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The answer of the following is 1ab

3ab + (-4ab) +7ab+(-5ab)=3ab-4ab+7ab-5ab= -ab +2ab= ab

The correct answer is 1ab.

the answer of the following is 1ab

=(30000×100)/450000=3000000/450000=300/45=60/9=15% is the right answer.

3a-2b-ab(a-b+ab)+3ab+b-a3a-a-2b+b-a²b+ab²+a²b²+3ab2a-b-a²b+ab²+a²b²+3ab

The extra 2.5 kg is obtained because of 20 reduction in price i.e. 20% of 160 = 32 rs.Reduced price 1 kg = 32/2.5 = 12.80 rs.So answer is 12.80 rs.And original price :-20% reduction price means you pay 80% of the original price80% of original price = 12.80 rs/kg100% of o.p. =16 rs/kg.

Let in 100 Rs person can buy x kg wheatAfter 21% reduction person can buy (x + 10.5) kg in 100 rs

So,10.5 kg wheat cost Rs 21Then 1 kg cost = 21/10.5= Rs 2

179088 is the right answer

179088 is the right answer

1456×123=1790088 is the correct answer of the following question.

329/400 = 0.8225

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x³+x²-2x-3=(x-2)(x²+ax+b)+5 =x³+ax²+bx-2x²-2ax-2b+5a-2=1a=3B-2a=-2B=-2+2a=4

But i want with steps

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(b+c)²/3bc+(c+a)²/3ac+(a+b)²/3ab

=(b²+2bc+c²)/3bc+(c²+2ac+a²)/3ac+(a²+2ab+b²)/3ab

=(ab²+2abc+ac²+bc²+2abc+a²b+a²c+2abc+b²c)/3abc

={ab(a+b)+bc(b+c)+ac(a+c)+6abc}/3abc=(-abc-abc-abc+6abc)/3abc [∵, a+b+c=0,∴,a+b=-c,b+c=-a,a+c=-b]

=(6abc-3abc)/3abc=3abc/3abc=1 (Proved)

squared numbers are a^2 and b^2 now adding them, gives a^2+b^2

thanks

0.8225 is the answer

here is your answer 329/400 = 0.8225hope its help you

correct answer is 0.8225

The tower of hanoi is a mathematical puzzle. It consists of three rods, and a number of disks of different sizes which can slide onto any rod. The puzzle starts with the disks in a neat stack in ascending order of size on one rod, the smallest at the top. We have to obtain the same stack on the third rod.

thanks

sum of infinite series = a/(1-r) so, a/(1-r) = 8 and second term is =ar = 2 a = 2/rso, 2/r(1-r) =8 => 1/r(1-r) = 4=> r-r² = 1/4 so, 4r²-4r+1 = 0r = 1/2.

The option (A) is the correct answer.

let rstterm of this A.P. be a , commom difference be dNow, nth term of A.P. is given by:a+(n-1)dso, its 8th term = a+(8-1)d = a+7dbut 8th term of A.P. is 32so, a+7d = 32 ...(1)similarly, 12th term = a+(12-1)d = a+11d = 52so, a+11d= 52 ....(2)Subtracting eq (1) from (2),a+11d - (a+7d) = 52 - 32=》4d = 20=》d= 5putting the value of d in (1),a+7d = a+7×5 = 32=》a+35 = 32=》 a = -3Now, a = -3 and d = 5so, second term of A.P. = a+ d = -3+5 = 2similarly 3rd term = a+2d = -3 + 5×2 = 7so, Required A.P. is : -3,2,7,12,17 ........

7th terma + 6d = 34........ (1)

12th terma + 11d = 64......(2)

eq(2) - eq(1)(a+11d) - (a+6d) = 5d​5d = 64-34 = 30d = 6

Put value of d in eq(1)a + 6*6 = 34a = -2 Therefore, 10th term = a + 9d = -2 + 10*6 = 58

6/31,6/32,6/33,6/34,6/35

thnks

Cost of all dresses ₹2,52,072

Area of square = side²so side =√areaa= √324a= 18

Area = 324 sq.m. so each side is 18m Perimeter = 4(18) = 72m

sec(90-A)=cosecAcosec(90-A)=cosecAcot(90-A)=tanAtan(90-A)=cot AhencesinA*cosecA*tanA/cosecAcosA*tanA-tanA/cotA=tanA/cotA*tanA-tan^2A=tanA-tan^2A

sec(-43π/6)= 1/cos(43π/6)as cos(-x)= cosx= -1.15

distance covered to fetch water one time =2×(1km420m) =2 km 840ma) distance covered everyday = 3×(2 km 840m) =6km 2520m = 8km 520m

b) distance covered in a week = 7×(8km 520m) =56km 3640m =59km 640 m

thanks

let other no. be za/c to que, x=120/100(z) &y=150/100(z) 2y/3=5x/6y=5x/4So, x is 80% of y

hope it helps u

length= 40dcmbreath= 15 dcmheight= 10 dcmcapacity of tank = l×b×h = 40×15×10 Lt = 6000 Ltno of times= 40×15×10/8 = 5×15×10 = 750 times

3x+4y=2 x-2y=43x+4y+2x-4y=2+85x=10 so x=26+4y=2 so 4y=-4 so y=-1a+b=5 2a-b=-5a+b+2a-b=5-5=0so 3a=0 a=0 so b=5

Gain = SP - CP

CP = SP - Gain

= 4325 - 432

= 3893

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