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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
1Write an algebraic expression for the following:(a) Subtraction of thrice x from 2 times y.!(b) The number a multiplied by itself.(c) One-half of the sum of numbers x and y.(d) One-fourth of the product of numbers p and q.(e) Numbers x and y both squared and added. |
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Answer» a) 2y-3xb) z×z= z^2c) (x +y)/2 (a) 2y - 3x (b) Z x Z ER. RAVI KUMAR ROY (c) 1/2(X+Y) (d) 1/4(PQ) (e) X^2 + Y^2 the right answer is (a) 2y-3x(b)z x z(c)1/2(x+y)(d)1/4(pq) hope this will help you like my answer bdhz gdd hssj gdhz. hsvsv |
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| 2. |
) 2y-x=0; 10x + 15y= 105 |
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Answer» Given : 2y - x = 0 .....(1) 10x + 15y = 105 ......(2) Use method os substitution so, x = 2y put in (2) 10 × 2y + 15y = 105 20y + 15y = 105 35y = 105 y = 105/35 = 3 So, x = 2y = 2×3 = 6 |
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| 3. |
which value of x, numbers x, x +3, x +9 are in G.P. |
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| 4. |
ater uat lell on aし△nser 2 m deepand 45 m wide is flowing at the rate of 3 km/h. Find the quantity of watero the sea per minute |
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| 5. |
5. 6 is the mean proportion between two numbers x and y and 48 is the third proportional of x(2011)and y. Find the numbers.36Find x and y.] |
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| 6. |
74. When the odd numbers from 1 to 99are added up, (like 1 + 3 +5+7 +....+95 + 97 +99), what is the digit inthe units place ? |
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| 7. |
The arithmatic mean of 10 terms is 24 and thearithmatic mean of 8 terms is 20. Find arithmatiemean of first two terms. |
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Answer» Wrong answerAnswer is 40 Mean of 10 terms is 24 and 8 terms is 20 so mean of first two terms should be lesser than 20.Correct answer will be 8 |
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| 8. |
\left. \begin array l \text lustration 17 . \text Find the value of C \text if A %2B 2 C = \\ A = \left[ \begin array c c c 1 & 2 & - 3 \\ 5 & 0 & 2 \\ 1 & - 1 & 1 \end array \right] B = \left[ \begin array c c c 3 & - 1 & 2 \\ 4 & 2 & 5 \\ 2 & 0 & 3 \end array \right] \end array \right. |
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| 9. |
12.The distance from Marura's home to the river is I km 420 m. If she fetcheswater 3 times daily from the river, what distance does she cover |
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Answer» distance covered to fetch water one time =2×(1km420m) =2 km 840ma) distance covered everyday = 3×(2 km 840m) =6km 2520m = 8km 520m b) distance covered in a week = 7×(8km 520m) =56km 3640m =59km 640 m |
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| 10. |
2) 9x4 is same as(i) 362(iii) 363(iv)184 |
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Answer» Given 9 × 4² We will do factorization, 3² × 4² ( 12)² i) option is correct |
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| 11. |
2*432 |
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Answer» 432 × 2_________ 864 864 is the right answer |
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| 12. |
5Ă5=6Ă6=7x7 = |
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Answer» 253649 |
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| 13. |
ractice Time 5Fill in the blanksa. 314+С. 3210 + 1002e. 0+Tick () the correct option.a. 3314 +0 3313- 314+324275c. 2553 + 1 - 2552 |
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Answer» a. 314 + 0 = 414 [Zero is the additive identity]c. 3210 + 1002 = 1002 + 32100 [Addition is commutative]e. 0 + 4275 = 4275 [Zero is the additive identity] a. 3314 + 0 = 3314 c. 2553 + 1 = 2554 |
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| 14. |
Construct the following angles and verify by measuring them by a protractor:75°4.(ii) 1050(ii) 1350 |
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| 15. |
exterior angles in the given triangle.the531426 |
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Answer» In the figure, 4, 5, 6 are exterior angles. |
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| 16. |
1. A student scored 18 marks out of 2marks in the first test of Math. Insecond test he scored 22 marks in thesecond test exceeds his first test byIJNV 2017](1) 4%(3) 16%(2) 8%(4) 80% |
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| 17. |
Divide 60 into three parts such that first will be of the second and the second will beof the third.4 |
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Answer» LCM of 5and 3=154/5×3/3 3/4×5/5=12/15 15/20=12:15:20=12+15+20=47=12/47×60=12like that only for 15and20=15/47×60=20/47×60 |
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| 18. |
How many terms of the arithmetic sequence 5,7.9to get 140?must be added |
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Answer» For Airthmetic sequence sum of n termsSn = n/2(2a + (n-1)d) For given sequencea = 5, d = 7-5 = 2 Let sum of given m terms is 140Then,140 = m/2(2*5 + (m- 1)2)280 = m (10 + 2m - 2)2m^2 + 8m - 280 = 02m^2 + 28m - 20m - 280 = 02m(m + 14) - 20(m + 14) = 0(2m - 20)(m + 14) = 0m = 10, - 14 As number of terms cannot be negative then m = 10 Thus sum of 10 terms of given sequence is 140 that means more 7 terms need to be added. |
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| 19. |
How many terms of the arithmetic sequence 5,7,9.......must be added to get 140? |
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Answer» Thank you |
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| 20. |
3) How many terms of the arithmeticsequence 99, 97, 95,.... must be addedto get 900? |
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| 21. |
vide 267 into three parts such that first one is4of the second and the ratio between second anrd is 6:7 |
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| 22. |
A river 3.5 m deep and 28 m wide is flowing at the rate of 2.4 km per hour. How many litresof water will flow into the sea in 10 minutes? |
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| 23. |
A river is 2m deep and 45m wide flowingat a rate of 3km/h.find the quantity ofwater run of the sea per minute |
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| 24. |
The sum of three terms of a geometric sequence is 39 and their product is 1. Find thecommon ratio and the terms.10 |
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| 25. |
Mensuration253he given figure, four equal circles are described about the fourcorners of a square so that each circle touches two of the circles asshown in the figure. Find the area of the shaded region, each side ofthe square measuring 14 cmHint. Area of the square-(14 × 14) cm2 = 196 cm21 22Sum of the areas of 4 quadrans-| 4 x x7x7 | cm2 = 154 cm2.. area of the shaded regton (196-154) cm2- 42 cm2 |
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| 26. |
16.A river 3 m deep and 40 m wide is flowing at therate of 2 km/hr. How much water will fall into thesea in a minute ? |
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Answer» thanks. for help can u give answer of one another question |
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| 27. |
3. The 10th term of the sequence /3,12,/27, .is(a) 243(b) 300(e) 363()432 |
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| 28. |
16. ABC is a triangle. D is a point on AB such that ADAB and E is a point on AC such4that AE =AC. Prove that DE = a BC.4 |
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| 29. |
MensurationIn the given figure, four equal circles are described about the four13.corners of a square so that each circle touches two of the circles asshown in the figure. Find the area of the shaded region, each side ofthe square measuring 14 cm.Hint. Area of the square -(14 x14) cm2- 196 cm2sum of the areas of 4 quadrants-| 4x47x7) cmn2-154 cm 2area of the shaded region (196-154) cm2 42 cm2 |
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Answer» thank you for your time |
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| 30. |
ie wire needed?eter of a regular hexagon with each side measuring 75 m.wih |
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Answer» thank you |
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| 31. |
288 I Mathematics-IX Semester-I3. Find the complement of the following angles:G) 64° 23' 35"(ii) 28° 25' 48'900 O' 6000o |
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Answer» thr complimentary angle of i) 90°00'00" - 64°23'35" = 25°36'25"ii) 90°00'00" - 28°25'48" = 61°34'12" |
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| 32. |
A floor measuring 7 m by 2.8 m is to be covered with tiles measuring 35 cm square. How many tileswill be needed?ntn measuring 42 cm by 14 cm is cut up into small squares of side length 7 mm. How man |
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| 33. |
a metallic cuboid measuring 9cmx6cmx4cm.find the side of the cube |
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Answer» If you like the solution, Please give it a 👍 |
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| 34. |
bus shaped field has green grass for 18 cows to graze, If each side of thes is 30 m and its longer diagonal is 48 m, how much area of grass ield willach201š Acow be getting? |
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| 35. |
eadth of a rectangular field are in the ratio 7:4. The cost of fencing theThe length and the brield at 25 per metre is 3300. Find the dimensions of the field. |
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| 36. |
The seventh term of an Arithmetic progression is four times its secondterm and twelfth term is 2 more than three times of its fourth term. Findthe progression |
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Answer» nth term of an APan = a + (n - 1) Then, 7th term of an APa7 = a + 6d 2nd term of an APa2 = a + d 12th term of an APa12 = a + 11d 4th term of an APa4 = a + 3d As per given conditiona + 6d = 4(a + d)3a = 2da = 2d/3.....(1) a + 11d = 3(a + 3d) + 22a - 2d = - 2....(2) Put value of a from eq(1) in eq(2)4d/3 - 2d = - 2(4d - 6d) = - 6d = 6/2 = 3 Hence, a = 2/3 * 3 = 2 Therefore, AP is 2, 5, 8, 11, 14 |
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| 37. |
) 2(a-1).. isd) (n-1)22. Sum of the nh terms of progression 2+4+6+8a) n (n-1)d) 2n?3. Areas of two similar |
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Answer» answer |
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| 38. |
How many terms of the arithmetic sequence 5, 7,9to get 140?must be added |
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Answer» a=5d=7-5=2 S=(n/2)*(2a+(n-1)*d)140=(n/2)*(2*5+(n-1)*2)140=(n/2)*(10+2n-2)280=8n+2n²2n²+8n-280=0n²+4n-140=0n²+14n-10n-140=0n(n+14)-10(n+14)=0(n-10)(n+14)=0n=10,-14 -14 is not possible Hence number of terms requires to produce a sum of 140= 10 |
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| 39. |
Find, in terms of n, an expression for the nth term of thesequence 5, 8, 13, 20 |
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Answer» If you find this solution helpful, Please like it. I Don't think that's the correct answer |
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| 40. |
In Fig. 65, if AB II CE, then the values of xand yare26, y144 (b)x-36, y : 154(c)154, y-36(d)xxx-144, y-261342x°62°Fig. 65 |
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Answer» x = 36 and y = 154 is the right answer |
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| 41. |
(B)r(C)rp-q(D)r+[16JM11006Consider the sequence 2,3, 5, 6, 7, 8, 10, 11,. (A) 2056of all positive integer, then 2011t term of this sequence(C) 2013(B) 2011(D) 2060 |
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Answer» we can see that here 4,9 are missing... so, the sequence doesn't contain all the square numbers now √2011 = 44.84.. so nearest perfect square is of 45*45 = 2025....so there will be 45 such numbers missing im the sequence.. and so the sequence will go for 45 ahead of 2011 so the number is 2011+45 = 2056. option A. |
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| 42. |
5. If {an} is a G.S. (i.e., geometric sequence) anda = 4, r = 5, find ag and So. |
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Answer» Givena1 = 4, r = 5 Then, a6 = a1*r^5 = 4*(5)^5a6 = 4*3125 = 12500 S6 = a1(r^n - 1)/(r - 1) = 4*(5^6 - 1)/4 = 15625 - 1 = 15624 |
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| 43. |
ECK POINT 16.6the area of a circle whose radius is) 7 cmthe area of a circle whose diameter is:10.5 c(ii) 2.1 mii) 3.5 |
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Answer» with the following formula solve the other sums |
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| 44. |
34. Solve for x:-+-+-:a,b,x,=aa+b+x |
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Answer» Like my answer if you find it useful! |
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| 45. |
âRank,ofthe matrix-\left[ \begin{array}{lll}{1} & {2} & {3} \\ {1} & {4} & {2} \\ {2} & {6} & {5}\end{array}\right] |
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Answer» thanks to ur ans |
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| 46. |
in Fig13.65, if AB II CE, then the values of x and yare26, y 144 (b) x 36, y 154 (x-144, yC)x 154, y 36 (d)x144, y 2662°2xFin. 65 |
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| 47. |
Δ ABC ~ Δ DEF and their areas be, respectively, 64 cm 2 and 121 cm2. If EF-154 cm, find BC. |
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| 48. |
EXERCISE 6.4I.Let AABC-A DEF and their areas be, respectively, 64 cm and 121 cm. IfEF 154cm, find BCtively, 64 cm and 121 cm IfEF 1542. Diaeonal |
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Answer» i was just checking the functioning of this app... but yastill THANKS for ur solution...... If you find the solution helpful, you can like it. ya I had already liked it ... |
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| 49. |
4. Write the first five terms of the G.P. where nth· is given as:52 |(i) 4.39-1(ii)2n |
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Answer» For 1 st termn= 1so4n= 2then4*3= 12n= 3= 36n= 4so 108nown= 581*4= 324 (2) nth term of GPTn = 5^n-1/2^n+1 Thus,T1 = 5^0/2^2 = 1/4T2 = 5^1/2^3 = 5/8T3 = 5^2/2^4 = 25/16T4 = 5^3/2^5 = 125/32T5 = 5^4/2^6 = 625/64 |
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| 50. |
(ii) If nth term of sequence is a, =n2-n+1. Find the first five terms. |
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