Q2) For a material modulus of elasticity is 116 GPa and shear modulus

1.	Q2) For a material modulus of elasticity is 116 GPa and shear modulus is 45 GPa. Find thevalue of bulk modulus for the material. (M99, 4marks)
Answer» Given E = 116 GPa and shear modules G = 45GPa so, G = E/2(1+μ) so, 45=116/2(1+μ) => 90(1+μ) = 116 => 1+μ = 116/90 => μ = 1.2888-1 = 0.28888 now bulk modulus = E/3(1-2μ) = 116/3(1-20.2888) = 116/30.4222 = 47.89GPa

Q2) For a material modulus of elasticity is 116 GPa and shear modulus is 45 GPa. Find thevalue of bulk modulus for the material. (M99, 4marks)

Answer»

Given E = 116 GPa and shear modules G = 45GPa

so, G = E/2(1+μ)

so, 45=116/2(1+μ) => 90(1+μ) = 116 => 1+μ = 116/90 => μ = 1.2888-1 = 0.28888

now bulk modulus = E/3(1-2μ) = 116/3(1-2*0.2888) = 116/3*0.4222 = 47.89GPa