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28 Find the 10th term of a sequence whose 7ih and 12thterm are 34 and 64 respectively |
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Answer» 7th terma + 6d = 34........ (1) 12th terma + 11d = 64......(2) eq(2) - eq(1)(a+11d) - (a+6d) = 5d5d = 64-34 = 30d = 6 Put value of d in eq(1)a + 6*6 = 34a = -2 Therefore, 10th term = a + 9d = -2 + 10*6 = 58 |
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