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answer will be...180-90+70=20 degree

20° is correct answer

correct answer is 20 °

correct answer is 20 °

20° is the correct answer

8^3=8×8×8=51216^3=16×16×16=409621^3=21×21×21=926130^3=30×30×30=27000

1. i) use angle A + angle B = angle ACDx + 56 = 123x = 123 - 56 = 67°

(ii)ans=125 is the answer by angle sum property sum of all the angles =180

The area of a parallelogram is given by the formula

Area=b×awherebis the length of any baseais the corresponding altitude

P = 12000, R = 12/100, n = 18/12 = 3/2Amount = P(1+R/2)^2 n = 12000(1+.12/2)^3 = 12000(1.06)^3 = 12000(1.19) = 14280

CI = A-P = 14280-12000 = Rs 2280

18 is divided into 13489

X= 200000.

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I don't know the answer

4x^2+3x-1=0; 4(1/4)^2+3(1/4)-1=4/16+3/4-1=1/4+3/4-1=1+3-4/4=4-4/4=0

because when we put that values then p(x) =0

because when we put that values then p(x) =0

sale ye bhi nahi ata

If they are the zeros of the polynomial after putting them we should get a 0so now puttingx= -1(-1)^2*4-3-1= 0now putting X= -1/44*(-1/4)^2+3(-1/4)-14/16-3/4-11/4-1/4= 0hence they are the zeros

Given E = 116 GPa and shear modules G = 45GPa

so, G = E/2(1+μ)

so, 45=116/2(1+μ) => 90(1+μ) = 116 => 1+μ = 116/90 => μ = 1.2888-1 = 0.28888

now bulk modulus = E/3(1-2μ) = 116/3(1-2*0.2888) = 116/3*0.4222 = 47.89GPa

i) 1+√-3 = 1+ √3i , so modulus is √(1)²+(√3)² = √4 = 2. and argument is ∅ = tan^-1(√3/1) = π/3

ii) 1+i = modulus is √1²+1² = √2. and argument is ∅ = tan^-1(1/1) = π/4

iii) -2i , modulus is 2. and argument is -π/2.

Area of a rectangular field is equal to length into breadth. Area =lb 3400=68×b b= 50 m.So the breadth of field is 50 m.

For travelling one time completely around the field, distance covered= Perimeterdistance covered in one round =2(l+b) =2(68+50) = 2(118) = 236m So in 5 rounds he travels 236×5 =1180 m.

Area = 8464 m²The side of square field = √8464 = 92 mDistance covered in making three rounds = 3 × Perimeter of the square field = 3 × 4 × 92 = 1104 m

iv) -16/1+i√3.

on rationalizing it with 1-√3i we get. -16*(1-√3i)/(1)²+(√3)² = 16(√3i-1)/4 = 4√3i -4.

so, the module is √(4√3)² +(4)² =√48+16 = 8.

and principal argument is ∅ = tan^-1(-√3) = -π/3.

Length of field = xBreadth of field = x/2

Given4*Perimeter = 4.5 km4*(2*(length + breadth)) = 4.58(x + x/2) = 4.58(3x/2) = 4.5x = 1.5/4 = 1500/4 = 375 m

Length of field = 375 m

greater than 34

for proving this we will put x= 2,(-3),4 in the equation if the answer comes as zero so that means these are the factors of the polynomialso put x= 28-12-20+24=0so this is a factor just like this we will keep doing the same thing and at the end these all three are the factors after putting x= (-3)p(-3) = 0p(4) = 0 as well

The period of the tangent function isπ. Therefore, the period oftan(3x)isπ/3(3xwill increase byπunits anytimexincreases byπ/3units).

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Ans :- Option (b) is correct.

For given question option b is correct

As for finding median first we need to arrange observations in ascending order for both odd and even no. Of observations

Thus both Assertion and reason is correct, but R is not correct explanation of A

hey bro please give questions one by one and like my answer plzzzzzzzz

Circumference=2πr616 m = 2 × (22/7) × rr= 98mArea = πr^2 = (22/7)(98)^2 m^2 = 30184 m^2

Let the total no. of swans = xNo. of swans playing on the shore = 7/2 √xRemaining swans = 2A/Q x=7/2 √x+2x-2 = 7/2 √x2(x-2) = 7√x4(x-2)² = 49x4(x²-4x+4) = 49x4x²-65+16 = 0(x-16) (4x -1) = 0x-16 = 0 or 4x-1 = 0x = 16 or x = 1/4Since, the no. of swans cannot be 1/4∴ x = 16The total no.of swans = 16

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Area of circle with radius r is given by,

Area of circle, A = πr²

Let 'r' be the radius of smaller circle, then radius of large circle = r+3

It is given that sum of areas = 89π m^2

To find r

Sum of areas = πr² + π(r +3)² = 89π m^2

⇒ π[r² + (r +3)²] = 89π

⇒ r² + (r +3)² = 89

⇒ r² + r² + 6r + 9 = 89

⇒ 2r² + 6r + 9 - 89 = 0

⇒ 2r² + 6r - 80 = 0

⇒ r² + 3r - 40 = 0 ----(1)

eq(1) is a quadratic equation.

Solving we get

r = 5 and r = -8

we take +ve values, so r = 5

Therefore radius of smaller circle = 5m

And radius of larger circle = r + 3 = 5 = 3 = 8m