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O Creco 1Pt one asd हक छा 600१ 6 0,04/9, 0+4 है दीन त१0९ न 3 athe? O fig’?M'Qfiw | : } -N |
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Answer» Since n is a positive integer taking b =3 We can write n = 3q + r , where q is some integer n = 3q , n = 3q + 1 , n = 3q + 2 Case 1 = When n = 3q, n + 2 = 3q + 2 and n + 4 = 3q + 4 clearly only 3q is divisible by 3 Case 2 = When n = 3q + 1, n + 2 = 3q + 3 and n + 4 = 3q + 5 . Here also only n + 2 = 3q + 3 = 3(q + 1) is divisible by 3. Other two namely n and n + 4 are not divisible by 3. Case 3 = When n = 3q + 2, n + 2 = 3q + 4 and n + 4 = 3q + 6 and in this case, only n + 4 = 3(q + 2) is divisible by 3 Hence only one out of n, n + 2 and n + 4 is divisible by 3 for any positive integer n . thanks |
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