: 1/4 (one quarter) and 5/6 (five sixths) areproper fractions.

A fraction where the numerator (the top number) is less than the denominator (the bottom number).

Example: 1/4 (one quarter) and 5/6 (five sixths) are proper fractions.

Whole number definition is - any of the set of nonnegative integers. Eg: 0, 1, 2, 3, 4, 5

Let us suppose the value of the machine an year ago=x. It's 10% will be x*10%=x/10If we analyze the question we can say that

X-X/10=3870009X=3870000X=3870000/9

Therefore X= Rs. 430000

4/5 + (-2/5)

4/5 - 2/5

(4-2)/5

2/5

-2/3 × 3/5 + 5/2 - 3/5×1/6 = -2/5 + 5/2 - 1/10 = (-4+25-1)/10 = 20/10 = 2

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(a + b)x - 2by = 5a + 2b + 13x - y = 14

What we want is to make these the same lines, or rather, have one lie on top of the other.

Let's solve each equation for y:(a + b)x - 2by = 5a + 2b + 12by = (a + b)x - 5a - 2b - 1y = (a + b)x/2b -5a/2b -1 - 1/2b

m = (a + b)/2by-intercept = -5a/2b - 1 - 1/2b

3x - y = 14y = 3x - 14

m = 3y-intercept = -14

Set the slopes equal to each other:(a + b)/2b = 3a + b = 6ba = 5b

Set the y-intercepts equal to each other:-14 = -5a/2b - 1 - 1/2b-28b = -5a - 2b - 1-26b = -5a - 1

Substitute a = 5b into equation:-26b = -5(5b) - 126b = 25b + 1b = 1

a = 5ba = 5

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jakksvj sbnskk fnskk sjosgu. skksuua

344222433444444322111123345554322

In triangle ABD

Angle BDA = 180 - 96 =84 by linear line propertySum of all angles of triangle is 180Let angle DAB be x then angle ABD is 3x

Remaining ans

x + 3x + 84 = 1804x = 96x =24

Angle ABD = 3x = 72 degree

9/5 = 100 ×9/5 = 180

probability of at least 2 heads = 4/8 = 1/2and probability of at most 2 heads= 7/8

Thnku ji

When 3 unbaised coins are tossed, the total number of events = 8

They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

(1) Number of favourable events (getting at least two heads) = 4

Probability of getting at least two heads = 4/8 = 1/2

(2) At most two heads

That is no head or one head or 2 heads

Probability of getting at most two heads = 7/8

Thnku ji u too

Given that Ravi starts for his school at 8.20 am.

Let the distance be x km.

Let the time taken by Ravito reach the school be y.

(1) Given that he travels at a speed of 10km/hr and reaches by 8 minutes late.

x/10 = y + 8/60

x/10 = y + 2/15 --- (1)

(2) Given that he travels at a speed of 16km/hr and reaches by 10 minutes early.

x/16 = y - 10/60

x/16 = y - 1/6. ----- (2).

on solving (1) and (2), we get

x/10 - x/16 = 2/15 + 1/6

3x/80 = 9/30

x = 9 * 80/3 * 30

= 8 km. ----- (3)

Substitute (3) in (2), we get

8/16 = y - 1/6

y - 1/6 = 8/16

y - 1/6 = 1/2

y = 1/6 + 1/2

= 2/3 hours

= 2/3 * 60

y = 40 minutes.

Ravi starts school at 8.20am + 40 minutes = 9.00AM.

Plz give the solution with easy method

y=20 minutes how you got 40minutes

100/8

91 = 35*2 +21

91= 70 +21 = 91

This statement is true

triangle ka figure send kar do

The height of a vertically standing pole to the length of its shadow on the ground is √3:1

Consider the height of pole be √3

∴ length of shadow =1.

In a triangle ABC,

tan ∠ACB = √3/1

tan ∠ACB = √3

∠ACB =60°

The height of a vertically standing pole to the length of its shadow on the ground is √3:1

Consider the height of pole be √3

∴ length of shadow =1.

In a triangle ABC,

tan ∠ACB = √3/1

tan ∠ACB = √3

∠ACB = 60°.ANS

40 are rottenhence remaining are250-40=210 appleshence percentage210/240*100=87.5%

no. of good apple=250-40 = 210% of good apple=210/250*100 =84%