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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Prove that29 36 23 |
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| 2. |
tree breaks due to storm and the broken partbendsmaking an angle 30° with it. The distance betweenthe foot of the tree to the point where the toptouches the ground is 8 m. Find the height of thetree.so that the top of the tree touches the ground |
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| 3. |
A tree breaks due to storm and the broken partbends so that the top of the tree touches the groundmaking an angle 300 with it. The distance betweenthe foot of the tree to the point where the toptouches the ground is 8 m. Find the height of thetree. |
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| 4. |
A tree breaks due to storm and the broken part bends so that thetop of the tree touches the ground making the angle 30° with it. Thedistance between the foot of the tree to the point where the toptouches the ground is 8 m. Find the height of the tree. |
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| 5. |
A tree breaks down due to storm and broken part bends. So that the top of the treetouches the ground making an angle 30 with the ground. The distance between thefeet of the tree to the point where the top touches ground is 18m. Find the heightof the tree. |
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Answer» thank you so muchplz do help me after also... |
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| 6. |
Find the ratio of 55 paise to Rs..paise to Rs. . |
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| 7. |
The triangular side walls of a flyover have been used for advertisements. Thethe walls are 122 m, 22 m and 120 m (see Fig. 8.9). The advertisements yieof 5000 per m2 per year. A company hired one of its walls for 3 monthsrent did it pay?2.menHow much122m22m120im |
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| 8. |
The triangular side walls of a flyover have been used for advertisements. The sides ofthe walls are 122 m, 22 m and 120 m (see Fig, 12.9). The advertisements yield anearning of ? 5000 per m2 per year. A company hired one of its walls for 3 months. Howmuch rent did it pay?122mc22m120m |
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| 9. |
2.The triangular side walls of a flyover have been used for advertisements. The sides of tthe walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield anearning of t 5000 per m2 per year. A company hired one of its walls for 3 months. Howmuch rent did it pay?122m22m120mFig. 12.9 |
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| 10. |
4)tan60° + 3cos30° BT Ha şta alfariFind the value of tan-60° + 3cos? 30° |
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Answer» tan^2 60 + 3cos^2 30 = (sqrt(3))^2 + 3*(sqrt(3)/2)^2 = 3 + 3*3/2 = 3 + 9/2 = (6 + 9)/2 = 15/2 = 7.5 |
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| 11. |
/ and m are two parallel lines intersected byanother pair of parallel lines p and q(see Fig. 7.19). Show that A ABC A CDA. |
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Answer» ckgfzxghjjkkfty jhsfhi hdshi hdfj thanks |
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| 12. |
10 If a point A (0,2) is equidistant from the pointsB (3.p) and C(p. 5), then find the value of p |
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| 13. |
a Find the total no of secs in 5 of 5 haSecon |
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Answer» 2250 is right answer of this question 5/8 of 3 hours =5/8 of 3600 seconds=5/8×3600= 5/1 × 450= 2250 2250 sec is the correct answer of the given question 2250 is the right answer of your question |
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| 14. |
Find twice the product of the extremes and hathe product of means of 12 23:: 36:69 |
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Answer» product of extremes = 12*69 = 828 so twice of it = 828*2 = 1656 product of mean = 36*23 = 828so half of it = 828/2 = 414 |
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| 15. |
Lazy Crazy also has a crazy way of taking money. He takes onlyin notes, notes andcoins. Now findout how they will pay him for what they have taken.Rs 420kiRs 143Rs 242Rs 55 |
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Answer» i) Four hundreds and Two Tenii) One hundred, Four Ten and Three coins. iii) Two hundreds, Four Ten and two coinsiv) Five Ten and Five coins |
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| 16. |
| हक श्रेग्नल की शुजाठँ दा, /2८7० और 23:72 B oil T 97 THT 7 3 s T oबाई रात कट । हरकिक) पे: |
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Answer» hit like if you find it useful |
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| 17. |
Lazy Crazy also has a crazy way of taking money. He takes onlycoins. Now findin nnotes andotesout how they will pay him for what they have taken.Rs 420 -LRs 143Rs 242Rs 55 |
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| 18. |
Lazy Crazy also has a crazy way of taking money. He takes onlycoins. Now findinnotes,notes andout how they will pay him for what they have taken.Rs 420 -Rs 143Rs 242Rs 55 |
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Answer» 1)4*100+20*12)1*100+2*20+1*103)2*100+2*20+1*104)3*20 |
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| 19. |
10.The area of a rectangular field is 0.5 ha. If one side is 12.5m,find theother side in meters. |
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Answer» area = 0.5 ha = 5000 sq meter one side is 12.5 m second side = 5000/12.5 = 400 m thanks |
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| 20. |
what will be the compound interest in₹ 5000 at 4% per annum in 2 year ? |
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Answer» Compund interest = 5000(1+4/100)^25000(104/100)^25000*1.085408interest will be 408 ruppes |
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| 21. |
A-B-C-D IN AC=BD THEN PRUVE IT AB=CD |
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| 22. |
whatwIllOC180The triangular side walls of a flyover have been used for advertisements. Thethe walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertiseearning of 5000 per m2 per year. A company hiredmuch rent did it pay?cm,2.one of its walls for 3 monhs. H122m22m120mFig. 12.9 |
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| 23. |
The priangular side walls of a flyover have been used forthe walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advatsenearming of Rs 5000 per m' per year. A company hired one of its wais fmuch rent did it pay? |
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| 24. |
trangular side walls of a flyover have heen used for adwals are 122 m. 22 m and 120 m (see Fig. 129). The advertisementas The sides otyield an. Thehired one of is walls for 3 mns.earning of 5000 per a per year A compatymuch rent did it pay? |
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| 25. |
A part of monthly expenses of a family is constant and the remaining varies withthe price of wheat. When the rate of wheat is 250 per quintal the total monthlyexpen3.ses are1000 and when it is? 240 per quintal, the total monthly expensesare 7 980. Find the monthly expenses of the family when cost of wheat is t 350per quintal (Assuming the consumption of wheat to be same). |
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Answer» HIT LIKE 👍 Hence, the Total monthly expenditure when the cost of rice ₹300 is ₹ 1२00 |
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| 26. |
e average age of family of five members is 24years. If the present age of youngest member is 8years. What was the average age of the family at thetime of birth of youngest member?10. Th |
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Answer» Solution:The average age of the family at the time of birth of the youngest member = 20 yrs Explanation:Total age of five members of a family = 24 x 5 = 120 Total age of four members at the time of birth of youngest = 120 - (8 x 5) = 120 - 40 = 80 yr Hence, the required average age = 80/4 = 20 yr |
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| 27. |
10. A part of monthly expenses of a family is constant and the remaining varies with the price of wheat.When the rate of wheat is Rs 250 a quintal the total monthly expenses of the family are Rs1000 .when itis Rs 240 a quintal, the total monthly expenses are Rs 980.Find the total monthly expenses of the familywhen the cost of wheat is Rs 350 a quintal. |
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Answer» Let the constant expenditure be ₹.x Let the consumption of rice by the family be y quintals. x+250y=1000------------------(1) x+240y=980-------------------(2) Subtracting eq (1)and(2) x + 250y =1000 x + 240y = 980 (-) (-) (-) --------------------------- 10y = 20 y= 20/10 y= 2………….(3) Put the value of y in eq 1 x+250y=1000 x + 250(2) = 1000 x+ 500 = 1000 x= 1000-500 x=500………….(4) Total monthly expenditure when the cost of rice ₹300 = constant expenditure + consumption of rice at ₹ 300 per quintal. = x+300y = 500 + 300 × 2 ( From eq 3 & 4) = 500+ 600 = ₹ 1100 Hence, the Total monthly expenditure when the cost of rice ₹300 is ₹ 1100 |
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| 28. |
(i) AP COQ |
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| 29. |
A survey conduct on 20 households in a locality by a group of students resultin the following frequency table for the number of family member in a householFamily size1-3 35-77-9 9-11Number of families2Find the Mode of this data. |
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| 30. |
Colurhn-IColumn -II(b) 2/6 (ii)(c) 6/9 ii)(d) 8/10 (iv)Rapid Fire Questions (Answer only Yes/No) |
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Answer» 3/5 = 0.62/6 = 0.3333336/9 = 0.666666 |
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| 31. |
Sudhir lent Rs. 2000 at coompound interest at 10% payable yearly, while Prashanth lwnt Rs. 2000 at compound interest at 10% payable half yearly. FInd the difference in the interest received by prashanth and sudhir at the end of the year. |
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| 32. |
(c) On a certain sum of money, the differenfor a year, payable half yearly aundFind the sum lent out, if the rate of ice beeen the compound interestst for a year is Rs 16. |
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| 33. |
8. A quadrilateral ABCD is drawn to circumnscribe a circle (see Fig. 10.12). Pruve thtAB + CD-AD +BCX'Y'Fig. 10.12Fig. 10.13 |
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Answer» AB+CD=AD+BC Proof : AP=AS PB=BQ CQ=CR RD=DS (the length of tangent drawn from an external point to a circle are equal) AP+PB+RD+CR=AS+BQ+DS+CQ =>AB+CD=AD+BC |
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| 34. |
8. A quadrilateral ABCD is drawn to circumscribe a circle (see Fig. 10.12) PB 10.12). ProveAB +CD AD +BCX'Fig. 10.12Fig. 10.13 |
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| 35. |
4. I and m are two parallel lines intersected byFig. 7.18another pair of parallel lines p and q(see Fig. 7.19). Show that A ABCEA CDAFig, 7.19 |
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Answer» thanks for the answer . |
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| 36. |
BRIGHTPAGE NODATE:prove that 4ABC is an isosceless triangleif and only if altitude AD bisec BC |
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| 37. |
12+72÷8 |
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Answer» 21is right and correct answer 12+921is the correct answer 21 is correct answer 21 is correct answer |
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| 38. |
Fig. 7,17AD and BC are equal perpendiculars to a linesegmentAB (see Fig. 7.18). Show that CD bisectsAB. |
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| 39. |
Fig. 7.184. 1 and m are two parallel lines intersected byanother pair of parallel lines p and(see Fig. 7.19). Show that Δ ABC Δ CDA.qFig. 7.19 |
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| 40. |
Fig. 7.18I and m are two parallel lines intersected byanother pair of parallel lines p and q(see Fig. 7.19). Show that Δ ABC Δ CDA.PmFig. 7.19 |
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| 41. |
Fig. 8.2010, ABCD is a parallelogram and AP and CQ areperpendiculars from vertices A and C on diagonalBD (see Fig. 8.21). Show that(ii) AP COQFig, 8.21 |
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| 42. |
9.In the given figure, ABII CDII FE, find the angles x and y.MB75째65째E O45째OV,10025째C N |
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Answer» a) angle ABC=angle BCD=>75°=y +25°=>y = 75°-25°=50°=>angle EFC + angle FCD = 180°( adjacent angle)=>x+25°=180°=>x=155° hit like if you find it useful b) angle AMO=angle MOD(alternate angle)=>45°=100°-x=>x=100°-45°=>x=55°=y=x=55°(alternate angle) |
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| 43. |
the level of water rise in the tank in half an hour?18. The internal and external diameters of a hollow spherical vessels are 21 cm and 25.2 cmrespectively. The cost of painting 1 cm 2 of the surface is 10 paise. Find the total cost to paint thevessel all over.an the nuter and inner curved surface areas of hollow right circular |
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| 44. |
Wikkd कान नशे (28 oVफिद सपा रद 0 न 95 ~fi07 + XSl '€50 et PRRD eke e THOE |
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| 45. |
oag ©oAV ( -asv ( vad )Wz थे. | ——V-Nagv e1 'छ७ 9B OV9 38 LoBIE ad 9 वॉर७3४ 7 8989 BRI |
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Answer» BDC is a correct answer |
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| 46. |
O Creco 1Pt one asd हक छा 600१ 6 0,04/9, 0+4 है दीन त१0९ न 3 athe? O fig’?M'Qfiw | : } -N |
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Answer» Since n is a positive integer taking b =3 We can write n = 3q + r , where q is some integer n = 3q , n = 3q + 1 , n = 3q + 2 Case 1 = When n = 3q, n + 2 = 3q + 2 and n + 4 = 3q + 4 clearly only 3q is divisible by 3 Case 2 = When n = 3q + 1, n + 2 = 3q + 3 and n + 4 = 3q + 5 . Here also only n + 2 = 3q + 3 = 3(q + 1) is divisible by 3. Other two namely n and n + 4 are not divisible by 3. Case 3 = When n = 3q + 2, n + 2 = 3q + 4 and n + 4 = 3q + 6 and in this case, only n + 4 = 3(q + 2) is divisible by 3 Hence only one out of n, n + 2 and n + 4 is divisible by 3 for any positive integer n . thanks |
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| 47. |
Class19. In the given figure, AD divides ZBAC in theratio 1: 3 and AD -DB.Determine the value of x.A.108° |
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| 48. |
ABC is a triangle, in which B-2 ZC. D isa point on side BC such that AD bisecZBAC and AB-CD. Prove that ZBAC-7 |
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| 49. |
Simplify:(2) (3-1 – 5-1-1 |
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Answer» 15/2 is the right answer 15/2 is the perfect answer |
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| 50. |
In a triangle ABC, CB=60°, ZC=40°. If AD isbisector of ZBAC and AE IBC then ZEAD = ? |
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Answer» this question answer is 40 |
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